Chapter 10 - One-Sample Tests of Hypothesis
Chapter 10
One-Sample Tests of Hypothesis
1.
a.
b
c.
d.
e.
2.
a.
b.
c.
Two-tailed, because the alternate hypothesis does not indicate a direction.
Reject Ho when z does not fall in the region from 1.96 and 1.96
Chapter 07 - Continuous Probability Distributions
Chapter 7
Continuous Probability Distributions
1.
1.1547 found by
d.
e.
f.
[1/(10 6)](10 6) = 1
0.75, found by [1/(10 6)](10 7)
0.5, found by [1/(10 6)](9 7) (LO 2)
a.
b.
a=2 b=5
3.5, found by (2 + 5)/2
c.
Chapter 04 - Describing Data: Displaying and Exploring Data
Chapter 4
Describing Data: Displaying and Exploring Data
1.
A histogram describes a frequency distribution using a series of adjacent rectangles. On the
other hand, a dot plot displays a dot for
Chapter 02 - Describing Data: Frequency Tables, Frequency Distributions, and Graphic Presentation
Chapter 2
Describing Data: Frequency Tables, Frequency Distributions, and
Graphic Presentation
1.
Pepsi-Cola has a 25% market share, found by 90/360. (LO 3)
Chapter 09 - Estimation and Confidence Intervals
Chapter 9
Estimation and Confidence Intervals
1.
51.314 and 58.686, found by 55 2.58(10 / 49) (LO 3)
2.
38.911 and 41.089, found by 40 1.96(5/ 81) (LO 3)
3.
a.
b.
c.
4.
1.44 (LO 3)
5.
a.
b.
$20. It is our b
Chapter 08 - Sampling Methods and the Central Limit Theorem
Chapter 8
Sampling Methods and the Central Limit Theorem
1.
a.
b.
c.
d.
303 Louisiana, 5155 S. Main, 3501 Monroe, 2652 W. Central
Answers will vary
630 Dixie Hwy, 835 S. McCord Rd., 4624 Woodvill
Chapter 12 - Analysis of Variance
Chapter 12
Analysis of Variance
1.
9.01 from Appendix B.4
2.
9.78
3.
Reject Ho if F > 10.5, where df in numerator are 7 and 5 in the denominator.
s 2 (10) 2
F = 12 =
= 2.04
F = 2.04, found by:
s2
(7) 2
Do not reject Ho. T
Chapter 11 - Two-Sample Tests of Hypothesis
Chapter 11
Two-Sample Tests of Hypothesis
1.
a.
b.
d.
e.
Two-tailed test
Reject Ho if z < 2.05 or z > 2.05
102 99
z=
2.59, found by
52 6 2
+
40 50
Reject Ho
p = 0.0096, found by 2(0.5000 0.4952) (LO 1)
a.
b.
One
Chapter 15 - Index Numbers
Chapter 15
Index Numbers
1.
114.6, found by ($19,989/$17,446)(100)
123.1, found by ($21,468/$17,446)(100)
124.3, found by ($21,685/$17,446)(100)
91.3, found by ($15,922/$17,446)(100)
105.3, found by ($18,375/$17,446)(100)
314.2,
Chapter 14 - Multiple Regressions Analysis
Chapter 14
Multiple Regressions Analysis
1.
a.
b.
c.
Multiple regression equation
the Y-intercept
$374,748 found by Y = 64,100 + 0.394(796,000) + 9.6(6940) 11,600(6.0) (LO 1)
2.
a.
b.
c.
d.
e.
Multiple regression
2010 Assignment Answers SG 15e
Chapter 1
What is statistics?
Part I
Part II
Part III
1. Quantitative
2. Qualitative
3. Quantitative
4. Qualitative
5. Quantitative
Part IV
6. Discrete
7. Discrete
8. Continuous
9. Continuous
10. Discrete
11. Interval
12. No
Chapter 13 - Correlation and Linear Regression
1.
( X X ) (Y Y ) ( X X )
Chapter 13
Correlation and Linear Regression
(Y Y )
( X X ) (Y Y )
X
Y
4
5
3
6
1
0
4
6
5
7
-1.6
-0.6
-2.6
0.4
-1.8
0.2
-0.8
1.2
2.56
0.36
6.76
0.16
3.24
0.04
0.64
1.44
2.88
-0.12
2.0
Chapter 05 - A Survey of Probability Concepts
Chapter 5
A Survey of Probability Concepts
1.
