User access level feature is used to achieve different access levels for different
authorized users. It is useful for protecting the IP phone from unauthorized configuration,
and popularly used for the Hosted PBX solution. The following describes how to
c
Tested headset list compatible with Yealink IP Phone
Tested wired headset list compatible with Yealink IP Phone
Manufacturer
Model
Wired Headset Connection
SupraPlus (HW251, HW251N, HW261, HW261N)
Plantronics
Entera (HW111N, HW121N)
Practica (SP11, SP12)
Name: Aileen Perez
Exercise 1: Cell Transport Mechanisms and Permeability: Activity 1: Simulating Dialysis (Simple Diffusion) Lab Report
Pre-lab Quiz Results
You scored 100% by answering 4 out of 4 questions correctly.
1. The driving force for diffusion i
Name: Emily Brantner
Exercise 2: Skeletal Muscle Physiology: Activity 7: Isotonic Contractions and the Load-Velocity Relationship Lab Report
Pre-lab Quiz Results
You scored 100% by answering 5 out of 5 questions correctly.
1. During an isotonic concentric
Name: Emily Brantner
Exercise 2: Skeletal Muscle Physiology: Activity 6: The Skeletal Muscle Length-Tension Relationship Lab Report
Pre-lab Quiz Results
You scored 100% by answering 5 out of 5 questions correctly.
1. During an isometric contraction
You co
Name: Emily Brantner
Exercise 2: Skeletal Muscle Physiology: Activity 2: The Effect of Stimulus Voltage on Skeletal Muscle Contraction Lab
Report
Pre-lab Quiz Results
You scored 100% by answering 4 out of 4 questions correctly.
1. Skeletal muscle fibers a
Name: Emily Brantner
Exercise 2: Skeletal Muscle Physiology: Activity 4: Tetanus in Isolated Skeletal Muscle Lab Report
Pre-lab Quiz Results
You scored 100% by answering 3 out of 3 questions correctly.
1. Stimulus frequency refers to
You correctly answere
Name: Emily Brantner
Exercise 2: Skeletal Muscle Physiology: Activity 1: The Muscle Twitch and the Latent Period Lab Report
Pre-lab Quiz Results
You scored 100% by answering 5 out of 5 questions correctly.
1. Skeletal muscles are connected to bones by
You
Name: Emily Brantner
Exercise 2: Skeletal Muscle Physiology: Activity 5: Fatigue in Isolated Skeletal Muscle Lab Report
Pre-lab Quiz Results
You scored 100% by answering 4 out of 4 questions correctly.
1. When skeletal muscle twitches fuse so that the pea
Name: Emily Brantner
Exercise 2: Skeletal Muscle Physiology: Activity 3: The Effect of Stimulus Frequency on Skeletal Muscle Contraction Lab
Report
Pre-lab Quiz Results
You scored 100% by answering 4 out of 4 questions correctly.
1. During a single twitch
Name: Emily Brantner
Exercise 1: Cell Transport Mechanisms and Permeability: Activity 5: Simulating Active Transport Lab Report
Pre-lab Quiz Results
You scored 100% by answering 4 out of 4 questions correctly.
1. The movement of sodium and potassium maint
Name: Emily Brantner
Exercise 1: Cell Transport Mechanisms and Permeability: Activity 2: Simulated Facilitated Diffusion Lab Report
Pre-lab Quiz Results
You scored 100% by answering 4 out of 4 questions correctly.
1. Molecules need a carrier protein to he
Name: Emily Brantner
Exercise 1: Cell Transport Mechanisms and Permeability: Activity 4: Simulating Filtration Lab Report
Pre-lab Quiz Results
You scored 100% by answering 4 out of 4 questions correctly.
1. Filtration is a process that
You correctly answe
Name: Emily Brantner
Exercise 1: Cell Transport Mechanisms and Permeability: Activity 3: Simulating Osmotic Pressure Lab Report
Pre-lab Quiz Results
You scored 100% by answering 4 out of 4 questions correctly.
1. Which of the following is true of osmosis?
Name: Emily Brantner
Exercise 1: Cell Transport Mechanisms and Permeability: Activity 1: Simulating Dialysis (Simple Diffusion) Lab Report
Pre-lab Quiz Results
You scored 50% by answering 2 out of 4 questions correctly.
1. The driving force for diffusion
Direct-Current Circuits
139
(c) The total resistance of the single branch of the series circuit (Case 1) is 2R. Thus, the
current in this case is I1 = V 2R . Note that this is one half of the current I 2 that
flows through each bulb in the parallel circui
138
CHAPTER 18
Apply Kirchhoffs loop rule around loop abcfa to find
( 6.00 ) I + ( 6.00 ) I 3 = 0
or
I3 = I
(1)
Apply Kirchhoffs loop rule around loop abcda to find
( 6.00 ) I + 6.00 V ( 10.0 ) I 2 = 0
or
I 2 = 0.600 A 0.600 I
(2)
Apply Kirchhoffs loop
Direct-Current Circuits
137
(b) When the power supply is connected to points A and C, the circuit reduces as
shown below to an equivalent resistance of Req = 1.09 .
