PHYS C1402(2) Midterm 2 Exam
Thursday, April 2"d, 2009
Prof. Jeremy Dodd
Answer all three questions. Point allocations for each question are shown in parentheses. You may
answer the questions in any order, but start each problem on a new page. Be sure to
Introduction to Electricity, Magnetism, and Optics C1402
Spring 2006
Midterm 2 (03/28/06)
There are 75 minutes permitted for the complete examination. Use the exam
book for your answers. Do not discuss the exam at any time. The exam is
closed book, but yo
Introduction to Electricity, Magnetism, and Optics
C1402 (Section 1)
Spring 2007
Final Exam (05/07/07)
There are 170 minutes permitted for the complete examination. Use the exam
book for your answers. Do not discuss the exam at any time. The exam is
close
PHYS C1402(2) Final Exam
Tuesday, May 12th, 2009
Prof. Jeremy Dodd
Answer all eight questions. Point allocations for each question are shown in parentheses. You may
answer the questions in any order, but start each problem on a new page. Be sure to show a
PHYS C1402(2) Midterm 1 Exam
Thursday, February 19th, 2009
Prof. Jeremy Dodd
Answer all three questions. Point allocations for each question are shown in parentheses. You may
answer the questions in any order, but start each problem on a new page. Be sure
Assignment 1 Solutions
Chpt 21 8. For ease of presentation (of the computations below) we assume Q > 0 and q < 0 (although the final result does not depend on this particular choice). (a) The x-component of the force experienced by q1 = Q is - ( Q
Assignment 2 Solutions
Chpt 23
r r 2. We use = E dA and note that the side length of the cube is (3.0 m1.0 m) = 2.0 m.
r (a) On the top face of the cube y = 2.0 m and dA = ( dA ) ^ . Therefore, we have j r 2 ^ ^ E = 4i - 3 ( 2.0 ) + 2 ^ = 4i - 18
Introduction to Electricity, Magnetism, and Optics
C1402 (Section 1)
Spring 2007
Midterm 2 (03/28/07)
There are 75 minutes permitted for the complete examination. Use the exam
book for your answers. Do not discuss the exam at any time. The exam is
closed
HW 5
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Chapter 28: Magnetic Fields
28.1 Magnetic Fields and the Definition of
o What Produces a Magnetic Field
Electromagnet, the current produced can be used to control a computer hard drive,
etc.
Permanent magnet, has permanent magnetic field
Mag
Do all problems. Show all your work if you want partial credit. There is an equation sheet attached.
Good‘luck and have a nice summer!
Problem 1 (40)
Assume a point-like nucleus of charge Q: +Ze where Z 2 atomic number is surrounded by a cloud of
electron
Numerical Answers to 2006 Final PHYS 1402
Imax R
NA
1.
B=
2.
Id = 4Rd 0
t
3.
High-pass lter:
2
R
Vout
=
Vin
1
c
2
+ R2
As 0, Vout 0, and as , Vout Vin
Low-pass lter:
1
c
Vout
=
Vin
1
c
2
+ R2
As 0, Vout Vin , and as , Vout 0
5.
(i)
B=
0 r dQ
2R2 dt
(ii)
Introduction to Electricity, Magnetism, and Optics
C1402 (Section 1)
Spring 2007
Midterm 1 (02/21/07)
There are 75 minutes permitted for the complete examination. Use the exam
book for your answers. Do not discuss the exam at any time. The exam is
closed
Assignment 3 Solutions
Chpt 24 24. . The potential is
VP =
1 4 0
dq 1 -Q (8.99 109 N m 2 C2 )(25.6 10-12 C) = dq = =- rod R 4 0 R rod 4 0 R 3.7110-2 m
= -6.20 V. We note that the result is exactly what one would expect for a point-charge Q at
Assignment 4 Solutions
Chpt 26 1. (a) The charge that passes through any cross section is the product of the current and time. Since t = 4.0 min = (4.0 min)(60 s/min) = 240 s, q = it = (5.0 A)(240 s) = 1.2 103 C. (b) The number of electrons N is give
Assignment 8 Solutions
Chpt 30 23. (a) Eq. 29-10 gives the field at the center of the large loop with R = 1.00 m and current i(t). This is approximately the field throughout the area (A = 2.00 104 m2) enclosed by the small loop. Thus, with B = 0i/2R
Assignment 6 Solutions
Chpt 28 6. The magnetic force on the proton is
r r r F = qv B
where q = +e . Using Eq. 3-30 this becomes (4 10-17 )i + (2 10-17)j = e[(0.03vy + 40)i + (20 0.03vx)j (0.02vx + 0.01vy)k]
^ ^ ^ ^ ^
with SI units understood.
Assignment 7 Solutions
Chpt 29 15. Each of the semi-infinite straight wires contributes 0 i / 4R (Eq. 29-7) to the field at the center of the circle (both contributions pointing "out of the page"). The current in the arc contributes a term given by