Principles of MicroEconomics: 102
Problem Set #2
Part I: Costs of Production and Cost Curves
1. Let us consider an orange grove. When the grove began in the 1950s, the orange trees were planted.
Today, you have purchased the grove. The trees must b
1. (10 points) The figure below shows the position of a particle as a function of time.
What is the particles position at t = 1.00 s?
Fromthegraph:x = 2 m
Velocityisconstantfromt = 2 s to t = 5 s:
What is the particles velocity at t = 3.00 s?
x f xi
1. (10 points) A toy train is riding around a circular track of radius 0.400 m. The angular position of the
train is shown in the graph below.
from t = 0 to t = 2 s:
vt r 0.750.4 0.3 m/s
ar 2 r 0.75 0.4 0.225 m/s 2
On the graphs
1. (10 points) The figure below shows the net force on a mass of 2.70 kg as a function of time. At t = 0,
the mass has a velocity of 5.00 m/s. What is the momentum and kinetic energy of the mass at t = 3.00 s?
area under curve = J
J p mv f mvi
61 1 26 2.7
1. (10 points) A 75.0 kg man stands on a scale in an elevator. The acceleration of the elevator as a
function of time is shown below.
What the scale would read
FG = mg = (75)(9.8) = 735 N
On the graphs provided below, graph the net force on the man, the
1. (10 points) Planet X has a mass of 5.20 x 1026 kg and a radius of 3.10 x 107 m. A cube has a side
length 7.00 cm and a density of 3500 kg/m3. What will be the buoyant force on the cube when it is fully
submerged in oil (density 900 kg/m3) while on the
1. (10 points) The graphs below show the x and y components of a particles velocity. At t = 0, the
particles position was r0 6.00 m, 40 SW
a) In what direction is the particle traveling at t = 1.00 s?
from the graph: v x 2 m/s
v y 4m/s
tan tan 1 6
1. (10 points) A long thin uniform rod has a length L and a mass M. It is initially held vertically and
attached to a wall with an axle located 1/6 of the way up from the bottom edge of the rod, as shown below.
The rod is then given a slight push so that
Key Formulas 1
Review: Key Equations from PHYS 151
Work and energy
W ext = K + U + E th
W = F r = Fr cos
K = mv2
= F v
Torque: = F ; = r F