100 W
R2 + 100 W = 110 W
Req = 1.09 W
A
R1
B
R2
C
R3
D
A
R1 + R2 = 1.10 W
C
I1
+
+
5.00 V
136
CHAPTER 18
18.61
(a) Using the rules for combining resistors in series and parallel, the circuit reduces as
shown below:
10.0 W 25.0 V
+
10.0 W 25.0 V
+
I
a
10.0 W
5.00 W
5.00
W
10.0 W 25.0 V
+
I
b
I1
10.0 W
a
I
b
5.00 W
20.0
W
I1
a
25.0 W
Step 2
Step
135
Direct-Current Circuits
Some typical data values for the graph
are
R ()
1.00
5.00
10.0
15.0
20.0
25.0
30.0
3.60 W
L
PL (W)
1.19
3.20
3.60
3.46
3.20
2.94
2.70
10.0 W
R
The curve peaks at PL = 3.60 W at a load resistance of R = 10.0 .
18.60
The total re
302
CHAPTER 23
23.63. (a) The lens makers equation for a lens made of material with refractive index
n1 = 1.55 and immersed in a medium having refractive index n2 is
1
1 n1
1 1.55 n2 1
1
= 1
=
f n2
n2
R1 R2
R1 R2
Thus, when the lens is in air, we ha
134
18.58
CHAPTER 18
Consider a battery of emf connected between
points a and b as shown. Applying Kirchhoffs
loop rule to loop acbea gives
I
I2
( 1.0 ) I1 ( 1.0 ) ( I1 I 3 ) + = 0
or
2 I1 I 3 =
e
I1
a
(1)
e
1.0 W
I1 I3
c
I3
1.0
W
3.0 W
5.0 W
I2 + I3
d
Mirrors and Lenses
(c) When n1 = 1.50 and n2 = 2.00 , f =
q=
and
( 6.00 m ) ( 2 .00 )
2 .00 1.50
301
= + 24.0 m
pf
( 10.0 m ) ( 24.0 m )
=
= 17.1 m
10.0 m 24.0 m
p f
The image is 17.1 m to the left of the lens
(d) Observe from equation (1) that f < 0 if n
Direct-Current Circuits
133
Substitution of equation (4) into (3) yields
310 I1 +
140
2
= 450 or 310 I1 450 I1 + 140 = 0
I1
Solving this quadratic equation gives two possible values for the current I1 . These are
20 W
I1 = 1.0 A and I1 = 0.452 A . Then, f
336
CHAPTER 24
24.71
The refractive index, n, of the wedge material
is greater than that of the surrounding air.
Thus, when illuminated from above, light
reflecting from the upper surface of the wedge
experiences a 180 phase shift while light
reflecting f
300
CHAPTER 23
(b) When q = 3 f , we find p =
(c) In case (a), M =
3 f f
=
3f
4
q
4f
=
= 3
p
4f 3
and in case (b), M =
23.61
( 3 f ) f
q
3 f
=
= +4
p
3f 4
If R1 = 3.00 m and R2 = 6.00 m , the focal length is given by
1 n1
1
1 n1 n2
= 1
+
=
f n2
3.00 m
132
CHAPTER 18
18.55
(a) For the first measurement, the equivalent circuit is
as shown in Figure 1. From this,
1
R1
2
1
Ry + Rx
2
Ry
Rx
Figure 1
(1)
a
For the second measurement, the equivalent circuit
is shown in Figure 2. This gives
Rac = R2 =
b
c
Ry
Ra
34
CHAPTER 15
Thus, if R = 1.27 10 3 m , we must have
sin 2 =
ay R
2
v0
=
( 6.90 10
10
m s 2 ) ( 1.27 10 3 m )
( 9 550
m s)
2
= 0.961
giving 2 = 73.9 or 2 = 180 73.9 = 106.1 . Hence, = 37.0 or 53.0
(b) The time of flight for each possible angle of project
Wave Optics
Thus,
335
1
2nt
sin 2 =
(1 sin 2 2 ) = 2nt cos 2
sin 2
cos 2
= 2 nt tan 2
The condition for constructive interference is then
2nt cos 2 = ( m + 1 2 )
(b) When 1 = 30.0 , then
n1 sin 1
1 ( 1.00 ) sin 30.0
= 21.2
= sin
n
1.38
2 = sin