PHYS 101: Solutions to Chapter 7 Home Work
3.
REASONING The impulse that the roof of the car applies to the hailstones can be found from the impulse -momentum
theorem, Equation 7.4. Two forces act on the hailstones, the average force F exerted by the roof
PHYS 101: Solutions to Chapter 1 Home Work
1. REASONING We use the fact that 1 m = 3.28 ft to form the following conversion factor:
(1 m)/(3.28 ft) = 1.
SOLUTION To convert ft2 into m2, we apply the conversion factor twice:
1 m 1 m
Area = 1330 ft 2
12
PHYS 101: Solutions to Chapter 2 Home Work
3.
SSM REASONING The average speed is the distance traveled divided by the elapsed time (Equation 2.1).
Since the average speed and distance are known, we can use this relation to find the time.
SOLUTION The time
PHYS 101: Solutions to Chapter 3 Home Work
1.
SSM REASONING The displacement is a vector drawn from the initial position
to the final position. The magnitude of the displacement is the shortest distance
between the positions. Note that it is only the init
PHYS 101: Solutions to Chapter 4 Home Work
3.
REASONING In each case, we will apply Newtons second law. Remember that it is the net force that appears in the
second law. The net force is the vector sum of both forces.
SOLUTION
a. We will use Newtons secon
PHYS 101: Solutions to Chapter 5 Home Work
1.
SSM REASONING The speed of the plane is given by Equation 5.1: v 2 r / T , where T is the period or the time
required for the plane to complete one revolution.
SOLUTION Solving Equation 5.1 for T we have
2 r 2
PHYS 101: Solutions to Chapter 6 Home Work
4.
REASONING
a. The work done by the gravitational force is given by Equation 6.1 as W = (F cos ) s. The gravitational force points downward,
opposite to the upward vertical displacement of 4.60 m. Therefore, the