The beam is subjected to a distrubuted load. For the
cross section at x = 0.6 m, determine the average shear
stress (a) at the neutral axis; (b) at y = 0.02 m.
Free Body Diagram:
Summing the moments about point B to determine the r
Problem 14.34 The load F = 4650 lb. Draw the
shear force and bending moment diagrams for the beam.
Draw the FBD of the beam and determine the reactions at points A
(3 x)(400x2 )dx + By (5 ft)
MA = 0 = (4650 lb)(3 ft)+
Problem 15.4 The beam consists of material with
modulus of elasticity E = 14x106 psi and is subjected
to couples M = 150, 000 inlb at its ends. (a) What is
the resulting radius of curvature of the neutral axis? (b)
Determine the maximum tensile stress due
Determine the coordinates of the ceny
Solution: Let us solve this problem by using symmetry and by
breaking the composite shape into parts.
l1 = 70 mm
h1 = 70 mm
l2 = 70 mm
h2 = 70 mm
Problem 10.24 A prismatic bar with length L = 6 m
and a circular cross section with diameter D = 0.02 m
is subjected to 20-kN compressive forces at its ends.
The length and diameter of the deformed bar are measured and determined to be L = 5.940 m and D =
Problem 10.44 In Problem 10.43, the iron will safely Free Body Diagram:
support a tensile stress of 100 ksi and the aluminum will
safely support a compressive stress of 40 ksi. What is
the largest safe value of the gap b?
We see from the FBD tha
Problem 10.9 The angle of the system in Prob- Free Body Diagram:
lem 10.8 is 60 . The bars are made of a material that will
safely support a tensile normal stress of 8 ksi. Based on
this criterion, if you want to design the system so that it
Problem 9.8 The prismatic bar has a solid circular Free Body Diagram:
cross section with 30-mm radius. It is suspended from
one end and is loaded only by its own weight. The mass
density of the homogeneous material is 2800 kg/m3 . Determine the average no
Problem 6.4 Determine the axial forces in the members of the truss.
Solution: First, solve for the support reactions at B and C, and
then use the method of joints to solve for the forces in the members.