Online Lecture Worksheet |
5.4 & 5.5
Name_
PART 1
5.4
5.5
3.
PART 2
5.4
1. Find the value(s) of x at which the function is equal to its average value on the given interval.
You will need to re-write the absolute value function when you calculate the neces
Kerry Hathaway
MTHSC 106 Bio 201
November 19, 2013
Homework 41
21.5.1 The data here has the form (Time, Temperature) where the time is the
amount of time that has elapsed since a rabbit was inoculated with
MTHS 1060 Test 1 Answer Key Fall 2013
Calculus of One Variable | Version A Sections 1.1 1.3, 2.1 - 2.6, 3.1 - 3.3
Students Printed Name: CUID:
Instructor: Section:
Instructions: You are not permitted to use a calculator on any portion of this test. Y
Online-Lecture Worksheet KEY
Velocity and Net Change (6.1) Pts 1 and 2
1. Find the position and velocity of an object moving along a straight line with the acceleration ,
initial velocity and initial position .
2. Consider an object moving along the x-axi
In-Class Activity KEY
5.3 Fundamental Theorem of Calculus
Names_
PART 1
1. The graph of fis shown in the figure. Let A(x) =
for f. Evaluate the following area functions.
(a) F(5)
(c) A(8)
()
and F(x) =
()
be two area functions
(b) F(8)
(d) F(2)
2. Evalu
Online Worksheet KEY
5.2 Definite Integrals
NAME_
PART 1
1. Given: The graph of f(x), where the area of Region I = 2 and the area of
Region II = 20.
Find the following definite integrals:
2. Consider f(x) = x 1 on [0, 4]
(a) Sketch the function on the giv
Online-Lecture Worksheet
Approximating Areas Under Curves (5.1)
PART 1
1. Consider the function on [2,4].
(a) Sketch the graph of the function on the given interval.
(b) Calculate the left Riemann sum using n = 4.
(c) Calculate the right Riemann sum using
Online Lecture Worksheet Key
LHopital (4.7) & Derivatives (4.8)
Name_Table_
Part 1:
Part 2
2. Find the general antiderivative F(x) for the function f(x). No negative exponents in your final
answer.
3. Solve the initial value problems. No negative exponent
Online LECTURE WORKSHEET
Optimization (4.4)
NAME_
_
Part 1
Part 2
1. What two positive real numbers whose product is 50 have the smallest possible sum? Use the
guidelines for solving optimization problems to answer this question. Dont forget to define you
In-Class Learning Activity
Maxima and Minima (4.1)
1. Use the graph below to identify the points on the interval at
which local and absolute extreme values occur.
2. Find the critical points of .
3. Find the absolute max and min of
PART 2
1.
2.
3.
Test 1 Answer Key
MTHS 1060
Version B
Calculus of One Variable I
Fall 2013
Sections 1.1 - 1.3, 2.1 - 2.6, 3.1 - 3.3
Students Printed Name: _ CUID: _
Instructor: _ Section: _
Instructions: You are not permitted to use a calculator on any portion of this te
Kerry Hathaway
Math 106 B 201
November 18, 2013
Homework 40
21.5.1 The data here has the form (Time, Temperature) where the time is the
amount of time that has elapsed since a rabbit was inoculated with a vi
Kerry Hathaway
HW #11
MTHS 106B 201
9/13/13
Exercise 8.2.1
Let f(t) = t^2 + 2 on the interval [1,3] with P = cfw_1, 1.5, 2.0, 2.5, 3.0 and E = cfw_1.2, 1.8,
2.3, 2.8.
I used MatLab to calculate the R
Kerry Hathaway
HW #29
October 26, 2013
MTHS106 B 201
16.1.9.
Find the first 6 Euler approximations for x = 2.5x with x(0)=6 for h=.3. Find the true
values and errors also. This time use the function DoEu
Kerry Hathaway
HW #32
MTHS 106 B 201
November 3, 2013
16.2.1-16.2.4
16.2.1
h = .05 and the model is y = .07 y (75 y), y(0) = 5.
> f = @(t,x) .07*x.*(75-x);
> true = @(t) 75./( 1 + (75/5 -
Newtons Law of Cooling Project
by Kerry Hathaway
MTHS 1060 Bio 201
Dr. Peterson
November 4, 2013
Introduction:
According to Newtons Law of Cooling, the temperature change of an object is proportional to
the difference between its own temperature and the t
Kerry Hathaway
HW #33
MTHS 1060 Bio 201
November 5, 2013
17.4.1
Examine the different between the steady state values for repression and activation
in the case T= 1.5. Here you would use CSSACT = @(tau,R)tau.*R.
Kerry Hathaway
HW #32
MTHS 106 B 201
November 3, 2013
16.2.1-16.2.4
16.2.1
h = .05 and the model is y = .07 y (75 y), y(0) = 5.
> f = @(t,x) .07*x.*(75-x);
> true = @(t) 75./( 1 + (75/5 -
MthSc 106 Test 3 Answer Key Fall 2012
Calculus of One Variable I Version A Sections 4.5 4.8, 5.1 5.5, 6.1
Students Printed Name: CUID:
Instructor: Section:
Instructions: You are not permitted to use a calculator on any portion of this test. You a
MthSc 106 Test 2 Answer Key Fall 2012
Calculus of One Variable | Version A Sections 3.4 3.8, 4.1 4.4
Students Printed Name: CUID:
Instructor: Section:
Instructions: You are not permitted to use a calculator on any portion of this test. You are not
a