Under steady-state conditions, a capacitor acts as a. an open-circuit
A 2-F capacitor is in parallel with a 4-V source. What is the energy (in joules) stored in the capacitor? e. 16
A 2-H inductor has been connected in series with a 4-V source and
Engr 260 - Circuits & Devices Sample Test 2 Part 2 Name: _
Part 2: 1. Find the current in the 6- using a) superposition, b) source transformation. Answer: 1.5 A
2. Determine Vo using nodal analysis. Ans: Vo = 8 V
3. For the circuit shown below: a
Engr 260 - Circuits & Devices - Sample Test 1 1. For the given circuit a. Find the equivalent resistance as seen by the voltage source. b. Find the current in the 5- resistor. c. Using the current divider equation, find the current in the 9- resistor
1. a. b. c.
Engr 260 - Circuits & Devices - Sample Test 1 For the given circuit Find the equivalent resistance as seen by the voltage source. Find the current in the 5- resistor. Using the current divider equation, find the current in the 9- resisto
Engr 260 - Circuits & Devices Sample Test 2 Part 2 Name: _
Part 2: 1. Find the current in the 6- using a) superposition, b) source transformation. Answer: 1.5 A
2. Determine Vo using nodal analysis. Ans: Vo = 8 V
3. For the circuit shown below: a
Engr 260 - Circuits & Devices - Test 2 March 26, 2008 Name: _ Part 2: Solve each of the following problems. 1. Find the current in the 2- resistor using superposition.
2. Use source transformation to find ix . Note: After source transformations, you
Engr 260 - Circuits & Devices February 20, 2008 Name: _SOLUTION_ 1. For the circuit shown: a) Find Req as seen by the voltage source. b) Determine the current I through the voltage source.
Req = 3 + 4 (2 + 6 3) = 3 + 2 = 5
I=
10 10 = = 2A Re q 5
2
Engr 260 - Circuits & Devices Sample Test 3
Part 2: (Note: For Part 1, go to the class website.) 1. By means of the circuit below the voltage v C is to be brought to 13 V in 3 ms by closing S1, with S2 kept open. The voltage v C is then to be kept a
Engr 260 - Circuits & Devices Sample Test 3
Part 2: (Note: For Part 1, go to the class website.) 1. By means of the circuit below the voltage v C is to be brought to 13 V in 3 ms by closing S1, with S2 kept open. The voltage v C is then to be kept a