chap-09-solutions
JJ Wang: Cal State U Long Beach
Chapter 9, Solution 1
By observation
Now
y
dI y
h
x
b
x2
x 2 [(h
dA
hx 2 1
x
dx
b
b
Then
Iy
dI y
y )dx]
hx 2 1
0
1
h x3
3
x
dx
b
x4
4b
JJ Wang: Cal State U Long Beach
b
or
0
Iy
13
bh
12
Chapter 9, Solution
chap-08-solutions
JJ Wang: Cal State U Long Beach
Chapter 8, Solution 5
To start block up the incline:
s
0.20
s
tan 1 0.20 11.31
Force triangle:
P
sin 36.31
800 N
sin 98.69
P
479.2 N
To prevent block from moving down:
Force triangle:
P
sin 13.69
800 N
sin
chap-07-solutions
JJ Wang: Cal State U Long Beach
Chapter 7, Solution 1
From Problem 6.79: On JD
D 80 lb
FBD of JD:
Fy
0: V
80 lb
0
Fx
0: F
0
MJ
0: M
(80 lb)(6 in.)
JJ Wang: Cal State U Long Beach
V
80.0 lb
F
0
M
480 lb in.
0
Chapter 7, Solution 8
FBD Rod
chap-06-solutions
JJ Wang: Cal State U Long Beach
Chapter 6, Solution 1
AB
32 1.252
BC
32
42
3.25 m
5m
Reactions:
MA
0: (84 kN)(3 m) C (5.25 m)
C
Fx
0: Ax
C
Ax
Fy
0
48 kN
0
48 kN
0: Ay
84 kN
Ay
0
84 kN
Joint A:
Fx
0: 48 kN
12
FAB
13
FAB
Fy
0: 84 kN
0
52 k
chap-05-solutions
JJ Wang: Cal State U Long Beach
Chapter 5, Solution 2
Dimensions in mm
A, mm 2
x , mm
y , mm
x A, mm3
y A, mm3
1
1200
10
30
12000
36000
2
540
30
36
16200
19440
28200
55440
1740
Then
X
xA
A
28200
1740
X
16.21 mm
Y
yA
A
55440
1740
Y
31.9 m
chap-04-solutions
JJ Wang: Cal State U Long Beach
Chapter 4, Solution 2
Free-Body Diagram:
MA
0 : (2 F )(1 m) (60 N)(0.15 m) (250 N)(0.3 m)
F
JJ Wang: Cal State U Long Beach
0
42.0 N
Chapter 4, Solution 14
Assume B is positive when directed
Sketch showing
chap-03-solutions
JJ Wang: Cal State U Long Beach
Chapter 3, Solution 1
Note that
and
20
28
20
8
(16 N) cos8
15.8443 N
Fy
Also
Fx
(16 N)sin 8
2.2268 N
x
(0.17 m) cos 20
0.159748 m
y
(0.17 m)sin 20
0.058143 m
Noting that the direction of the moment of each
chap-02-solutions
JJ Wang: Cal State U Long Beach
Chapter 2, Solution 7
Using the triangle rule and law of sines:
(a)
sin
50 N
sin
sin 25
35 N
0.60374
37.138
(b)
25
R
sin117.86
180
180 25
117.86
37.1
37.138
35 N
sin 25
JJ Wang: Cal State U Long Beach
R
73