Chapter 2 Heat Conduction Equation 2-126 A spherical liquid nitrogen container is subjected to specified temperature on the inner surface and convection on the outer surface. The mathematical formulat
Chapter 2 Heat Conduction Equation
Variable Thermal Conductivity
2-94C During steady one-dimensional heat conduction in a plane wall, long cylinder, and sphere with constant thermal conductivity and n
Chapter 2 Heat Conduction Equation 2-68 A compressed air pipe is subjected to uniform heat flux on the outer surface and convection on the inner surface. The mathematical formulation, the variation of
Chapter 2 Heat Conduction Equation
Solution of Steady One-Dimensional Heat Conduction Problems
2-52C Yes, this claim is reasonable since in the absence of any heat generation the rate of heat transfer
Chapter 2 Heat Conduction Equation
Chapter 2 HEAT CONDUCTION EQUATION
Introduction
2-1C Heat transfer is a vector quantity since it has direction as well as magnitude. Therefore, we must specify both
Chapter 4 Transient Heat Conduction 4-118 Internal combustion engine valves are quenched in a large oil bath. The time it takes for the valve temperature to drop to specified temperatures and the maxi
Chapter 4 Transient Heat Conduction
Review Problems
4-105 Two large steel plates are stuck together because of the freezing of the water between the two plates. Hot air is blown over the exposed surfa
Chapter 4 Transient Heat Conduction 4-81 A cubic block and a cylindrical block are exposed to hot gases on all of their surfaces. The center temperatures of each geometry in 10, 20, and 60 min are to
Chapter 4 Transient Heat Conduction
Transient Heat Conduction in Multidimensional Systems
4-69C The product solution enables us to determine the dimensionless temperature of two- or threedimensional h
Chapter 4 Transient Heat Conduction 4-47 A hot dog is dropped into boiling water, and temperature measurements are taken at certain time intervals. The thermal diffusivity and thermal conductivity of
Chapter 4 Transient Heat Conduction
Transient Heat Conduction in Large Plane Walls, Long Cylinders, and Spheres 4-26C A cylinder whose diameter is small relative to its length can be treated as an inf
Chapter 4 Transient Heat Conduction
Chapter 4 TRANSIENT HEAT CONDUCTION
Lumped System Analysis
4-1C In heat transfer analysis, some bodies are observed to behave like a "lump" whose entire body temper
Chapter 16 - Section B - Non-Numerical Solutions
16.1 The potential is displayed as follows. Note that K is used in place of k as a parameter to avoid confusion with Boltzmanns constant.
Combination o
Chapter 14 - Section B - Non-Numerical Solutions
14.2 Start with the equation immediately following Eq. (14.49), which can be modied slightly to read: ln i = (nG R/ RT ) (n Z ) ln Z +n +1 ni ni ni
whe
Chapter 12 - Section B - Non-Numerical Solutions
12.2 Equation (12.1) may be written: yi P = xi i Pi sat . Summing for i = 1, 2 gives: P = x1 1 P1sat + x2 2 P2sat . Differentiate at constant T : d 1 d
Chapter 11 - Section B - Non-Numerical Solutions
11.6 Apply Eq. (11.7): (nT ) Ti ni =T n ni =T (n P ) Pi ni =P n ni m ni =P
P ,T ,n j
T , P ,n j
P ,T ,n j
T , P ,n j
11.7 (a) Let m be the mass of the
Chapter 10 - Section B - Non-Numerical Solutions
10.5 For a binary system, the next equation following Eq. (10.2) shows that P is linear in x1 . Thus no maximum or minimum can exist in this relation.
Chapter 9 - Section B - Non-Numerical Solutions
9.1 Since the object of doing work |W | on a heat pump is to transfer heat | Q H | to a heat sink, then: What you get = | Q H | What you pay for = |W |
Chapter 8 - Section B - Non-Numerical Solutions
8.12 (a) Because Eq. (8.7) for the efciency Diesel includes the expansion ratio, re VB / V A , we relate this quantity to the compression ratio, r VC /
Chapter 7 - Section B - Non-Numerical Solutions
7.2 (a) Apply the general equation given in the footnote on page 266 to the particular derivative of interest here: T S T = P S S P P T The two partial
Chapter 6 - Section B - Non-Numerical Solutions
H S =T
P
6.1 By Eq. (6.8),
and isobars have positive slope T S
Differentiate the preceding equation: 2 H S2
2 H S2 =
P
=
P
P
Combine with Eq. (6.17):
T
Chapter 5 - Section B - Non-Numerical Solutions
5.1 Shown to the right is a P V diagram with two adiabatic lines 1 2 and 2 3, assumed to intersect at point 2. A cycle is formed by an isothermal line f
Chapter 4 - Section B - Non-Numerical Solutions
4.5 For consistency with the problem statement, we rewrite Eq. (4.8) as: CP = A + B C T1 ( + 1) + T12 ( 2 + + 1) 2 3
where T2 / T1 . Dene C Pam as the v
Chapter 3 - Section B - Non-Numerical Solutions
3.2 Differentiate Eq. (3.2) with respect to P and Eq. (3.3) with respect to T : P T =
T
1 V2
V P V T
T
V T V P
+
P
1 V
2V PT 2V T P
= +
2V PT 2V PT
=
P
Chapter 2 - Section B - Non-Numerical Solutions
2.3 Equation (2.2) is here written: Ut + EP + EK = Q + W
(a) In this equation W does not include work done by the force of gravity on the system. This i
Chapter 1 - Section B - Non-Numerical Solutions
1.1 This system of units is the English-system equivalent of SI. Thus, gc = 1(lbm )(ft)(poundal)1 (s)2 1.2 (a) Power is power, electrical included. Thus
10.35 a) The equation from NIST is: Mi = ki yi P The equation for Henry's Law is:i Hi = yi P x Solving to eliminate P gives: By definition:
Mi Hi
Eq. (1) Eq. (2) Eq. (3)
=
Mi
=
ni ns Ms
ki xi
where M
Problems 10.25 to 10.34 have been solved using MS-EXCEL 2000 We give the resulting spreadsheets. Problem 10.25 a) BUBL P T=-60 F (-51.11 C) P=200 psia P=250 psia P=215 psia (14.824 bar) ANSWER Ki yi=K