Phys 204  Final exam Formulae Sheet
1 u = 1.6605387 x 1027 kg
1 u = 931.502 MeV/c2
1 eV = 1.602 1019 J
mp = 1.672 1027 kg
= 1.0073 u = 938.280 MeV/c2
mn = 1.674 1027 kg
= 1.0087 u = 939.57 MeV/c2
me = 9.11 1031 kg
= 5.486104 u = 0.511 MeV/c2
m = 6.64465
COURSE OUTLINE
Physics 204/1 51, 2016
(Instructor: Dr. R.C. Sharma)
TEXT: 1. Physics for Scientists and Engineers by Serway Jewett Brooks/Coles
2. Notes on Mechanics P204 by Dr. R.C. Sharma. (Will be Available on
.COURSE CONTENTS:
1.
2.
3.
4.
5.
6.
7.
8.
Phys 204 (Mechanics)
Final exam. Time: 3h:00. April 16, 2007
Work you answers from basic principles
Answer all questions on booklet (including multiple choice questions)
Budget your time
The exam has 5 sheets of paper, including the formulae sheet.
Return
Chapter 4
Motion in Two Dimensions
Motion in Two Dimensions
Using + or signs is not always sufficient to fully
describe motion in more than one dimension
Vectors can be used to more fully describe motion
Will look at vector nature of quantities in more de
ASSIGNMENT 1
Physics 204
(Do any 10 problems)
Q1 A vector has xcomponent of 25.0 units and a ycomponent of 40.0 units. Find the
magnitude and direction of this vector.
Ans: (47.2 units, 122)
Q2
Q3
A displacement vector lying in the xy plane has a magn
Chapter 13
Universal Gravitation
Newtons Law of Universal
Gravitation
Every particle in the Universe attracts every other
particle with a force that is directly proportional to
the product of their masses and inversely
proportional to the distance between
Chapter 12
Static Equilibrium
and
Elasticity
Static Equilibrium
Equilibrium
implies the object is at rest
(static) or its center of mass moves with a
constant velocity (dynamic)
Static equilibrium is a common situation in
engineering
Principles involve
Chapter 11
Angular Momentum
The Vector Product
There
are instances where the product of two
vectors is another vector
Earlier we saw where the product of two vectors
was a scalar
This was called the dot product
The
vector product of two vectors is also
Phys 204 (Mechanics)
Formulaesheet
Lawofcosines
Law of sines
Quadratics:
Trigonometric Identities:
1
1 u = 1.6605387 x 1027 kg
1 u = 931.502 MeV/c2
1 eV = 1.602 1019 J
mp = 1.672 1027 kg
= 1.0073 u = 938.280 MeV/c2
mn = 1.674 1027 kg
= 1.0087 u = 939.57
Phys 204 (Mechanics)
Assignment 4 chapter 4 Motion in 2 dimensions
Problem 4.1: A motorist drives south at 26.0 m/s for 3.00 min, then turns west and travels
at 25.0 m/s for 2.00 min, and finally travels northwest at 30.0 m/s for 1.00 min. For this
6.00 m
Circular Motion
Uniform motion in a circle: uniform means the particle
always has the same speed.
defines e
43 = sir by definition
Does sir = s'lr'? Yes.
is a good denition.
4: is in radians 360: 6 = CIR
Call this angle "2 1c radians"
' 275=CIR
arc ca
A ball is thrown.
At time t, it is at x, y.
x, y are functions of t.
X(t).. V(t) (53:1me t) Path: y(x) Ran e of a Pro' ectile
a @
R
z=1J;,t
3 1.:
d wwat  "15 "if
To find R, we want to know it when y = 0 (say,
when t = tR)
50: 0 = guts'it;
any; 3? Maxim
Pe=mgh
Ke=(1/2)mv^2
Pe+Ke=Total energy
Need to split into 2 parts: Energy at top and energy at
bottom
Energy at top:
Ke=0 Pe=mgh
therefore total energy:
Ke+Pe=total at top
0+mgh=mgh
Energy at bottom
Ke= 1/2mv^2 Pe=0
ke+pe=total energy at bottom
1/2mv^2+0=
How to lot x vs t iven a lot of x vs :50 t. The Simple Pendullim
& SHM
/\;
Restoring force due. to gravity
is
mgsin 9
F =  m sin
9 9 9
For small angles, sin 9'1: 5
0.84 ' 1.0
0.48 0.5
0.0998 0.1 F3 = mgsin6 e mg f'DTEDEJTIEIII
With 3 = sIL radians
Hallett #714
Find: magnitude and direction of the cat's velocity at the
instant it touchesthe ground.
origin
Solution Let the origin of the axes be on the ground, with
TL) and '1? . Then
x0=0; y0 =+3.00m
x = 4.00 m; y = 0
Vx = We unknOwn
Vyo =0 and Vy
A ball is thrown.
At time t, it is at x, y.
x, y are functions of t.
X(t), W) (561!9 t) Ran e of a Pro' ectile

7 '= 1);.1:
3 t.
r we; watt 24*
To find R, we want to know x when y = 0 (say,
when t = g)
50, 0 = at'3' Jit: Maximum height of a projectile
c
Angular speed, frequency, period, angular frequency
angular speed
frequency _\.
Angular velocity vector u
A
DEF: 1,.) has magnitude (.0
The direction is given by the jartop
rule.
Q9 CLOSE THE JAR
THE MIDPOINT
GOES INTO
THE BOARD
SEE THE TAIL OF TH
Vectors
C H A P T E R
3
3.1 Coordinate Systems
3.2 Vector and Scalar Quantities
3.3 Some Properties of Vectors
3.4 Components of a Vector and
Unit Vectors
In our study of physics, we often need to work with physical quantities that have both
numerical and
C H A P T E R
6
Circular Motion and
Other Applications
of Newtons Laws
6.1 Extending the Particle in
Uniform Circular Motion
Model
6.2 Nonuniform Circular Motion
6.3 Motion in Accelerated
Frames
6.4 Motion in the Presence of
Resistive Forces
Kyle Busch, d
The Laws of Motion
C H A P T E R
5
5.1 The Concept of Force
5.2 Newtons First Law and
Inertial Frames
5.3 Mass
5.4 Newtons Second Law
5.5 The Gravitational Force and
Weight
5.6 Newtons Third Law
5.7 Analysis Models Using
Newtons Second Law
5.8 Forces of F
Serway
Reew Problem
A block of mass m rests on top of a frictionless inclined plane
of mass 377: and height It as shown below. The block slides
down the plane and moves along a horizontal surface until it
stops. The coefcient of kinetic fricdon between th
Phys 204 (Mechanics)
Formulaesheetmidterm
Lawofcosines
Law of sines
Quadratics:
Trigonometric Identities:
1
1 u = 1.6605387 x 1027 kg
1 u = 931.502 MeV/c2
1 eV = 1.602 1019 J
mp = 1.672 1027 kg
= 1.0073 u = 938.280 MeV/c2
mn = 1.674 1027 kg
= 1.0087 u =
Phys 204 (Mechanics)
Assignment 5 chapter 5 Newtons laws of motion
Problem 5.5: The gravitational force exerted on a baseball is 2.22 N down. A pitcher
throws the ball horizontally with velocity 12.0 m/s by uniformly accelerating it along a
straight horiz