ECE 580: Optimization by Vector Space Methods
Fall 2013
Midterm Exam
R. Srikant
October 23 2013, 7:00-8:15pm
There are four problems, each worth 25 points, for a total of 100 points. There is also a bonus
problem worth ve points; this problem will not use
ECE 580 / Math 587
Correspondence # 12
FALL 2006
March 26, 2011
SOLUTION TO
THE MIDTERM EXAM
Problem 1
(i) Let x(t) = y (t) 1 t. The given constraint can then be written in terms of x as follows:
1
(
)
t 1 + t + x(t) dt = 1
1
0
tx(t) dt =
0
1
6
Then, the
ECE 580 / Math 587
SPRING 2011
Correspondence # 5
February 17, 2011
Solution Set 2
cfw_
11.
11
1
lim xi = 1, , , . . . , n , . . . . . . because it has innitely many elements.
p
i
24
2
Now,
(xn , xm ) =
( n1
)1
1 p
0 as m, n ,
m < n.
m, n,
2ip
i=m
m<n
ECE 580 / Math 587
SPRING 2011
Correspondence # 1
January 24, 2011
ASSIGNMENT 1
Reading Assignment:
Text: Chapters 1 & 2.
Recommended Reading:
Curtain & Pritchard: Chapter 1.
Problems (to be handed in):
Due Date:
Thursday, February 3.
1. Let M and N be su
ECE 580 / Math 587
SPRING 2011
Correspondence # 17
April 21, 2011
Solution Set 6
41.
(i) We are given that (xn xo , x) 0 (and equivalently that (x, xn xo ) 0) for all
x X , and that xn x . Then,
xn xo 2 = xn 2 + (xn , xo ) (xo , xn xo )
= xn 2 xo 2 (xn xo
ECE 580
Optimization by Vector Space Methods
Spring, 2008
About the Midterm
Prof. Sean Meyn, [email protected]
Mon. & Weds., 11-12:30, 106B6 Engg. Hall
It is now ocial: the midterm exam will be held on Tuesday eve., March 4, 6:00-7:30 .
Content The exam will
ECE 580 / Math 587
Professor Tamer Baar
s
SPRING 2011
May 5, 2011
FINAL EXAM
DUE DATE & TIME : Monday, May 9, 2011; 9:00 am.
If I am not around, leave with my secretary next door to my oce at CSL, or
slide under my door.
Answer the four questions below, s
ECE 580 / Math 587
SPRING 2011
Correspondence # 3
February 3, 2011
Solution Set 1
1. Let x M + N . Then x = m + n with m M , n N . Clearly m M N , n M N and
x = m + n [M N ]. Thus M + N [M N ].
Let x [M N ]. Then x =
where
k
i=1 di yi
m=
with yi M or yi N
cams; + hék 4K»
weds.
(MN fXAéz .3 yékatk
Muww
Jam as A0913 0 kW
NMD-IQ Ww* W xeg 3419A!» MUM: \\ F\\X
a PM é \\&\\M\\m\l w
$7 \\F\\ e MM
FwACN 16H
FW 9 1W3
77 HF: \{C(4§\
m
19X
2 W \HM\
M»:
71" _ I
., W WM MM
M? um} gnu. max\0l \JS}: 0
3"