LECTURE 10: GEOGRAPHY, CLIMATE, AND NATURAL RESOURCES
A. INTRODUCTION
A. INTRODUCTION
B. GEOGRAPHY
C. DIAMONDS THEORY
D. CLIMATE
E. NATURAL RESOURCES
F. RELATED LITERATURE
Are the determinants of income differences among countries we
have examined so far
CHAPTER 12
Exercises
E12.1 (a) vGS = 1 V and vDS = 5 V: Because we have vGS < Vto, the FET is in cutoff. (b) vGS = 3 V and vDS = 0.5 V: Because vGS > Vto and vGD = vGS vDS = 2.5 > Vto, the FET is in the triode region. (c) vGS = 3 V and vDS = 6 V: Because
CHAPTER 11
Exercises
E11.1 (a) A noninverting amplifier has positive gain. Thus v o (t ) = Avv i (t ) = 50v i (t ) = 5.0 sin(2000t ) (b) An inverting amplifier has negative gain. Thus v o (t ) = Avv i (t ) = 50v i (t ) = 5.0 sin(2000t ) E11.2
A= v
RL Vo 7
CHAPTER 10
Exercises
E10.1 Solving Equation 10.1 for the saturation current and substituting values, we have
Is =
iD exp(vD / nVT ) 1
10 4 = exp(0.600 / 0.026) 1 = 9.502 10 15 A Then for vD = 0.650 V, we have
= 0.6841 mA
iD = I s exp(vD / nVT ) 1 = 9.502
CHAPTER 9
Solutions for Exercises
E9.1 The equivalent circuit for the sensor and the input resistance of the amplifier is shown in Figure 9.2 in the book. Thus the input voltage is
v in = v sensor
Rsensor + Rin
Rin
We want the input voltage with an intern
CHAPTER 8
Exercises
E8.1 The number of bits in the memory addresses is the same as the address bus width, which is 20. Thus the number of unique addresses is 220 = 1,048,576 = 1024 1024 = 1024K. (8 bits/byte) (64 Kbytes) = 8 64 1024 = 524,288 bits Startin
CHAPTER 6
Exercises
E6.1 (a) The frequency of v in (t ) = 2 cos(2 2000t ) is 2000 Hz. For this frequency H (f ) = 260 o. Thus, Vout = H (f )Vin = 260 o 20 o = 460 o
and we have v out (t ) = 4 cos(2 2000t + 60 o ). (b) The frequency of v in (t ) = cos(2 30
CHAPTER 5
Exercises
E5.1 (a) We are given v (t ) = 150 cos(200t 30 o ) . The angular frequency is the coefficient of t so we have = 200 radian/s . Then f = / 2 = 100 Hz T = 1 / f = 10 ms Vrms = Vm / 2 = 150 / 2 = 106.1 V Furthermore, v(t) attains a positi
CHAPTER 4
Exercises
E4.1 The voltage across the circuit is given by Equation 4.8: v C (t ) = Vi exp( t / RC )
in which Vi is the initial voltage. At the time t1% for which the voltage reaches 1% of the initial value, we have 0.01 = exp( t1% / RC ) Taking
CHAPTER 3
Exercises
E3.1
v (t ) = q (t ) / C = 10 6 sin(10 5t ) /(2 10 6 ) = 0.5 sin(10 5t ) V dv i (t ) = C = (2 10 6 )(0.5 10 5 ) cos(10 5t ) = 0.1 cos(10 5t ) A dt
Because the capacitor voltage is zero at t = 0, the charge on the capacitor is zero at t
CHAPTER 2
Exercises
E2.1 (a) R2, R3, and R4 are in parallel. Furthermore R1 is in series with the combination of the other resistors. Thus we have: 1 Req = R1 + = 3 1 / R2 + 1 / R3 + 1 / R4
(b) R3 and R4 are in parallel. Furthermore, R2 is in series with
CHAPTER 1
Exercises
E1.1 E1.2 E1.3 Charge = Current Time = (2 A) (10 s) = 20 C
i (t ) =
dq (t ) d = (0.01sin(200t) = 0.01 200cos(200t ) = 2cos(200t ) A dt dt
Because i2 has a positive value, positive charge moves in the same direction as the reference. Th
CHAPTER 13
Exercises
E13.1 given by the Shockley equation: 1 v For operation with iE > I ES , we have exp BE > 1 , and we can write V T v iE I ES exp BE V T Solving for v BE , we have The emitter current is v iE = I ES exp BE V T
i v BE VT ln E I ES
v BC
CHAPTER 14
Exercises
E14.1
(a) iA =
vA RA
iB =
vB RB
iF = iA + iB =
vA RA +
v A vB + RA RB
v o = RF iF = RF
(b) For the vA source, RinA (c) Similarly RinB = RB .
vB RB v = A = RA . iA
(d) In part (a) we found that the output voltage is independent of th
CHAPTER 15
Exercises
E15.1 If one grasps the wire with the right hand and with the thumb pointing north, the fingers point west under the wire and curl around to point east above the wire. If one places the fingers of the right hand on the periphery of th
LECTURE 1: THE FACTS TO BE EXPLAINED & A FRAMEWORK FOR ANALYSIS
A. SOME BASIC FACTS
A. SOME BASIC FACTS
B. DIFFERENCES IN THE
LEVEL OF INCOME
C. DIFFERENCES IN THE
RATE OF INCOME
GROWTH
Exercise: Describe the
possessions of these families.
