TEE! At t = 0 , the circuit is under dc conditions.
6
. m i(O=9=6A
6 + 3
i f Since the inductor current
cannot change
an o 9 A 72 1 instantaneously,
i(O=i[0+]=i(0]=6A
Fort>0
Atr=oo
13
Iw=2A
() 9
T29
L
1':
R9!
R0! = T2H[6+3] = 351
0.5 1
r=s
3 16

When applying equations 15
lt'ila) and (b), it is customary to
express rat in radians and ii in
degrees, yielding mixed angular
units (as indicated in the follow-
ing examples. Although this is
acceptable when the equations
are written in symboiic form.
y

[able 9-2
Phasor Representation
1; =150cos(500:+45) (V)
r = 3.0 sin (2000: + 30) (mA)
= summons: 60) (mA)
The phase angle of45 can be seen in the time-domain graphs of i and 1 shown in Fig. 9-6(a), and the phasor
diagram with I and V shown in Fig. 9

3.8 Find all branch currents in the network shown in Fig. 3-l4(o).
Fig. 3-14
The equivalent resistances to the left and right of nodes at and h are
llzlll
Roqllelt = 5 +T = 9.3 9
(51(3)
swim 2T: too
Now referring to the reduced network of Fig. 344(k),
2

5/7/2015
Find i(t) for t>0 in the circuit below. (Make clean
circuit diagrams & show all calculations for max.
marks.)
08 May 2015
Section: A
Batch^2014
Do not remove the question paper from
the answer script.
NA-Test 2
Roll No: 2014-EEMax. Marks % 5
Find

Series RC, RL, and RLC Circuits
Parallel RC, RL, and RLC
Circuits by Mr. Fawad Shaukat
EE 201- NETWORK ANALYSIS Sring 2015
General Information
i=
dQ
dt
vR = RiR
Q 1 t
iC ( ) d
=
C C
di
vL = L L
dt
vC =
Time Constants
L
RL =
R
Natural frequency
(1a)
Q =

By: Fawad Shaukat
TOOL:
RLC CIRCUITS
GENERAL RLC SOLUTION
Summary
Series and parallel RLC circuits may be solved by a step-by-step procedure outlined
below in (a)-(d). Figs. 1 and 2 illustrate series and parallel RLC circuits. Note that
the circuitry to w

INTRODUCTION TO SIMULATION USING ELECTRONIC
WORKBENCH
CONTENTS:
1. Introduction
2. Use of Electronic workbench
3. Analyzing EWB blocks models
3.1 Specifying the type of analysis with simulation
4. Building and Testing the circuit
4.1 Using the main instru

RLC CIRCUITS
Step 0: If not specified, determine the initial capacitor voltage V C(0-) and initial
inductor current IL(0-) using circuit analysis.
These are the two parameters that cannot change instantly, thus
VC(0-) = VC(0+)
and
IL(0-) = IL(0+)
In order

(SSUET/QR/110)
SIR SYED UNIVERSITY OF ENGINEERING & TECHNOLOGY, KARACHI
ELECTRONIC ENGINEERING DEPARTMENT
3rd SEMESTER
NETWORK ANALYSIS (EE-201)
Aims and Objectives
This course is the foundation on which most other courses in electrical
engineering curric