ME 352 - Machine Design I
Name of Student:_
Fall Semester 2012
Lab Section Number:_
EXAM 1. OPEN BOOK AND CLOSED NOTES.
Wednesday, September 26th, 2012
Please use the blank paper provided for your sol
ME 352 - Machine Design I
Fall Semester 2012
EXAM 2. Answers
Problem 1 (25 Points)
(i) X C = 0.5 cm/cm
YC = 0.866 cm/cm
X C = + 0.825 cm/cm2
YC = + 0.390 cm/cm2
(ii) ut = + 0.5 i + 0.866 j
un = 0.866
Problem 1 (25 Points)
(i) 3.8 kg-m2
(ii) 3.39 N-m, CCW
Problem 2 (25 Points).
Part I.
Exact: 1 = 477.41 rad/s
and
2 = 823.82 rad/s
(i) 1 = 499.69 rad/s
(ii) 1 = 413.05 rad/s
Part II.
(i) FB = 1.1944 i
Problem 1 (25 Points)
For the mechanism shown in the figure below, the input link 2 rotates with an angular velocity of
2 = 2 rad/s CCW and an angular acceleration of 2 = 5 rad/s 2 CC W. The masses an
ME 352
Spring 2013
Homework Answers
Homework No. 5
a) R2 (A to O4) + R7 (O4 to B) R3 (A to B) = 0
Using this vector loop: dR2/dt = 0.15 m/sec d2R2/dt2 = 0.10 m/sec2
b) R3 = 34.641 mm
theta3 = 120 degr
ME 352
Spring 2013
Homework No. 4
4a) Problem 3.29 on p. 162 of the text using instant centers:
Follower angular velocity = 4.38 rad/sec (hence CCW)
Roller angular velocity = -83.0 rad/ sec (hence 83.
ME 352
Spring 2013
Homework No. 3
3a) Refer to the figure for Problem 2.16 on p. 95 of the text
Position Solution:
theta 3 (vector AB) = 45 degrees
theta 4 (vector CB) = 90 degrees
Kinematic coefficie
ME 352 - Machine Design I
Spring 2013
Homework No. 3a
Name
Lab. Div. Number
Note: this is the 1_st of m problems due
Due: Friday, February 1, 2013
Refer to problem 2.16 on p. 95 of the ME 352
ME 352
Spring 2013
Answers to Homework No. 2
Configuration #1:
Configuration #2:
theta3 = 8.942 degrees
theta3 = 291.058 degrees
theta4 = 79.471 degrees
theta4 = 220.529 degrees
In part 4) after the f
ME 352 - Machine Design I
Name_
Spring 2013
Lab. Div. Number_
Homework No. 2
Due: Parts 1, 2, 3, 4 on Friday, January 25, 2013 (10 pts)
Part 5 in Lab at your first Lab period the week of January 28, 2
ME 352
Spring 2013
Answers to Homework No. 1
1) Problem 1.5 on p. 41 of the text
a) M=1
b) M=1
c) M=0 (exception since mobility is one) d) M=1
2) Problem 1.6 on p. 41 of the text
n=5 J1=5 J2=1
M=1
3)
ME 352 - Machine Design I
Name_
Spring 2013
Lab. Div. Number_
Homework No. 1
Due: Wednesday, January 16, 2013
Homework Notes (Will apply to all homeworks this semester)
(i) The handout sheet must be s
ME 352 - Machine Design I
Fall Semester 2012
EXAM 1 - Answers
Problem 1.
Part I. (7 Points).
MA 1.86
Part II (18 Points).
m 3(7 1) 2(8) 1 1
A possible set of vectors is shown in figure below.
1
Proble
ME 352 - Machine Design I
Name of Student:_
Fall Semester 2012
Lab Section Number:_
EXAM 2. OPEN BOOK AND CLOSED NOTES.
Thursday, November 8th, 2012
Write your solutions on the blank paper provided an