MATHEMATICS FOR PART I ENGINEERING
MA160-166
SEMESTER 1 EXAMINATION 2002/03
Full marks may be obtained for complete answers to ALL questions in section A and FOUR questions in
section B.
All questions in section A are worth 2 marks and all questions in se
MATHEMATICS FOR PART I ENGINEERING
SEMESTER I EXAMINATION
MA160-166
2001/02
Full marks may be obtained for complete answers to ALL questions in
section A and FOUR questions in section B.
All questions in section A are worth 2 marks and all questions in se
MATHEMATICS FOR PART I ENGINEERING MA160-166
SOLUTIONS TO SEMESTER 1 EXAMINATION 2002/03
SECTION A
A1.
8+61
3
1
13
x2 (x3/2 )
x2 (x3 )1/2
=
= x2+ 2 4 = x 4 = x 4
x1/4
x1/4
A2.
|x + 2| 1,
A3.
(i) cosec =
2
2
cos = 1 sin
(ii) sin + cos = 1,
cos +
A5.
d
dx
MATHEMATICS FOR PART I ENGINEERING MA160-166
SEMESTER 1 EXAMINATION 1999/00
Full marks may be obtained for complete answers to ALL questions in section
A and FOUR questions in section B.
All questions in section A are worth 2 marks and all questions in se
MATHEMATICS FOR PART I ENGINEERING MA160-166
SEMESTER 1 EXAMINATION 2000/01
Full marks may be obtained for complete answers to ALL questions in section
A and FOUR questions in section B.
All questions in section A are worth 2 marks and all questions in se
MATHEMATICS FOR PART I ENGINEERING MA160/162/166
SOLUTIONS TO SEMESTER 1 EXAMINATION 2001/02
SECTION A
A1 2x2 7x + 3 = (2x 1)(x 3),
= 0 if x =
1
or x = 3
2
A2 |x 1| > 1 x 1 > 1 or (x 1) > 1
i.e. x > 2 or x + 1 > 1 x < 1 1 = 0
Hence the solution is x < 0 o
MATHEMATICS FOR PART I ENGINEERING MA160-166
SOLUTIONS TO SEMESTER 1 EXAMINATION 2000/01
SECTION A
1
A1
x(x2 ) 3
x
1
2
2
=
xx 3
x
1
2
2
1
7
= x1+ 3 2 = x 6
A2 2 + x < 1 x < 2x
3
2 + x < 1 x 2x < 3, x <
2
1
1 x < 2x 3x > 1, x >
3
3
1
so the solution is <