Solutions to Physics: Principles with Applications, 5/E, Giancoli
Chapter 20
CHAPTER 20
1.
(a) The maximum force will be produced when the wire and the magnetic field are perpendicular,
so we have
Fmax = ILB, or
Fmax/L = IB = (9.80 A)(0.80 T) =
7.8 N/m.
(
Physics 150 1st Lecture
08/28/2013
Classical Mechanics
1. Describe and predict where and when of moving objects
2. Understand forces that cause objects to move
Force
o Newtons 2nd law
F = ma
Energy
o Kinetic Energy
mv^2
Iw^2
kx^2
Momentum
o Mv
o
Homework problems Chapters 7: Approximate Methods
Read by: 11/10
Read sections: all
Homework due by: your recitation, 11/10-11
Suggested problems: Chapter 7-2, 7-5, 7-7, 7-17, 7-20, 7-21, 7-22, 7-25
Graded HW problem due by your recitation, 11/10-11:
Vari
Chapter 6: The Hydrogen Atom
Homework due by your recitation, 11/3-4
Suggested problems: 6-20, 6-21, 6-23, 6-28, 6-40, 6-45, 6-46
Additional Graded Problem hand in for grading at recitations on 11/3-4.
Explicit expressions for hydrogenlike wavefunctions (
Chem 221 Physical Chemistry I
Fall 2015
Instructor:
Professor Marsha I. Lester
Chemistry (Cret Bldg) Room 262, 215-898-4640
milester@sas.upenn.edu
Office Hours: M 5-6, F 3-4, or by appt
Teaching Assistants:
Victoria Barber, vbarber@sas.upenn.edu
Chen Li,
Kim 1
Suzy Kim
ENGL311
Prof. Paul K. Saint-Amour
5 November 2015
The Vanishing and the Dismembered: The Serialized Female Flesh of Charles Dickens
But sweet-tooth Laura spoke in haste:
Good folk, I have no coin;
To take were to purloin:
I have no copper i
University of Pennsylvania
The Wharton School
Marketing Department
Marketing 225/725 Principles of Retailing
Spring 2016
Bari A. Harlam
Marketing Department
Wharton School
Email: bharlam718@gmail.com
Telephone: 401.301.2678
Office Hours: by appointment
Co
Kirara Sato
ENGL 311
Prof. Paul Saint-Amour
Thesis Partial Draft
Haply for I am [black]: Blackface, Black Actors, and Black Identity in Othello
The theatre is a place that allows indeed, demands the transformation of identities, but in
actual practice, su
Solutions to Physics: Principles with Applications, 5/E, Giancoli
Chapter 12
CHAPTER 12
1.
Because the sound travels both ways across the lake, we have
L = !vt = !(343 m/s)(1.5 s) =
2.6 102 m.
2.
Because the sound travels down and back, we have
L = !vt =
Solutions to Physics: Principles with Applications, 5/E, Giancoli
Chapter 23
CHAPTER 23
1.
For a flat mirror the image is as far behind the mirror as the object is in front, so the distance from object to
image is
do + di = 1.5 m + 1.5 m =
3.0 m.
2.
Becau
Solutions to Physics: Principles with Applications, 5/E, Giancoli
Chapter 16
CHAPTER 16
1.
The number of electrons is
N = Q/e = ( 30.0 106 C)/( 1.60 1019 C/electrons) =
2.
The magnitude of the Coulomb force is
F = kQ1Q2/r2.
If we divide the expressions fo
Solutions to Physics: Principles with Applications, 5/E, Giancoli
Chapter 14
CHAPTER 14
1.
The required heat flow is
Q = mc T = (20.0 kg)(4186 J/kg C)(95C 15C) =
6.7 106 J.
2.
For the work to equal the energy value of the food, we have
W = (750 Cal)(4186
Solutions to Physics: Principles with Applications, 5/E, Giancoli
Chapter 10
CHAPTER 10
1.
2.
3.
4.
When we use the density of granite, we have
m = V = (2.7 103 kg/m3)(1 108 m3) =
2.7 1011 kg.
When we use the density of air, we have
m = V = LWH = (1.29 kg
Solutions to Physics: Principles with Applications, 5/E, Giancoli
Chapter 6
CHAPTER 6
1.
Because there is no acceleration, the contact force must have the same magnitude as the weight. The
displacement in the direction of this force is the vertical displa
Solutions to Physics: Principles with Applications, 5/E, Giancoli
Chapter 33
CHAPTER 33
Note: A factor that appears in the analysis of energies is
ke2 = (9.00 109 N m2/C2)(1.60 1019 C)2 = 2.30 1028 J m = 1.44 MeV fm.
1.
2.
We find the distance from
D = 1/
Solutions to Physics: Principles with Applications, 5/E, Giancoli
Chapter 32
CHAPTER 32
Note:
1.
2.
3.
A useful expression for the energy of a photon in terms of its wavelength is
E = hf = hc/ = (6.63 1034 J s)(3 108 m/s)(109 nm/m)/(1.60 1019 J/eV);
E = (
Solutions to Physics: Principles with Applications, 5/E, Giancoli
Chapter 31
CHAPTER 31
Note:
1.
A factor that appears in the analysis of energies is
ke2 = (9.00 109 N m2/C2)(1.60 1019 C)2 = 2.30 1028 J m = 1.44 MeV fm.
We find the product nucleus by bala
Solutions to Physics: Principles with Applications, 5/E, Giancoli
Chapter 30
CHAPTER 30
Note:
A useful expression for the energy of a photon in terms of its wavelength is
E = hf = hc/ = (6.63 1034 J s)(3.00 108 m/s)(109 nm/m)/(1.60 1019 J/eV);
E = (1.24 1
Solutions to Physics: Principles with Applications, 5/E, Giancoli
Chapter 28
CHAPTER 28
Note:
At the atomic scale, it is most convenient to have energies in electron-volts and wavelengths in
nanometers. A useful expression for the energy of a photon in te
Page 1 of 5
Physics 101 Midterm I
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