Physics 1C Winter 2015
Exam 1 Test Form A
1. A straight line crosses the triangle shown at right,
such that it is perpendicular when it crosses the right
edge of the triangle. What is the value of the angle ?
Clicker Question 24A-1
The amplitude of the oscillating electric field at your cell
phone is 8 V/m when you are 10 km from the broadcast
antenna. What is the electric field amplitude when you are
20 km from the antenna?
A) 8V/m.
B) 4V/m.
C) 2V/m.
D) 1V/m
Clicker
Question
27A-1
Suppose the viewing screen in a double-slit experiment is
moved closer to the double slit apparatus.
happens to the interference fringes?
A) They get brighter but otherwise
do not change.
B) They get brighter and closer
together.
C)
Clicker Question 13B-3
Two loudspeakers are 2.0 m apart and are driven by the
same oscillator emitting 700 Hz sound waves (speed of
sound is 341 m/s). A listener stands 5.0 m in front of
the speakers and 2.0 m to one side of the center. What
is the pathle
Clicker Question 14B-1
You are tuning a guitar by comparing the sound of the string
with that of a standard tuning fork. You notice a beat
frequency of 5Hz when both sounds are present. You tighten
the string and the beat frequency rises to 8Hz. To tune t
Clicker Question 12C-1
What is the period of the oscillations described
by 5.0m * cos(40pt)? (no calculators please)
A) 0.0 s
B) 1.0 s
C) 0.1 s
D) 10 s
E) 0.05 s
Clicker Question 12C-1
What is the period of the oscillations described
by 5.0m * cos(50pt)?
Clicker Question 13A-1
In water, if the source of the wave suddenly
doubled its frequency how would the velocity
change?
A) The velocity of the wave would quadruple.
B) The velocity of the wave would double.
C) The velocity of the wave would remain the sa
PHYS 1C S PRING 2016: QUIZ 4
Version A
Answer Keys
Version A: EAEEB BCDAB
Version B: CEEAD BBCAB
Version C: ECEDD ABCBB
Version D: BCDED CBABD
1. A contact lens is made of plastic with an index of refraction of 1.80; it is shaped as shown
in the figure be
PHYS 1C S PRING 2016: QUIZ 1
Version A
1. The Period of a simple pendulum on Earth is 3.00 seconds. When the length of the
string is increased to 10 the original length, its period becomes:
a) 3.2 seconds.
b) 5.5 seconds.
c) 0.32 seconds.
d) 1.0 seconds.
quiz4 practice problems
Multiple Choice
Identify the letter of the choice that best completes the statement or answers the question.
1. The index of refraction of cubic zirconia is 2.15. The critical angle for total internal reflection, at
a cubic zirconi
Clicker Question 12A-1
If I double the displacement, what happens to the force F2 relative to the original force
F1 ?
A) F2 = 2 * F1
B) F2 = F1
C) F2 = - 2 * F1
D) F2 = 1/2 * F1
Clicker Question 12A-1
If I double the displacement, what happens to the forc
Clicker Question 25A-2
A light ray travels from medium 1 to medium 3 as
shown in the figure below. What can we say about
the relationship between the index of refraction for
medium 1 (n1) and the index of refraction for
medium 3 (n3)?
A) n3 > n1.
B) n3 =
Clicker Question 25A-1
A light ray travels from medium 1 to medium 2 as shown in
the figure below. What can we say about the relationship
between the index of refraction for medium 1 (n1) and the
index of refraction for medium 2 (n2)?
A) n2 > n1.
B) n2 =
P302
P30.6
P3014
P30 .1 8
An iron nucleus {in hemoglobin) has a few more neutrons than
protons, but in a typical water molecule there are eight neutrons and
ten protons.
So protons and neutrons are nearly equally numerous in your body,
each contribut
P281
E
The energy of a single SOO-nrn photon is:
6.626x103 -s' 3.00x108m/s' .
l I Hi, l =3.98x10"9]
500x10 In
he
I = hf: FL
The energy entering the eye each second
E = Pm = 121204400 X 10 W/m1 {3(850 X N3 m)2]{1.00 s}
= 2.27 X 10"[5 1
The number
Physics 1C Winter 2015
Exam 2 SOLUTIONS
PHYSICS 1C WINTER 2015
EXAM 2 SOLUTIONS
Page 1 of 9
Physics 1C Winter 2015
Exam 2 SOLUTIONS
1. Which one of the following is NOT re
Question 1 10 out oft points
Unpolarized light traveling in the positive: direction with intensity lmax is incident upon two polarizers. Both polarizers lie in the xy plane. The first polarizer has a
transmission axis aligned with thex axis. The second
Mirrors:
Concave Mirrors
IMAGE BY REFRACTION:
Images by Thin Lenses:
Converging Lens:
Diverging Lens:
If the image of the first lens lies on the back side of the second lens, the image is treated as a virtualobject
for the second lens (-P)
Farsighted eye
P12.3
P12.6
x = (4.00 m)cos(3.00n't + 71:); compare this with x = Acos(a)t + ¢) to
nd
(a) w=27rf=3.007r or
0» T=%=
<c>
<d> ¢=
(e) x(t = 0.250 s) = (4.00 m) cos (1.75) =
The proposed solution,
x(t)= x1. cos wt+(&) sin wt
(0
implies velocity
dx .
v
P133 (a) We note that sin(6) = si.n(7§) = sin(8 + It), so the given wave
function can be written as
y(x, t) : (0.350) sin (107rt + Sex + n 1/4)
Comparing, 10}? t Strx + 3/4 : Rx mt + qt. For constant phase, x
must increase as I increases, so the wav
P24.4 This radio is a radiotelephone on a ship, according to Frequency
assignments made by international treaties, laws, and decisions of the
National Telecommunications and Information Administration
1
Th v; fl.- " I Z _
E' I'ESOII'IHCE' equenLy 15 f0 z
P254
P25.8
{a}
(bl
(c)
The law of refraction n, sin 9, = 112 sin 92
353°
can be put into the more general form
L L air :11 -l
sin191 = sin 92 water H; = 4/3
E).[ 02
' 9. ' t9q
5 I = 5m - ANS. FIG. P254
:2, v2
This form applies to all ki
Section 26.1
P26.1
P26.7
Images Formed by Flat Mirrors
ANS. FIG. P26.1 shows the path of rays ;,
reected by a mirror of minimum height:
rays from the person's feet and top of his J
head travel along the respective paths \Ji
123 and 543 to his eyes. T
Final Practice Problems
1. A light ray is propagating in a crystal with a wave length in the crystal of 540nm. It strikes the
interior surface of the crystal at an incidence angle of 34 degrees, and emerges into air at 76
degrees to the surface normal. Wh