2b) Let X be the number of hours spent in the maze, assuming the mouse starts in the center. E[X] is the
expected number of hours to leave the maze, again assuming the mouse begins from the center of the
maze. Let Y be the number of hours traveling down t
Y(t) = d/dt Y(t)
Y(0+) = d/dt Y(0+) = slope of Y just after time 0.
Hint for problem 9.9 part b:
Let h(x) = probability Mark gets the ball if we start in state x.
h(D) = 0.25 h(H) + 0.25 h (M) + 0.25 h(S) + 0.25 h(T)
(D=Dick, H=Helen, etc)
Homework 5 Clarification:
My Hint for Question 1a is not correct. It is possible for Xi to go larger than 2 the way the problem is
described. You have the option following options to solve the problem:
1. Solve the problem as stated, accounting for the po
Random Process Models in Engineering
Corrected solutions for homeworks 9 and 10 below.
Tuesday and Thursdays, 10-11:45 in room: J. Baskin 169
Lecture Notes on Probability Theory and Random Processes
Jean Walrand Department of Electrical Engineering and Computer Sciences University of California Berkeley, CA 94720 August 25, 2004
Table of Contents
Table of Contents Abstract Introduction 1 Mode