1. It is suspected that a coin is not balanced (not fair). Let p be the probability of tossing a head.
To test H0: p = 0.5 against the alternative H1: p > 0.5, a coin is tossed 15 times.
Let X be the number of times a head is observed in the 15 tosses of
What test is used to compare the rank order differences of two
Question 1 options:
Question 2 (1 point)
What type of tests can be used if the assumptions of normalcy
are being met?
Q. 1 A veterinarian surveys 26 of his patrons. He discovers that 14 have dogs, 10 have cats, and 5 have
fish. Four have dogs and cats, 3 have dogs and fish, and one has a cat and fish. If no one has all three
kinds of pets, how many patrons have none of t
Conduct a hypothesis test for the following scenario.
A coffee-dispensing machine is supposed to deliver 12 ounces of liquid into a large paper cup, but the costumer
believes that the actual amount is less. As a test he plans to obtain a sample of 30 c
With these values, vve eempute hl:
The formulae for ealeulatihg the mean values of the variables is" and F:
With these values, eempute 432-0:
EDD = [155
The equatien of the regression line
[in] Regression to the mean :
On average, the observations tend to cluster around the mean,whether or not they follow a
really unusual value. It only becomes most obvious when a strange resultis
followed by something much more ordinary.
In this example, t
[1) The derived the probability distribution for X isp (I).
The number of breakdowns on a given day is
The value ofmean is given:I by
E[X) = [3.25
The exact answer is [3.25.
[2) The value ofE[X2:I=Z;r2-pl:x:|
[13) The standard normal distribution is
P|:2.25 is 31.25) = PIZE c:1.25)P|:z -=:2.25)
:3 3.33435 3.312224 [3inee on using eaeel funetion, = storm sinv|:pro3o3sfity):|
2 = 3.3321
Therefore, the probability is 3.3321
[13) The standard normal dist
IifJ'ne hundred sixty:r students are randomlyr assigned to reeeitre either the multivitamin
or a pl aeebo and are instrueted to take the as signed drug dailjgir for 20 days.
On dag:r 2E], eaeh student takes a standardized exam and the mean se
The range rule tells us that the standard deviation of a sample is approximatelv equal to one
fourth of the range of the data. In other words.s= 4
From the above range rule, we may not eonvinee that the distribution i
[raj The sample size is as: 3100.
The preparti an is; = [3.056.
The nieanis ELY): up
ZhEIZij = 3100 
The standard deviatien is J: upq
[hjl The page at 3100 eharaeters is feund te have the l
[1) The formula for calculating the range is
Rouge = Moat warm Mississasm
= %Zcfw_1261335)3 ans133.5113 HEB-133530 lo-13353
+(1ss 433.5113 +cfw_144 133.5)2
(n) Instruetinns tn nhtain Regression output using EKEElI
* Enter the variables SEEP and NE in the eelurnns ef the eseel werl-tsheet.
* ICheese Data A; Data Analysis %~Regressien.
* Seleet the Input range I" and and the input range X.
* Cliel-t Lahels
With these values, we compute b1 :
5, 5 34335
The formulae for calculating the mean values of the variables X and I":
(Hypothetical) The General Social Survey measures the amount of hours that individuals
spend on the internet each week. Males use the Internet 10.17 hours per week. (standard
deviation 11.71 N = 118), while women use the Internet 9.08 hours per week (s
Q.1 Solve the following questions:
1. How many words can be formed by using all letters of TIHAR (1 mark)
There are five letters can be filled in five places in 5p5 ways i.e., 5!
2. Five digits are given as 3, 1
For each question, explain in detail what Mr. or Ms. Mistake are doing wrong. If appropriate,
explain what they could do be doing better
1) Mr. Mistake decides to run a regression of presidential Democratic vote share on state
unemployment. He in
1. Exercise 17-2 on page 762 of your textbook.
Using 1997 as the base yearIndex for 1998 = (14.50/6.50)*100 = 223.08
Index for 1999 = (7.50/6.50)*100 = 115.38
Index for 2000 = (10/6.50)*100 = 153.85
Index for 2001 = (14.25/6.50)*100 = 219.23
Around 1980, China adopted the so-called one-child policy, in which parents were strongly
encouraged to have only one child (except under exceptional circumstances, for example if
their rst child was disabled). A series of nancial penalties for
1. Exercise 12-14 on page 526 of the textbook.
500 180 = 320
9 X 20 = 180
11 2 = 9
320/2 = 160
160/20 = 8.00
There are 3 Treatments. The total sample size is 12.
Select a level of significa
1. Exercise 1330 on page 588 of your textbook. (10 marks)
Null Hypothesis: H0: = There is no positive correlation between family
income and student GPA).
Alternative Hypothesis: Ha: > There is positive correlation between family
income and s
Show all work (dont just provide final answers) to allow partial credit.
It is preferable that you type your solution and use the computer to
produce any graphs. However, it is acceptable to develop the solution
by hand and submit
The general manager of an engineering firm wants to know if a technical artist's experience
influences the quality of their work. A random sample of 24 artists is selected and their years of
work experience and quality rating (as assessed by their supervi
STA 215 Winter 2016 Instructor: Olsen THQ 7 10 points Due: March 31
Directions: Complete each problem, and read each one carefully. To alleviate confusion, I have
included all information from the textbook necessary to complete each problem. I have also
Use the following scenario and data for all the questions
In the past, the population proportion of consumers preferring orange juice with no pulp was
. To test if this population proportion has changed, a random sample of
consumers is selected. Among
1) Z test for single mean H0: u = u0, H1: u =/= u0
2) T test for single mean H0: u = u0, H1: u =/= u0
3) T test for two means H0: u 1= u2, H1: u1 =/= u2
4) T test for paired samples H0: d = 0, H1: d =/= 0, here d = u1 u2
5) Z test for single proportion H0
The results can be occurred in random way or cant be expected in advance
before going to do particular experiment.
Flip a fair coin, then results are known such as head and tail but we
cannot expect which result will happen.
Topics of the test:
Regression, Correlation, Chi-square tests, Permutations and Combinations, Probability, expected value of
a random variable.
Q. 1 According to the records of the National Safety Council, accidental deaths in the United States
(a) From the above regression output,
we note that the value of SSE = [3.1429
(2) From the above regression output,
we note that the value of S = [1138932 .
Step1: The null and alternative hvpothes es are as follows:
He : ,31 = 0 cfw_There is no linear re