2.
Outcome
1
2
3
4
1
A
A
F
F
2
A
F
A
F
(LO 1)
Outcome
1
2
3
4
5
6
7
8
9
1
A
A
A
R
R
R
S
S
S
2
A
R
S
A
R
S
A
R
S
(LO 1)
3.
a.
b.
0.176 found by 6/34
Empirical (LO 2
A Review of Chapters 5 7
Answers to Section Two Exercises
A Review of Chapters 5 7
1.
a.
b.
c.
0.035 from Appendix B.9 where =0.8 and n = 15
0.018, found by 0.001 + 0.003 + 0.014
0.648, found by 0.250 + 0.231 + 0.132 + 0.035
2.
a.
b.
c.
0.1353, found from
A Review of Chapters 1 4
Part III
Answers to section one exercises
A Review of Chapters 1 4
1.
a.
b.
c.
Mean is 147.9. Median is 148.5. Standard deviation is 69.24
The first quartile is 106. The third quartile is 186.25.
Bo xpl ot of C1
0
50
100
150
C1
20
Chapter 18 - Nonparametric Methods: Analysis of Ranked Data
Chapter 18
Nonparametric Methods: Analysis of Ranked Data
1.
a.
b.
If the number of pluses (successes) in the sample is 9 or more, reject Ho.
Reject Ho because the cumulative probability associat
A Review of Chapters 13 and 14
Answers to Section Five Exercises
A Review of Chapters 13 and 14
a.
b.
c.
d.
e.
2.
Net profit
Y = a + b1 X 1 + b2 X 2 + b3 X 3 + b4 X 4
$163,200
About 86% of the variation in net profit is explained by the four variables.
Ab
A Review of Chapters 10 12
Answers to Section Four Exercises
A Review of Chapters 10 12
1.
Ho: 36
H1: < 36
Reject Ho if t < 1.683
35.5 36.0
z=
= 3.60 Reject Ho. The mean height is less than 36 inches.
0.9 / 42
2.
Ho: 0.08 H1: >0.08
Alpha = 0.01
p
z=
Reje
Chapter 16 - Time Series and Forecasting
Chapter 16
Time Series and Forecasting
1.
The weighted moving averages are:
31584.8
33088.9
34205.4
34899.8
35155.0
34887.1
The trend increases the first few years and then tops out around 35,000 subscribers. (LO 2
A Review of Chapters 17 and 18
Answers to Section Seven Exercises
A Review of Chapters 17 and 18
1.
H0: Median 60
H1: Median > 60
The sample has 16 values above 60. From a binomial table ( n = 20, p = 0.5) the probability of 16
or more incidences is 0.006
A Review of Chapters 15 and 16
Answers to Section Six Exercises
A Review of Chapters 15 and 16
1.
a.
b.
c.
106.1, found by (157/148)100.
100.0, found by (157/157)100.
147.3 + 4.9t and 186.5, found by 147.3 + 4.9(8).
2.
a.
104.4, found by 100(4.8/4.6+4.7/4
Chapter 01 - What is Statistics?
Chapter 1
What is Statistics?
1.
a.
c.
e.
Interval
Interval
Ordinal
b.
d.
f.
Ratio
Nominal
Ratio (LO6)
2.
a.
c.
Ratio
Ratio
b.
d.
Nominal
Ratio (LO6)
3.
Answer will vary. (LO6)
4.
a.
c.
b.
d.
Population
Sample (LO3)
5.
Qua
Chapter 03 - Describing Data: Numerical Measures
Chapter 3
Describing Data: Numerical Measures
1.
= 5.4 found by 27/5 (LO 2)
2.
= 5.5 found by 33/6 (LO 2)
3.
a.
b.
Mean = 7.0, found by 28/4
(5 7) + (9 7) + (4 7) + (10 7) = 0 (LO 2)
4.
a.
b.
4.2 found by
Chapter 19 - Statistical Process Control and Quality Management
Chapter 19
Statistical Process Control and Quality Management
1.
40
0.5
0.4
30
0.3
20
0.2
10
0.1
0
Problem not corrected
Unfriendly
Invoice error
Price high
Long wait
0
Count
38
23
12
10
8
Pe