MA244 Analysis III
Assignment 3.
From this sheet, Questions 6, 8, and 9, are to be submitted by the deadline
of 2pm on Thursday 8th November 2012. In addition a sheet containing attempts (successful and unsuccessful) for all A questions will receive the
e
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this extract and the work from which it was taken. This Digital Copy has been
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Course m
NAME
CLASS
DATE
Applications of the Derivative
You will be assessed on the following criteria:
Criterion B: Investigating patterns in mathematics (max
8)
Criterion C: Communicating in mathematics (max 8)
Achievement
Level
0
12
34
56
78
12
34
56
Level Achi
An Application of Mixed Nash Equilibrium
1. Introduction
There are many game problems in life. One of them is a classic example of a Battle of sexes (a game
between a couple), which not only exists in the game between husband and wife, can also be applied
Assessment 2 for MA590
March 1, 2017
1
Radioactive phosphorus is used as a tracer in the lab. Let the amount of phosphorus at time t
be m(t). The phosphorus takes 14 days for half of it to decay. After an experiment with 6 grams
of phosphorus, researcher
lengthn function: compute length in bytes(characters) of text excluding trailing blanks.
lengthc function: compute length in bytes(characters) of text including trailing blanks.
countw function: count the number of words or sentences, for sentences end in
4.
(a)
To summarize the distribution of total income for married men and women, we should make sure
whether the marital status is married. So, we first summarize the marital status.
We can see all the people are married, so we could summarize the distribu
1.
a.
a x
We can set a exponential function: y=
so that
2=at and let the half-life as one unit.
Hence, we can obtain the parameter is 0.693147. thus, we can derive that after 1.584963 units can meet
the requirement to exactly remain one third of C14 whic
2.
function h=hilb(n)
h=zeros(n,n);
for i=1:n
for j=1:n
h(i,j)=1/(i+j-1);
end
end
end
function x=backslash(n)
B=ones(n,1);
h=zeros(n,n);
for i=1:n
for j=1:n
h(i,j)=1/(i+j-1);
end
end
x=h\B;
end
X=backslash(n)0=2
X =
-2.0000
6.0000
> X=backslash(n) 0=5
X =
(a) Because of a3 dominates a1, so column a1 can be removed from our consideration. (every entry
in column a3 is larger than the corresponding entry in the a1)
(b) For play B, we would subtract each number in the column from the largest number in the row.
Chapter 3 Cohomology
3.0 Cohomology Introduction
Let X be a 1-dimensional -complex, so X is an oriented graph (or pseudo-graph if edges that
begin and end at the same vertex are allowed). If v0 and v1 are two vertices in X and e is an
oriented edge from v
MA244 - Analysis III
Anthony Manning
October - December 2007
Contents
1 Analysis I & II, Uniform Continuity and Continuity by Open
Sets
2
2 The Integral for Step Functions
12
3 The Integral for Regulated Functions
17
4 Indenite Integral and the Fundamenta
Copyright Notice
Staff and students of this University are reminded that copyright subsists in
this extract and the work from which it was taken. This Digital Copy has been
made under the terms of a CLA licence which allows you to:
access a copy
Course m
Complex Number and
its Application in Kinematics
Extension of Number System
We know that there is no solution in real number when we have a
equation as
2 = 1
So we tend to introduce a new number i to let it satisfy
2 = 1
We call i as a imaginary unit.
i