Physics 101/102/103 Syllabus
Welcome to the Physics 101/102/103 Sequence! Be prepared for a fun and exciting year as we explore the concepts of Mechanics,
Electricity and Magnetism, Waves, Optics, and Modern Physics together.
General Info
Class Location:
Physics 101 Conversions and Powers of Ten Exercise
The purpose of this exercise is to become familiar with how to convert between units and power of ten
notations.
Conversions
Scientists use the International System of Measurement (S.I. units) when making
1
Chapter 32 Homework Solutions
1.
SSM WWW REASONING The biologically equivalent dose (in rems) is the product of the absorbed
dose (in rads) and the relative biological effectiveness (RBE), according to Equation 32.4. We can apply
this equation to each t
1
Chapter 31 Homework Solutions
1.
A
SSM REASONING For an element whose chemical symbol is X, the symbol for the nucleus is Z X ,
where A represents the total number of protons and neutrons (the nucleon number) and Z represents the
number of protons in th
Chapter 30 Home Work Problems - Solutions
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1.
SSM REASONING Assuming that the hydrogen atom is a sphere of radius ratom, its volume Vatom is
given by
4
3
ratom.
3
Similarly, if the radius of the nucleus is rnucleus, the volume Vnucleus is given by
4
3
Chapter 29 HW Solutions
1.
REASONING AND SOLUTION The energy of a single photon is
E = hf = (6.63 1034 Js)(98.1 106 Hz) = 6.50 1026 J
The number of photons emitted per second is
Power radiated
5.0 10 4 W
7 .7 10 29 photons / s
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Energy per photon
6.50 1
Ch 27 HW Solutions
1.
SSM REASONING AND SOLUTION To decide whether constructive or destructive interference
occurs, we need to determine the wavelength of the wave. For electromagnetic waves, Equation 16.1 can
be written f c , so that
c 3.00 10 8 m
5.6
Chapter 26 Home Work Solutions
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1.
SSM REASONING The substance can be identified from Table 26.1 if its index of refraction is known.
The index of refraction n is defined as the speed of light c in a vacuum divided by the speed of light v in the
substanc
Chapter 25 Home Work Problem Solutions
3.
REASONING The drawing shows
Bird
the bird in the plane mirror, as seen
camera. Note that the image is as far
mirror as the bird is in front of it.
the distance d between the camera
image by noting that this distan
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CH 24 HW Solutions
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1.
REASONING The distance traveled by the X-rays is equal to their speed multiplied by the elapsed time.
Therefore, the elapsed time is equal to the distance divided by the speed. The distance is known. Since Xrays are electromagnet
Names:_
Physics 103 Group Session for Chapter 31 & 32
1) In electrically neutral atoms, how many
38
(a) protons are in the uranium 292 U nucleus?
(b) neutrons are in the mercury
202
80 Hg nucleus?
(c) electrons are surrounding the
93
41 Nb
nucleus?
REASON
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Physics 103 Group Session for Chapter 27, 29, & 30 - Solutions
o
1) The dark fringe for m = 0 in a Youngs double-slit experiment is located at an angle of = 15 . What is the angle that
locates the dark fringe for m = 1?
REASONING In a Youngs doubl
Names:_
Physics 103 Group Session for Chapter 24 26-Solutions
1) The police car is moving to the right at 27 m/s, while the speeder is coming up from behind at a speed of 39 m/s.
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Assume that the electromagnetic wave emitted by the radar gun has a freque
Velcome to the Vorld of Vectors
sa Bradley M.S. Physics 101
Scalars & Vectors
Scalar Quantity:
Has magnitude only, no direction Can be expressed with a single number (and units)
Vector Quantity:
Has magnitude and direction Are expressed with numbers and
1
Chapter 22 Homework Solutions
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3. REASONING AND SOLUTION The motional emf generated by a conductor moving perpendicular to
a magnetic field is given by Equation 22.1 as = vBL, where v and L are the speed and length,
respectively, of the conductor, and
Chapter 21 Homework Solutions
1.
