O p t i o n a l R e v i e w - 3.6 - 3.9
S H O R T A N S W E R.
F i n d t h e d e r i v a t i v e o f y w i t h r e s p e c t t o x, t , o r , as a p p r o p r i a t e.
1) y = l n 3 x
2) y =
ln x
x7
1)
2)
1
3) y = x 6 l n x - x 3
3
3)
4) y = l n (cos(l n )
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M at h 1125 - E x a m 2 - F a l l 2010
S H O R T A N S W E R.
F i n d a l l p o i n t s w h e r e t h e f u n ct i o n i s d i sc o n t i n u o u s.
1)
1)
2)
2)
3)
3)
Pr o v i d e a n a p p r o p r i a t e r e s p o n s e.
4) Is f co n t i n u o us a t f(
Math 1125Q
Practice Problems for Exam 1
Answer the following questions. Keep in mind that you will have to show your work on the exam
to earn credit. This practice exam is not necessarily comprehensive. It is only meant for practice,
and to supplement you
Math 1125Q
Solutions to Practice Problems for Exam 1
Answer the following questions. Keep in mind that you will have to show your work on the exam
to earn credit. This practice exam is not necessarily comprehensive. It is only meant for practice,
and to s
Math 1125
Exam 2 Practice Problems
Spring 2010
1. Evaluate the following limits using limit laws. If the limit goes goes to innity or negative
innity, then say so. You should be able to justify your answers by showing work or giving
appropriate explanatio
Math 1125
Exam 2 Practice Solutions
Spring 2010
x2 4x
x(x 4)
x
= lim
= lim
= 4/5
x4 x2 3x 4
x4 (x 4)(x + 1)
x4 (x + 1)
x
x2 4x
= lim
= since for x > 1 and close to 1, we have
lim
2 3x 4
x1+ (x + 1)
x1+ x
x < 0, x + 1 > 0 and x + 1 goes to 0, so the ratio
Solutions for 3.6-3.9 review
1. y =
1
3x
3=
1
x
1
x7 ( x ) 7x6 ln(x)
2. y =
x14
3. y = 6x5 ln(x) x6
4. y =
1
x
x2
1
( sin(ln()
cos(ln()
1
5. y = 4x (ln(4)
6. y = 11(cos ) 111 ( sin )
7. Note: This problem should be written: y = (2cos )
y = 2cos ln(2)(
1125-Final Review
1 . If
, evaluate the difference quotient
.
2. Find the domain of the function.
3. Suppose that the graph of f is given. Describe how the graph of the function
the graph of f.
4. Use the table to evaluate the expression
x
f(x )
g (x )
1