In 4499M, (one) represcrvfs whi happens
1'15 'H'Ib sin n rat. h fder ue why,
MATH 1050 Group Exercise 1.3 You do a, 3%?mrwiabkc 9F to FL 5 .
1. Identify the transformations that should be made on the graph offo) = \E iozamve at me graph of 90:) = \fx + 40
Correlation
Stat 1040 Chapters 8 and 9
Objectives
Given a scatter plot of two associated variables, x and y
estimate the five-number summary of the data (average of x,
average of y, sd of x, sd of y, r).
distinguish between a linear and non-linear asso
STAT 2300 GROUP Quiz A 5.3 5.4
SHOW ALL WORK IN A CLEAR AND ORGANIZED FORMAT. IDENTIFY YOUR ANSWERS. Use 4 decimal places.
1. A bottling plant uses an automated process to ll bottles marked as containing 16 fluid ounces of spring water. Past testing has
i
27
28. All the books published by a certain publisher have a mean of 256 pages and a standard deviation of 23 pages.
A random sample of books by the publisher have a mean of 243 pages and a standard deviation of 19 pages.
(a) Summarize the given informati
x z p
n
n
30
s
x t p
n
n
1
n
p z
r
30
p
p (1 p)
n
n
p
10
n (1
p)
10
n=
z
m
n=
2
z
2m
2
n
n
H0 : = 0
z=
x
p0
/ n
2
x
s
s
30
n
H0 : = 0
t=
x 0
p
s/ n
df = n
1
p
p
2
30
np0
10
n (1
H 0 : p = p0
z=r
p
p0
p0 (1 p0 )
n
p0 )
10
2
We use a chi-square test statistic
(observed counts-expected counts)
2
X2 =
expected counts
all cells
with k 1 degrees of freedom.
k
is the number of groups/categories
*If our observed counts and expected counts are really dierent, what kind of numbers
x=
x1 + x2 + x3 + + xn
n
s2 =
P (A
( x1
2
x) + ( x2
2
x) + + ( xn
n1
) = P ( A) + P ( B )
P (A | B ) =
P(
P(
)
P (B )
P(
) = P (A | B ) P (B )
P(
) = P ( A) P ( B )
x)
2
)
X = x 1 p 1 + x 2 p2 + + x k p k
q
2
2
( x 1 X ) p 1 + ( x 2 X ) p2 + + ( x k
X=
2
x z p
n
n
30
s
x t p
n
n
1
n
p z
r
30
p
p (1 p)
n
np
10
n (1
p)
10
n=
z
m
n=
2
z
2m
2
F
F
T
x
P (22 < < 28) = 0.99
x
= 10
x = 150
C
C
n
x
= 0.01
n
n = 100
n = 196
n = 10000
n = 38416
D
x = 66.2
= 4.1
C
A
= $30
C
= 2.5
x = 29.6
B
A
Yes
We don't know.
No
Y
1
Review for Exam 1 KEY
The exam will cover:
Gathering and Describing Data
Probability Parts 1 and 2
Random Variables
Expected Value and Variance
Binomial Distribution
Normal Distribution
Sampling Distribution
Formula Sheet
You can bring one 8.5 x 11 piec
1
Probability Homework Part 1 KEY
Section 4.1
*If you don't have dice, you can use a dice roller online such as http:/www.random.org/dice/
Exercises from the book:
1. 4.2,
2. 4.6,
3. 4.7
4.2. The overall rate (56%) is an average. Graduation rates vary gr
1
Gathering Data Homework
1. Exercises from book: 3.17, 3.39. 3.53, 3.58, 3.74, 3.75
2. A study compared a group of doctors that took aspirin every day and a group of doctors that took a placebo every
day. They found that the subjects in the aspirin group
1
Probability Homework Part 1
Section 4.1
*If you don't have dice, you can use a dice roller online such as http:/www.random.org/dice/
Exercises from the book:
1. 4.2,
2. 4.6,
3. 4.7
More Exercises:
4. What is the probability of getting at least one six i
Probability - Part 2 - Homework
Question 1
a) Not always true because there may be a union
b) No, you do not subtract, but rather, add.
