Quiz 2: Chapter 2
1
Marks: 1
For questions 1 to 6, use the following data :
Weights
4.5 - 6.9
7.0 - 9.4
9.5 - 11.9
12.0 - 14.4
14.5 - 16.9
Frequencies
2
7
5
4
2
The class boundaries of the bin (9.5 -
Quiz 6
Question 1
(1 point)
To find the 98% confidence interval for the population mean, for a
situation in which n is greater than 30, what Z value would you use?
Hint: do not use the Z table or your
Quiz10
Question 1
(1 point)
Assume the data below are independent samples from normally distributed populations with the same
variance.
A
B
C
D
19
11
24
14
21
14
19
16
26
21
21
14
24
13
26
13
18
16
20
Quiz 5
Question 1
(1 point)
Use the same data for questions 1, 2, 3, and 4:
The time that it takes to assemble a piece of machinery
is well modeled by the normal distribution with mean of
72.9 minutes
Quiz 10.
Question 1
(1 point)
The correlation coefficient, r, must have a value between 0 and 1.
Student response: Percent Correct
Student
Answer Choices
Value
Response Response
0.0%
a. true
100.0%
b.
Quiz 1
1) There are eleven quizzes in STAT 263, and all eleven quizzes will count toward the 10% quiz portion of the final
grade. (Hint: It would be useful for this and several other quiz questions to
MTHE/STAT455, STAT855
Fall 2014
Stochastic Processes
Assignment #1
Due Friday, Sep.26
Starred questions are for 855 students only.
1. Consider the simple random walk, cfw_Xn : n 0, starting at 0 (X0 =
MTHE/STAT455, STAT855
Fall 2014
Stochastic Processes
Assignment 4
Due Friday, Nov.28
1. Consider a continuous time Markov chain with state space S = cfw_1, 2 and generator
matrix
"
#
G=
,
where >
MTHE/STAT455, STAT855
Fall 2014
Stochastic Processes
Assignment #2
Due Tuesday, Oct.14
Starred questions are for 855 students only.
1. Let cfw_Xn : n 0 be a time-homogeneous Markov chain with state sp
Equations
Tuesday, June 14, 2016
6:04 PM
probability of event A
P(A) = 0.5
P(A B) probability of events
intersection
probability that of events A and
B
P(AB) =
0.5
P(A B) probability of events
probab
MTHE/STAT455, STAT855 Midterm Solutions
Fall, 2013
1. (15 marks)
(a) (7 marks) Dene M1 , M2 and M3 , where Mi is the expected number of steps to
get to the target vertex starting at a vertex that is i
STAT455/855
Fall 2010
Stochastic Processes
Final Exam, Solutions
1. (15 marks)
(a) (8 marks) Let Sm be the number of steps until the walk rst reaches state m
starting in state 0, and let Si,i+1 be the
STAT455/855
Fall 2007
Applied Stochastic Processes
Final Exam, Solutions
1. (15 marks)
(a) (11 marks) Let q = P (Xi > m). This is the same for all Xi , and is equal to
j1
p(1 p)
q=
m
(1 p)j =
= (1 p)
MTHE/STAT455, STAT855
Fall 2012
Stochastic Processes
Final Exam, Solutions
1. (15 marks)
(a) (10 marks) Condition on the rst pair to bond; each of the n 1 adjacent pairs
is equally likely to bond. Giv
STAT 455/855 Midterm Solutions
Fall, 2010
1. (15 marks)
(a) (4 marks) Each individual in the initial population is the root of a Galton-Watson
branching process starting at a single individual. If the
MTHE/STAT455, STAT855 Midterm Solutions
Fall, 2012
1. (15 marks)
(a) (5 marks) Following the hint let mk denote the expected additional number of
rolls required if the rst roll is k. Let X denote the
MTHE/STAT455, STAT855
Fall 2013
Stochastic Processes
Assignment #2, Solutions
Total Marks: for 455 and for 855.
1. From Sheet. (8 marks)
(a) (4 marks) The example should be such that knowing the infor
MTHE/STAT455, STAT855
Fall 2013
Stochastic Processes
Assignment #3, Solutions
Total Marks: 33 for 455 and 43 for 855.
1. From Sheet. (6 marks)
(a) (3 marks) If we sum gij (n) over n we get the probabi
MTHE/STAT455, STAT855
Fall 2013
Stochastic Processes
Assignment #4, Solutions
Total Marks: 38 for both 455 and 855.
1. From Sheet. (10 marks)
(a) (4 marks) The problem is to compute the probability th
MTHE/STAT455, STAT855
Fall 2013
Stochastic Processes
Final Exam, Solutions
1. (15 marks)
(a) (6 marks) If fr denotes the probability mass function of the family size in the
modied branching process wi
MTHE/STAT455, STAT855
Fall 2013
Stochastic Processes
Assignment #5, Solutions
Total Marks: 20 for both 455 and 855.
1. From Sheet. (10 marks)
(a) (3 marks) The given expression for Gn is clearly corre
MTHE/STAT455, STAT855
Fall 2013
Stochastic Processes
Assignment #1, Solutions
Total Marks: 37 for 455 and 45 for 855.
1. From Sheet. (10 marks)
(a) (4 marks) First note that if n is even then Xn must
Student Number
Queens University
Department of Mathematics and Statistics
STAT 353
Midterm Examination February 12, 2009
Total points = 30. Duration = 58 minutes.
This is a closed book exam.
One 8.
Student Number
Queens University
Department of Mathematics and Statistics
STAT 353
Midterm Examination February 18, 2010
Total points = 30. Duration = 58 minutes.
This is a closed book exam.
One 8.
STAT 353 Solutions: Assignment 5
Winter, 2014 (Total 30 marks)
Problem 1 (From Sheet.) (9 marks) Expressing Xi and Xj as in the hint, for i = j we have
E[Xi Xj ] = E[(Xi1 + . . . + Xin )(Xj1 + . . . +
Student Number
Queens University
Department of Mathematics and Statistics
STAT 353
Final Examination April 24, 2010
Instructor: G. Takahara
Proctors are unable to respond to queries about the interpr
Student Number
Queens University
Department of Mathematics and Statistics
STAT 353
Final Examination April 9, 2009
Instructor: G. Takahara
Proctors are unable to respond to queries about the interpre
Student Number
Queens University
Department of Mathematics and Statistics
STAT 353
Midterm Examination February 18, 2011
Total points = 30. Duration = 58 minutes.
This is a closed book exam.
One 8.
Student Number
Queens University
Department of Mathematics and Statistics
STAT 353
Final Examination April 21, 2011
Instructor: G. Takahara
Proctors are unable to respond to queries about the interpr
STAT 353 Solutions: Assignment 9
Winter, 2014 (Total 30 marks)
Problem 1 (From Sheet.) (5 marks) Let Fn be the distribution function of Xn and let
F (x) = 0 for x < c and F (x) = 1 for x c (i.e., F is