p = 40kPa Load Case 2 p = 40kPa, 200N force Comosworks p = 20kPa DisplacementStress - Radial Stress - Tang. Displacement Stress - Radial Stress Tang. Displacement: Node X (m) Value (mm) Value (N/m^2)
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4315103, Moaz Ahmed
7442491, Mohammad Sharafatul Islam
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DESIGN PROJECT
DESIGNING A SOLA
Chapter 7: The Energy Equation
Faculty of Engineering and Industrial Sciences
Swinburne University of Technology
Summer 2010
The Energy Equation
Kinetic Energy
(fluid jet)
A fluid can have
several for
CHAPTER 05
1. The amount of mass in a system is constant. True or False
A. True
B.False
2.The _ is the control volume expression for the conservation of mass.
YOUR ANSWER: continuity equation
3.If den
Chapter 4: Flowing Fluids and Pressure
Variation
Faculty of Engineering and Industrial Sciences
Swinburne University of Technology
Summer 2010
Streamline
Flow visualization is the visual examination o
Question 1 a) Intensive properties do not depend on the size (extent) of the system but extensive properties do. b) The fluids whose shear stress is proportional to the velocity gradient are called Ne
Chapter 5: Control Volume Approach
and Continuity Equation
Faculty of Engineering and Industrial Sciences
Swinburne University of Technology
Summer 2010
Overview
Engineers are often concerned about ev
Fluid Mechanics 1 Assignment 2 Due Date 5/10/2009 at 5:00 PM
Question 1
I. A velocity field is given by: Velocity fields are plotted V 6 x ^ m/s j below, where the arrows indicate the magnitude and di
A 1. tank is filled with seawater to a depth of 12 ft. If the specific gravity of seawater is 1.03 and the atmospheric pressure at this location is 14.8 psi, the absolute pressure (psi) at the bottom
Chapter 4: Flowing Fluids and Pressure
Chapter 4: Flowing Fluids and Pressure
Variation
Faculty of Engineering and Industrial Sciences
Swinburne University of Technology
Summer 2010
Overview
Many phen
Chapter 7: The Energy Equation
Faculty of Engineering and Industrial Sciences
Swinburne University of Technology
HES2340 : Fluid Mechanics 1
1
Chapter 7: The Energy Equation
The Energy Equation
flow
Chapter 10: Flow in Conduits
Faculty of Engineering and Industrial Sciences
Swinburne University of Technology
Summer 2010
Pressure Drop and Head Loss
Pressure Drop
are the sum of
+
Major Losses
due t
Chapter 10: Flow in Conduits
Faculty of Engineering and Industrial Sciences
Swinburne University of Technology
Summer 2010
Pressure Drop (Loss)
Pressure Drop (Loss)
are the sum of
+
Major Losses
due t
Chapter 15: Open Channel Flow
Faculty of Engineering and Industrial Sciences
Swinburne University of Technology
Summer 2010
Objectives
FLOW IN OPEN CHANNELS
Understand
State of Flow
Flow Classificatio
Chapter 15: Flow in Open Channels
Faculty of Engineering and Industrial Sciences
Swinburne University of Technology
Summer 2010
Open-Channel Flows
Learn the different flow
regimes
in
open
channels
and
Chapter 10: Flow in Conduits
Faculty of Engineering and Industrial Sciences
Swinburne University of Technology
Summer 2010
Flow in Pipes
Laminar flow
Understand
Analysis of
fully developed
flow
Pipe s
Chapter 6: Momentum Equation
Faculty of Engineering and Industrial Sciences
Swinburne University of Technology
Summer 2010
Momentum
If an object is standing still,
then its momentum is zero
To calcula
Fluid Mechanics 1
HES2340
Chapter 1: Introduction
Dr Amal Owida
Faculty of Engineering and Industrial Sciences
Swinburne University of Technology
Summer School 2009/2010
Fluid Mechanics HES2340
Introd
QUESTION 2
SUGGESTED SOLUTION:
(a) The magnitude of the shear stress is greater at the moving plate (y = H) since max
shear stress will occur at this point.
(b) Recall
=
= (cfw_(H) + .
Deriving an ex
15.15: PROBLEM DEFINITION
Situation:
Rectangular, concrete-lined channel
Width is 4m
Slope is .004
Q = 25 m3 / s
Find:
The uniform ow depth ( m).
Assumptions:
n = 0.015
PLAN
Use the Manning equation t
10.63: PROBLEM DEFINITION
Situation:
Water drains from a tank, passes through a pipe and then jets upward.
D = 1.5 cm, L = 10 m, z = 5 m.
Two 90 elbows in pipe.
Find:
(a) Exit velocity of water ( m/ s
SUGGESTED SOLUTION:
The control volume selected is shown below .The control volume is stationary.
Free body diagram
ANALYSIS:
Recall the momentum equation
Momentum diagram
Momentum equation in x- and
10.6: PROBLEM DEFINITION
Situation:
Air is owing from a large tank to ambient through a horizontal pipe.
Pipe is 1" Schedule 40. D = 1.049 in = 0.0266 m.
V = 10 m/ s. f = 0.015, L = 50 m.
Sketch:
Find
CHAPTER 03
1. Write Newton's second law of motion.
YOUR ANSWER: F = ma
2.The lines that are tangent to the velocity vectors throughout the flow field are called
steady flow lines. True or False
A. Tru
CHAPTER 04
1. The representation of fluid parameters as a function of the spatial coordinates is termed
a _.
A. Velocity field
B. Field representation
C. Position vector
2.Name the two general approac