Homework 6 solution
4.11 -20C is -4F, and 50C is 122F Use subscript I to refer to interstage state. There is no interstage cooler or economizer between the compressors. Stream numbers from figure 4.9 in text. (a) condenser (Psat at 122F) = 1.7 MPa =P
1. Two streams of air are mixed in a steady-state process shown below. Assume air is an ideal
gas with a constant heat capacity CP = 7R/ 2.
(a) What is the temperature of the stream leaving the tank?
(b) What is the rate of entropy generation within the t
Duct Flow
Consider the adiabatic steady-state flow of a compressible fluid. In the absence of shaft
work and potential energy changes
H = - u2
applies. In differential form, dH = -udu.
Also, m = uA/V
Because m is constant at steady state
d (uA/V) = 0 or
d
Homework 1
1. A container filled with 25 kg of water at 20oC is fitted with
a stirrer which is driven by gravity acting on a 35 kg mass. The
weight falls slowly through a distance of 5 m and drives the
stirrer. Assuming all the work done by the weight is
Chapter 3. Volumetric Properties of Pure Fluids
The mathematic equation of PVT is called equation of state. The most simple equation of state is PV = RT, which can be used for ideal gas. PVT BEHAVIOR OF PURE SUBSTANCES The three lines display conditions o
Chapter 4. Heat Effects
In two circumstances 1. 2.
(
Constant volume U is independent on V. This is exactly true for ideal gases and incompressible fluids and approximately true for low pressure gases For
U )T dV = 0 V
Will be true
Q = U = CV dT
T1
T2
The
The Second Law of Thermodynamics
Differences between heat and work
First law: the transformation of energy, heat and work. All the efforts to make perpetual motion machine have failed The second law deals with the reaction direction and efficiency All ef
Chapter 6 Thermodynamic Properties of Fluids
Purpose of this chapter: 1. Derive equations which allow calculation of entropy, enthalpy, from PVT, CP and Cv etc 2. Discussion diagrams and tables for convenient use 3. Develop generalized correlations which
Chapter 7 Applications of Thermodynamics to Flow Processes
The discipline: Fluid mechanics and Thermodynamics
Example-1: If the states and thermodynamic properties at entrance and exit are known, first law and second low can be used for calculating the ex
Chapter 7 Applications of Thermodynamics to Flow Processes
The discipline: Fluid mechanics and Thermodynamics
Example-1: If the states and thermodynamic properties at entrance and exit are known, first law and second low can be used for calculating the ex
Chapter 8 Production of Power from Heat
The efficiency of conventional fossil-fuel steam-power plants rarely exceeds 35%. However, efficiencies greater than 50% can be realized in combined-cycle plants : from advanced-technology turbines. from steam-powe
Chapter 9 Refrigeration and Liquefaction
Application
Air conditioning of buildings, transportation, and preservation of foods and beverages Manufacture of ice Dehydration of gases Low-temperature reactions Separation of volatile hydrocarbons Continuous
CHEMICAL ENGINEERING THERMODYNAMICS I
ChBE 2110 SPRING2005 Lecture: Monday 9:05-9:55 AM Room L1255 ES&T
Text: Smith, Van Ness, and Abbott, Introduction to Chemical Engineering Thermodynamics, Seventh Ed., McGraw-Hill, 2004 (REQUIRED) Instructor: Yulin Den
function Reidel(R,Tn,Pc,Tc,MW,Hexp) Trn=Tn/Tc Trn=.577 H Hn=(R*Tn)/MW)*(1.092*(log(Pc)-1.013)/(.930-Trn) % %Hexp=Hexp*1000/MW PE=100*(abs(Hexp-Hn)/Hexp)
Review - Part one
Thermodynamic systems
Open system can exchange both energy and matter with the surroundings Closed system exchanges energy but NOT matter with the surroundings Isolated system neither energy nor matter can be exchanged with the surroundi
function RK(Tr,Pr,z) %RK(Tr,Pr,z,R,P,T) sigma=1; epsilon=0; omega=.08664; p psi=.42748; aTr=Tr^(-.5) q=(psi*aTr)/(omega*Tr) beta=(omega*Pr)/(Tr) Z=1+beta-q*beta*(z-beta)/(z+(epsilon*beta)*(z+(sigma*beta) % %V=(Z*R*T)/P end
function RK(Tr,Pr,z,R,P,T) sigma=1; epsilon=0; omega=.08664; p psi=.42748; aTr=Tr^(-.5) q=(psi*aTr)/(omega*Tr) beta=(omega*Pr)/(Tr) Z=1+beta-q*beta*(z-beta)/(z+(epsilon*beta)*(z+(sigma*beta) e=100*abs(Z-z)/Z % %V=(Z*R*T)/P end
function SRK(Tr,Pr,z,R,P,T) sigma=1; epsilon=0; omega=.08664; p psi=.42748; aTr=(1+(.48+(1.574*omega)-(.176*omega^2)*(1-(Tr^-.5)^2 q=(psi*aTr)/(omega*Tr) beta=(omega*Pr)/(Tr) Z=1+beta-q*beta*(z-beta)/(z+(epsilon*beta)*(z+(sigma*beta) V V=(Z*R*T)/P end
CHEMICAL ENGINEERING THERMODYNAMICS I (ChBE 2110) Fall 2010, Test-1 NAME: 1. October, 2010
(30) Air is compressed by a compressor at a flow rate of 0.1 kmol per second. The temperature and the velocity of air flow are 300 K and 10 m s-1 at the entrance, a
CHEMICAL ENGINEERING THERMODYNAMICS I (ChBE 2110) Fall 2010, Test-1 NAME: 1. October, 2010
(30) Air is compressed by a compressor at a flow rate of 0.1 kmol per second. The temperature and the velocity of air flow are 300 K and 10 m s-1 at the entrance, a