c) No, this just implies that they are independent
Question 2
Data
male
male liers
total liers
73%
See cell calculation
Expected Value and Variance Homework
Question 1
-The mean of the P distribution of X is:
*See Cell Calc*
0.1538
Given data
Val of X
Proby
Question 2
The mean grade in the course is:
Given
0
0.8507
1
0.1448
2
0.0045
1
0.04
2
0.2
3
0.4
0
0.05
2.88
4
0.31
Qu
Binomial Distribution Homework
Question 1
a) No, this is false because if you tossed the same coin 20,000
more times is would gradually become closer to a .5 probability in
either direction. Having so few tosses will discredit your theory.
b) Same respons
1
Normal Distribution Homework
Part 1: Shape of Normal Distribution
1. 1.109
2. 1.110
3. 1.120
Part 2: Empirical Rule
4. 1.112
5. 1.113
6. 1.122
7. 1.123
Part 3: Standard Normal Distribution
8. 1.126
9. 1.128
10. 1.129
(a) Hint: z has cumulative proportio
Normal Distribution Homework
Question 1
*On PDF file*
Question 2
*On PDF file*
Question 3
*On PDF file*
Women Men
Given
Mean:
14,297
14060
Question 4
Snd.Dev:
6,441
9065
a)
About
12,882 will fit in the 68% of the standard deviation of the mean
68%
About
2
N
n
x
X
=
=
X
X
=
q
( x1
p
p
s
x 1 p 1 + x 2 p2 + + x k p k
X
x i pi
2
2
X ) p2 + + ( x k
X ) p1 + ( x 2
a
X +a = X + a
X
b
bX = b X
X
Y
X +Y = X + Y
X
a
2
X +a
X
2
X
b
2
b X
X
=
= b2
2
X
Y
2
X +Y
=
2
X
+
2
Y
2
X ) pk
n
n
p
X = np
X
p
x
s
p
x
x
SEx
x
1
Sampling Distribution Homework
Sections 3.3, 5.1, and 5.2
Read book pages 202-209. (Skip Example 3.29 and Example 3.30)
Part 1: Samples and Populations
1. 3.83
2. A marketing research rm wishes to determine if the adult men in Laramie, Wyoming, would be
Sampling Distribution Homework
Question 1
a)
The Population is college students and the sample is 17,096. This is a fact
of the sample. Another way of putting it would me that "ABOUT" 19.4% of
college students are binge drinkers - This assuming that the s
x z p
n
n
30
s
x t p
n
n
1
n
p z
r
30
p
p (1 p)
n
np
10
n (1
p)
10
n=
z
m
n=
2
z
2m
2
n
n
H0 : = 0
z=
x
p0
/n
2
x
s
s
30
n
H0 : = 0
t=
x 0
p
s/ n
df = n
1
p
p
2
30
np0
10
n (1
H 0 : p = p0
z=r
p
p0
p0 (1 p0 )
n
p0 )
10
114
x = 3077
n = 114.
s = 987
s
x t
Condence IntervalsIntroduction
Point Estimates
We can use the sample mean x as an estimate of the population mean .
(We call it a point estimate because the sample mean is just one number, or a single point.)
Example 1. We want to estimate the true popula
1
Condence Intervals Homework
Condence Interval for Population Mean ( is known)
x z
n
Assumption: normal population or
n 30
Condence Interval for Population Mean ( is unknown)
s
x t
n
Degrees of freedom:
n1
Assumption: normal population or
n 30
Condence
Condence IntervalsIntroduction
Point Estimates
We can use the sample mean x as an estimate of the population mean .
(We call it a point estimate because the sample mean is just one number, or a single point.)
Example 1. We want to estimate the true popula
1
Condence Intervals Homework KEY
Condence Interval for Population Mean ( is known)
x z
n
Assumption: normal population or
n 30
Condence Interval for Population Mean ( is unknown)
s
x t
n
Degrees of freedom:
n1
Assumption: normal population or
n 30
Cond