ECE 290
Lecture 1
Lecture 1
Representation of Information
Topics
Course overview
Binary and hexadecimal representation of information
2s complement representation and arithmetic
Binary representation of real numbers
Codes, code distance
Error detection an
Chapter 4
Gausss Law
4.1 Electric Flux . 4-2
4.2 Gausss Law . 4-3
Example 4.1:
Example 4.2:
Example 4.3:
Example 4.4:
Infinitely Long Rod of Uniform Charge Density . 4-8
Infinite Plane of Charge. 4-9
Spherical Shell . 4-12
Non-Conducting Solid Sphere . 4-
Physics 114 Exam 3 Spring 2013
Name: _
For grading purposes (do not write here):
Question
Problem
1.
1.
2.
2.
3.
3.
4.
Question 1 (10 points). Determine the initial direction of the deflection of charged particles as
they enter the magnetic fields shown i
Chapter 3
Gauss(s) Law
3.1
3.1.1
The Important Stu
Introduction; Grammar
This chapter concerns an important mathematical result which relates the electric eld in
a certain region of space with the electric charges found in that same region. It is useful
f
Homework 1: Solutions
1. Consider how the de Broglies suggestion might explain some properties of the hydrogen atom. a. Show that the assumption h p = m = and the quantization condiction that the length of a circular orbit be an integer multiple of the le
Problem # 1:
(a) Show that the minimum conductivity of a semiconductor sample occurs when n0 = ni
(p/n).
(b) What is the expression for the minimum conductivity?
(c) Calculate the minimum conductivity for Si
NAME _
MIDTERM EXAM 2 - SOLUTIONS
(Closed book)
ECE 442
July 21, 2008
8:00 a.m. 9:00 a.m.
Instructions: Write your name, and NetID where indicated. You are allowed to use one formula
sheet (81/2 11) and a calculator. This examination consists of 2 problem
Lecture 9, p 1
Lecture 9:
Introduction to QM:
Review and Examples
S1
S2
Lecture 9, p 2
Photoelectric Effect
KEmax = e Vstop = hf
Binding
energy
The work function:
3
Vstop (v)
is the minimum energy needed to strip
an electron from the metal.
is defined
Lecture 6:
Waves Review, Crystallography,
and Examples
Lecture 6, p. 1
Single-Slit Diffraction (from L4)
Single
P
Slit of width a. Where are the minima?
Use Huygens principle: treat each point
across the opening of the slit as a wave
source.
The first min
ECE210/211
University of Illinois at
Urbana-Champaign
Analog Signal Processing
Fall 2010
Allen, Jones, Levinson
Exam 2
Thursday, October 21, 2010 - 7:00-8:15 P.M.
Name:
NetID:
Section:
(circle one)
Class:
(circle one)
9AM
10AM
ECE 210
1PM
ECE 211
Please c
E CE 2101211 University o f Illinois
Analog Signal Processing
Fan 2008
Trick, Basar, Franke
Exam 1
Thursday, September 25, 2008 -7:00~8:15 P M
Name:
Section: (circle one) Class: (circle one)
9 AM
l OAM
1 PM
ECE 210
ECE 211
Please clearly PRINT your name
Problem 1.24 The plot in Fig. P1.24 displays the cumulative charge q(t ) that has
entered a certain device up to time t . Sketch a plot of the corresponding current i(t ).
q
20 C
0
1
2
t (s)
3
4
5
20 C
Figure P1.24: q(t ) for Problem 1.24.
Solution: Based
HNG DN THAY I PASSWORD CC DCH V PDT
( EMAIL, ELEARNING, FORUM, PORTAL )
BC 1:
ngnhpvotrang Portal ( oto ) : http:\www.daotao.hcmut.edu.vn
ngnhpvotikhon
Nungnhpthnhcngchuynnbc 2
Nungnhpkhngthnhcng TH ncas 4 PDTxin reset li
password trang Portal ( oto )
Homework 1 Solutions
Physics 721
Soring 2013
1
Jackson 1.3
Using Dirac delta functions in the appropriate coordinates, express the folowing charge distributions as
three-dimensional charge densities (x).
The equations to use in solving this problem are
f
Sequential Circuit Design
Objectives
This section deals with the design of sequential circuits including the following: A discussion of the construction of state/output tables or diagrams from a word description or flow chart specification of sequential b
Digital Circuit Engineering
Product State Graphs
DIGITAL
VLSI
DESIGN
Carleton University
2008
John Knight
Seq3ProdFSM_C.fmI p. 1
Revised; April 8, 2009
Slide i
Special State Graphs
Checking for Dual Sequences
1101 or 1011 Mealy Detection
Product Graph
01
ECE 290
Lecture 2
Lecture 2
Boolean Algebra
Topics
Boolean functions
Boolean algebra identities and Boolean proofs
Principle of duality
SOP, POS
Canonical forms
Reading
M. Morris Mano, Charles R. Kime, Logic and Computer Design Fundamentals, 4th edition,
ECE 290
Lecture 3
Lecture 3
Combinational logic analysis and design
Topics
K-maps and function minimization
NAND, NOR, XOR, XNOR functions
Analysis of combinational networks
Design of combinational networks
Reading
M. Morris Mano, Charles R. Kime, Logic a
ECE 290
Homework 5
Homework #5
Problem 5.1.
In this problem you will design a Full Subtractor (FS) cell. As shown below, this cell has inputs
xi and yi and a borrow input bi. There are two outputs: difference di and borrow-out bi+1. The cell
should be des
ECE 290
Homework 6
Homework #6
Problem 6.1.
(a) Shown below is the logic diagram of a D latch. It consists of 4 NAND gates and an inverter.
It has 2 inputs: D and C.
i.
ii.
iii.
Express Q+ as a function of C, D, and Q.
Complete the next-state table for th
ECE 290
Homework 8
Homework #8
Problem 8.1.
Consider a 128M x 32 RAM
a. How many address lines and data lines would this RAM need?
b. How many bytes does this RAM hold?
c. How many 4K x 4 RAMs would you need to make a 128M x 32 RAM? What size
decoder woul
ECE 290
Lecture 10
Lecture 10
LC-3 microarchitecture and I/O
Topics
LC-3 microarchitecture
Memory-mapped I/O
Interrupt-based I/O
Reading
Y. N. Patt and S. J. Patel, Introduction to Computing Systems: from bits & gates to C & beyond, 2nd
edition, McGraw-Hi
ECE 290
Homework 6 Solution
Homework #6 Solutions
Problem 6.1
(a) Q+ = (Qbar (CD)')' = (Q (CD')')' + CD = CD + QC' + QD = CD + C'Q.
C D
Q+
0 0
Q
0 1
Q
1 0
0
1 1
When C=1, the inputs to the second stage (which is similar to an unclocked
SR latch, but with
ECE 290
Homework 7
Homework #7
Problem 7.1.
Consider a 3-bit twisted ring counter consisting of 3 D flip-flops (labeled A, B, C from left-toright) and an inverter, connected such that DB = QA, DC = QB, and DA = QC.
a. Starting with state QAQBQC = 000, giv
ECE 290
Homework 7 Solution
Homework #7 Solutions
Problem 7.1
a. 000 -> 100 -> 110 -> 111 -> 011 -> 001 -> 000 -> .
b. 010 and 101 are illegal states. If the counter starts in one of these states, it will be stuck in the
loop 010 -> 101 -> 010 -> 101 -> .