SSM REASONING AND SOLUTION The magnitude of the force can be determined using Equation
21.1, F = q vB sin where is the angle between the velocity and the magnetic field. The direction of the
force is determined by using Ri
Physics 102, Chapter 20 Homework Solutions
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1. REASONING The current I is defined in Equation 20.1 as the amount of charge q per unit of time t
that flows in a wire. Therefore, the amount of charge is the product of the current and the time interval. The
Physics 102 Chapter 19 Homework Solutions
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1.
REASONING When the electron moves from the ground to the cloud, the change in its electric potential
energy is (EPE) = EPEcloud EPEground. (Remember that the change in any quantity is its final value
minus it
Physics 102: Chapter 18 Homework Solutions
1.
SSM REASONING AND SOLUTION The total charge of the electrons is
q = N(e) = (6.0 1013)(1.60 1019 C)
q = 9.6 106 C = 9.6 C
The net charge on the sphere is, therefore,
qnet = +8.0 C 9.6 C = 1.6 C
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3. REASONING
a
Physics 102 Homework Solutions: Ch 17
5.
SSM REASONING The tones from the two speakers will produce destructive interference with the smallest
frequency when the path length difference at C is one-half of a wavelength. From Figure 17.7, we see that the pa
Physics 102 Homework Solutions: Ch 16
1.
SSM REASONING Since light behaves as a wave, its speed v, frequency f, and wavelength are related to
according to v = f (Equation 16.1). We can solve this equation for the frequency in terms of the speed and the
wa
PHYS 101: Solutions to Chapter 9 Home Work
1. REASONING AND SOLUTION
According to Equation 9.1, we have
Magnitude of torque = F
where F is the magnitude of the applied force and is the lever arm. For an axis passing through the cable car at
its center and
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Chapter 23 Homework Solutions
1.
SSM REASONING The voltage across the capacitor reaches its maximum instantaneous value when
the generator voltage reaches its maximum instantaneous value. The maximum value of the capaci tor
voltage first occurs one-four
PHYS 101: Solutions to Chapter 6 Home Work
4.
REASONING
a. The work done by the gravitational force is given by Equation 6.1 as W = (F cos ) s. The gravitational force points downward,
opposite to the upward vertical displacement of 4.60 m. Therefore, the
PHYS 101: Solutions to Chapter 5 Home Work
1.
SSM REASONING The speed of the plane is given by Equation 5.1: v 2 r / T , where T is the period or the time
required for the plane to complete one revolution.
SOLUTION Solving Equation 5.1 for T we have
2 r 2
PHYS 101: Solutions to Chapter 4 Home Work
3.
REASONING In each case, we will apply Newtons second law. Remember that it is the net force that appears in the
second law. The net force is the vector sum of both forces.
SOLUTION
a. We will use Newtons secon
PHYS 101: Solutions to Chapter 3 Home Work
1.
SSM REASONING The displacement is a vector drawn from the initial position
to the final position. The magnitude of the displacement is the shortest distance
between the positions. Note that it is only the init
PHYS 101: Solutions to Chapter 2 Home Work
3.
SSM REASONING The average speed is the distance traveled divided by the elapsed time (Equation 2.1).
Since the average speed and distance are known, we can use this relation to find the time.
SOLUTION The time
PHYS 101: Solutions to Chapter 1 Home Work
1. REASONING We use the fact that 1 m = 3.28 ft to form the following conversion factor:
(1 m)/(3.28 ft) = 1.
SOLUTION To convert ft2 into m2, we apply the conversion factor twice:
1 m 1 m
Area = 1330 ft 2
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PHYS 101: Solutions to Chapter 7 Home Work
3.
REASONING The impulse that the roof of the car applies to the hailstones can be found from the impulse -momentum
theorem, Equation 7.4. Two forces act on the hailstones, the average force F exerted by the roof