D. SOURCES OF
E
LECTURE 9: INCOME INEQUALITY
A. INTRODUCTION
B. MEASURING INCOME
INEQUALITY
C. THE KUZNETS
HYPOTHESIS
A. INTRODUCTION
How GDP is Divided among Households?
D. SOURCES OF INCOME
INEQUALITY
E. EFFECT OF INCOME
INEQUALITY ON GROWTH
F. ECONOMIC MOBILITY
G. REL
LECTURE 7: GROWTH IN THE OPEN ECONOMY
A. INTRODUCTION
B. AUTARKY VERSUS
OPENNESS
C. THE EFFECT OF
OPENNESS ON
ECONOMIC GROWTH
D. OPENNESS AND
FACTOR
ACCUMULATION
E. OPENNESS AND
PRODUCTIVITY
F. OPPOSITION TO
OPENNESS
A. INTRODUCTION
We have so far assume
LECTURE 8: GOVERNMENT
A. INTRODUCTION
B. THE CASE FOR
GOVERNMENT
INTERVENTION
C. THE CASE AGAINST
GOVERNMENT
INTERVENTION
D. HOW GOVERNMENT
AFFECTS GROWTH
(EMPIRICAL EVIDENCE)
A. INTRODUCTION
How does the government affect economic growth?
An example:
No
LECTURE 5: MEASURING PRODUCTIVITY
A. WHAT IS
PRODUCTIVITY?
B. PRODUCTIVITY IN
THE PRODUCTION
FUNCTION
C. PRODUCTIVITY
DIFFERENCES AMONG
COUNTRIES
D. PROBLEMS IN
MEASURING
PRODUCTIVITY
E. PRODUCTIVITY
GROWTH DIFFERENCES
AMONG COUNTRIES
F. RELATED
LITERATUR
LECTURE 6: THE ROLE OF TECHNOLOGY IN GROWTH
A. INTRODUCTION
B. THE NATURE OF
TECHNOLOGICAL
PROGRESS
C. PATENT PROTECTION
A. INTRODUCTION
Technology Has Profoundly Changed the Way We Live
D. TECHNOLOGY
CREATION AND
GROWTH ONE
COUNTRY MODEL
E. TECHNOLOGY
CR
LECTURE 3: POPULATION AND ECONOMIC GROWTH
A. SOME FACTS
ABOUT POPULATION
B. POPULATION AND
OUTPUT OVER THE
LONG RUN
C. BREAKDOWN OF THE
MALTHUSIAN MODEL
A. SOME FACTS ABOUT POPULATION
The Most Populated Countries of the World (2012)
D. POPULATION
GROWTH I
LECTURE 2: PHYSICAL CAPITAL
A. CAPITAL AND
OUTPUT
B. THE NATURE OF
CAPITAL
C. CAPITALS ROLE IN
PRODUCTION
D. THE SOLOW
GROWTH MODEL
E. THE STEADY STATE
F. A THEORY OF
INCOME DIFFERENCES
G. A THEORY OF
RELATIVE GROWTH
RATES
A. CAPITAL AND OUTPUT
Tools tha
LECTURE 10: WHAT WE HAVE LEARNED AND WHERE WE ARE HEADED
A. WHAT WE HAVE
LEARNED
A. WHAT WE HAVE LEARNED
B. WHAT THE FUTURE
HOLDS
C. A FINAL THOUGHT
One of the most striking facts about the world today is the
astounding variation in income per capita amo
LECTURE 4: HUMAN CAPITAL
A. WHAT IS HUMAN
CAPITAL?
A. WHAT IS HUMAN CAPITAL?
B. THE NATURE OF
HUMAN CAPITAL
C. HUMAN CAPITAL IN
THE FORM OF HEALTH
It is the quality of workers
Health
D. HUMAN CAPITAL IN
THE FORM OF
EDUCATION
Education
Human
Capital
E. A
CHAPTER 17
Exercises
E17.1 From Equation 17.5, we have
Bgap = Kia (t ) cos( ) + Kib (t ) cos( 120 ) + Kic (t ) cos( 240 )
Using the expressions given in the Exercise statement for the currents, we have
Bgap = KI m cos(t ) cos( ) + KI m cos(t 240 ) cos( 12
CHAPTER 16
Exercises
E16.1 The input power to the dc motor is Pin = Vsource I source = Pout + Ploss Substituting values and solving for the source current we have 220I source = 50 746 + 3350 I source = 184.8 A Also we have
50 746 Pout 100% = = 91.76% 50 7
Operational Amplifier Circuits
Hambley, Chapter 14
1
Objectives
1. List the characteristics of ideal op amps. 2. Identify negative feedback in op-amp circuits. 3. Analyze ideal op-amp circuits that have negative feedback using the summing-point constraint
Logic Circuits
Hambley, Chapter 7
1
Objectives
1. 2. 3. 4. 5. 6. Appreciate the advantages of digital technology compared to analog technology. Understand the terminology of digital circuits. Basic combination circuits blocks - logic gates Interconnect lo