3B II
4
4
=
4.1 (p.7)
R
(b)
P
(c)
Q
(b)
(d)
P
(a)
W Y
B
2
A
3
(a)
5
0.833 m
(a)
1
4
v 1.6667
=
= 0.833 m
f
2
11
(1)
12
(2)
X
Z
Y
(b)
4.2 (p.22)
1
2
Z
C
X
W
A
T = 2 min = 2 60 = 120 s
1
1
f =
=
= 0.008 Hz
T 120
3
C
4
B
5
A
6
C
7
8
13
1 1
=
=
3B II
5
5
2
5.1 (p.47)
1
B
2
D
3
(a)
C
(1)
v = f f
v = f = 10 1 = 10 cm s
1
v P vQ
=
P Q
3
4
=
P 5
(b)
P = 3.75 cm
(2)
v = f
(c)
f=
f 4 Hz
v = f
v
=
f
=
10
4
3
B
4
D
=
D
5
5
5
= 1 cm
(b) (i)
4
= 0.8 Hz
5
D
2.5 cm
(a)
Q
=
(3)
= 2.5
3A I
3
3
(3) O
O O
3.1 (p.84)
1
D
2
(ii)(iv)(vi)
5
(i)(iii)(v)
3
(a)
A
v = vu =
1
v
5
1
(b) & (c)
1 1 1
1 5 1 6
=
+
= 1 +
=
+
=
f
v v v v v
u v
5
v
f=
6
6
(a)
(b)
3.2 (p.100)
1
B
2
D
(1) F
7
(a)
(1)
f = 18 cmu = 15 cm
1 1 1
=
+
f
u v
1
1
1
=
+
18
3A I
2
2
2.1 (p.51)
1
C
2
A
3
A
(1)
P Q
P Q
(2)
R Q
R Q
R Q
(3)
R P
11
R P
R P
4
B
sin r
sin 30
=
sin 16.5 sin 19.5
r = 25.2
5
B
n1 sin 1 = n2 sin 2
6
A
1.50 sin a = 1 sin 45
a = 28.1
7
(a)
b = a = 28.1
1 sin c = 1.50 sin 28.1
(b)
4
2
2
= 1.6 0.7 0.3 = 0.6 A
2.1 (p.60)
2.2 (p.68)
1
1
C
B
Q = It = 0.3 60 = 18 C
B = 6 2 = 4 V
2
D
1 C B
3
(a)
= VQ = 4 1 = 4 J
(b)
B
2
C
3
A
A A B
X
(1) (3)
4
C
AB D
5
(a)
(b)
6
C
5
(a), (b)
B
V1 = V3 = V4
6
7
8
(c)
9
V2V3V4
E 2270
=
=
4
3
3
P
V2
R
3.1 (p.133)
P2 = 0.07032
1
C
P5 = 0.07812
W
P10 = 0.03912
2
A
V 2 220 2
=
= 24.2
P
2000
V 2 200 2
(b) (i) =
=
= 1650 W
R
24.2
V
200
(ii) =
=
= 8.26 A
R 24.2
V
220
(c) =
=
= 9.09 A
R 24.2
7
P = I2R RI
(a)
P1 : P2 : P3 = R1 : R2 : R3
4
4
4
9
(a)
4.1 (p.166)
1
A
2
C
(b)
3
B
4
D
5
C
(1)
10
P R
(2)
P Q
(3)
6
(a)
11
(b)
7
4.2 (p.183)
1
A
2
A
3
D
8
(a)
4
B = BP + BQ =
(b)
C
5
0 I 0 2 I 3 0 I
=
2 r
2 r
2 r
B
2015
1
4
4
= 2.67 105 T
2
8
8
sy = uyt +
8.1 (p.304)
1
B
2
D
1.2
1
=0+
(9.81)t 2
2
2
t = 0.3497 s
=
t=
s x 0 .8
=
= 0.533 s
u x 1.5
7
sx
30
=
= 85.8 m s1
0.3497
t
(a)
t=
vy = uy + ayt
= 0 + 9.81 0.533
sx
3
=
= 0.3 s
u x 10
= 5.23 m s1
1
ayt 2
2
1
=0+
(9.81)0.32
2
sy = uyt
2
9
9
9.1 (p.336)
1
C
2
A
3
A
4
A
r=
(d)
=
= 25(1.7453 103)2
v
r
= 7.62 105 m s2
= 8.25 104 rad s1
2
2
(b) =
=
= 7620 s
4
8.25 10
v2
=
r
1600 2
=
(200 1740)103
6
(a)
= 17.19(1.7453 103)2
= 5.24 105 m s2
9.2 (p.353)
1
B
2
B
=
t
0.698
=
400
3
B
2
tan
Lesson 4: Laboratory: Gas Laws 1
How do quantities of gases change with changing amounts, pressures, temperatures,
and volumes? Balloons are containers of gas that you will use to explore such questions.
Specifically, you will look at how the volume of a
Unit 3: Gas Laws
EXTRA CREDIT ASSIGNMENT (CLASS CONNECT ALTERNATIVE)
September 3, 2015
ICP (2015 2016)
Gas Laws WebQuest (DUE: September 13, 2015)
I believe this assignment is a great way to introduce our next unit, Gas Laws! Itll give you a little
more i