Top 10 badminton players in the world
World badminton is mostly dominated by Asian players, especially those from China. However some
European countries, most notably Denmark is still a badminton powerhouse and has its players in top 10 rankings.
The Top
CALCULATION OF E FIELD
E FIELD DUE TO A NUMBER OF POINT CHARGES
The E field at a point can be computed from Coulomb's law if the
magnitudes and positions of all charges contributing to the field are
known.
To find magnitude of the E field at a point P, at
THE ELECTRIC FIELD & GAUSSS LAW
Electric Field
E field is said to exist all around a point charge and is
represented in the form of curved lines with arrowhead
pointing in a particular direction.
Direction of E field at any point in the field is given by
THE ELECTRIC FIELD & GAUSSS LAW
Electric Field
E field is said to exist all around a point charge and is
represented in the form of curved lines with arrowhead
pointing in a particular direction.
Direction of E field at any point in the field is given by
Capacitance
Capacitors, Dielectrics
Capacitors
Introduction
Two conductors separated by an insulator form a capacitor.
Conductors are parallel and hold charges equal in magnitude,
opposite in sign. There is no net charge on the capacitor.
Applications
Tu
THE ELECTRIC FIELD & THE GAUSSS LAW
Electric Field Lines
E field is said to exist all around a point charge and is
represented in the form of curved lines with arrowhead
pointing in a particular direction.
Direction of E field at any point in the field
Example 2
An particle is a nucleus of doubly ionized helium. It has
a mass m of 6.68x1027 kg and a charge q of +2e or
3.2x1019C. Compare the force of electrostatic repulsion
between two
particles with force of gravitational
attraction between them.
G
Electric Potential & Potential Energy
E field is force per unit charge
Like other forces, it is capable of doing work
Work, Energy & Force are closely related terms
Force.
The agent which can do work, cause motion or
stop motion. Units are Newton (Kg m s
Example 1
Point charges q1 and q2 of + 12 x 109 C and 12 x 109 C,
respectively, are placed 0.1 m apart, as in fig255. compute
the electric fields due to these charges at points a, b & c.
o
Ec
10 cm
Eb
b
4 cm
+
q
1
10 cm
a
6 cm
Ea
4 cm

q2
Example 2
Badminton
Court
The Badminton Court shall be a rectangle laid out with lines of 40mm wide, preferably in white
or yellow color. The Badminton Court Dimensions are of 13.4m in length and 6.1m in width.
The post shall be 1.55m in height from the surface of
FIELD OF LINE CHARGE
Gaussian Surface
E=E
E=0
(E)(2r)
o
1
E
2o r
FIELD OF INFINITE SHEET OF CHARGE
A
2EA
o
E
2 o
FIELD OF INFINITE PLANE CHARGED
CONDUCTING PLATE
E1
E2
E1
E2
E1
b
a
E
A
c
E2
E E1 E2
2 o 2 o o
A
EA
o
E
o
FIELD BETWEEN OPPOSITELY CHAR
The Hall Effect
The forces on moving charges in a conductor, placed in a magnetic field are demonstrated by
Hall Effect. The conductor is in the form of a strip.
If excess charge carriers are electrons as in metals, the ve charge accumulates at upper edge
Equipotential Surfaces
Equipotential Surfaces
Potential Gradient
b
b
Line Integral Vab . cos d E d
E
a
a
b
Vab
dV
dV
b
a
a
Millikan OilDrop Experiment
q 18
VAB
3
3
vT
2g
Cathode Ray Oscilloscope
Electrostatic Deflection of Cathode Rays
P
l
P/
Magnetic Field
Magnetic field on a charged particle +q moving with velocity V in a direction
to a
magnetic field B in terms of magnitude is given by
F qV B qVBsin q(VxB)
F
B
NA 1m 1
qV
F
Moving
charge q
B dA B.dA B A BAcos
B
qVBsin
+
V sin
Weber B.
Magnet
Introduction to Magnetic Field
Poles North & South
Analogy E Field with M Field
Charges set up E Field
E Field exerts force on a charge
Similarities
A moving charge or current creates M Field in the space surrounding
it
The M Field exerts a fo
1
QUIZ TE43
NO
Name
Class.
Q1.
Time
30 mins
How many electrons would be required to make the collated charge of
0.5 Coulomb?
Q2.
Find the force on a proton in an E field = 4x10 4 NC1, directed along x axis
Q3.
Find the electrical force between two par
E Field Lines and Electric Flux
E Field lines were defined as the imaginary curved lines emanating
from a positive charge and represent the extent of varying E field due
to that charge or due to distributed charge. Direction of.
If we place an element of
EXAMPLE 1.3
(a) Prove if an ntype semiconductor the minority carrier concentration becomes 10%
of majority carrier concentration at critical temperature, the intrinsic carrier
concentration ni, will become equal to 0.35 ND.
(b) Find this critical tempera
EXAMPLE 1.3:
(a) Prove if in an Ntype semiconductor the minority carrier concentration becomes
10% of majority carrier concentration at critical temperature the intrinsic carrier
concentration, ni, will become equal to 0.35 ND.
(b) Find this critical tem
EXAMPLE 1.4
Certain bar of Ntype silicon has:
Length = L = 5 cm;
Square crosssectional area = 25 mm2;
n = 1350 cm2 per voltsec;
p = 480 cm2 per voltsec;
I = current through the bar is 10 mA and
V = Voltage applied across the bar = 2 Volts
(a) Find the
Physics of Semi Conductors
Types of Materials (Conduction)
Conductors
Metals, Higher population of free electrons
Insulators
Have very few free electrons at room temperature
Semi Conductors The Concentration of electrons at room temperature is
in betwe