Solutions to Physics 101 Midterm #1 10/2/08
The average on this exam was 75 with a standard deviation of 18. The highest score was 100 and
the lowest score was 16.
1
#1 (33 points) A 1.20 kg block is launched upward from the bottom of an inclined plane wi
Solutions to Physics 101 Midterm #1 10/5/06
The average on this exam was 75 with a standard deviation of 18. The highest score was 100 and
the lowest score was 23.
#1 (33 points) A river ows from north to south with a current of 1.70 m/s. The river is 315
Solutions to Physics 101 Midterm #1 10/4/07
The average on this exam was 78 with a standard deviation of 18. The highest score was 100 and
the lowest score was 30.
#1 (33 points) You are stopped at a red light on a highway. At time t = 0 the light turns g
Page 1
Physics 101 Midterm II
Thursday November 12th, 2009
5:00 5:50 pm
LAST Name:
SOLUTIONS
First Name:
Signature:
Penn ID:
Section (circle one):
Durian-10am
Devlin-11am
This is a 50-minute closed-book examination. You may use a ruler, any calculator, an
Solutions to Physics 101 Final Examination 12/19/06
The average on this exam was 138 with a standard deviation of 34. The highest score was 199 and
the lowest score was 24.
#1 (25 points)
A wire is stretched between two posts, which are 70.0 cm apart. The
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Physics 01 M idterm I
82
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Thursday ctober tr', 009
5 : 0 0 5 : 5 0p m
LAST N ame:
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Signature:
PennI D:
Section ( circie o ne):
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Devlin-ll am
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This i s a 5 0-minutec losed-book xamination. Y ou m ay u s
PHYSICS 1
EQUATION SHEET
Prof. Doney 11/29/14
CONSTANTS/CONVERSIONS
VECTORS & RIGHT TRIANGLES
1 mi = 1.609 km = 5280 ft
Note: right (90) angle is required
1 in. = 2.54 cm
1 m = 3.28 ft
1 liter = 1000 mL = 1000 cm3 = 1x10-3 m3
1 kg = 2.2 lb
1 kcal = 4180 J
Physics 101
Classical Physics
Spring 2010
Homework 10 Solutions
DUE IN CLASS ON April 15 1. If the frequency of a wave is 200 Hz, and the wavelength is 2 m, how much time is required for a single wave to pass by an observer? (a) 0.005 s , (b) 0.050 s, (c)
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Physics 101 Midterm II
Thursday November 12th, 2009
5:00 5:50 pm
LAST Name:
First Name:
Signature:
Penn ID:
Section (circle one):
Durian-10am
Devlin-11am
This is a 50-minute closed-book examination. You may use a ruler, any calculator, and a
f
Page 1 of 5
Physics 101 Midterm I
Thursday October 8th, 2009
5:00 5:50 pm
LAST Name:
First Name:
Signature:
Penn ID:
Section (circle one):
Durian-10am
Devlin-11am
This is a 50-minute closed-book examination. You may use a ruler, any calculator, and a
form
Chapter 4: Dynamics: Newtons Laws of Motion
Solutions to Problems: 23, 25 , 34, 37, 40, 47, 67, 70, 89, 97
23.
Consider the point in the rope directly below Arlene. That point can be analyzed as having three forces on
itArlenes weight, the tension in the
71, 76, 84, 89, 62, 15
71.The minimum time between pulses would be the time for a pulse to travel from the boat to the maximum distance
and back again. The total distance traveled by the pulse will be 170 m at the speed of sound in fresh water,
1440 m/s.
Chapter 6: Work and Energy
Solutions to Problems:
12: note that since v is constant the total work done must be zero.
28, 35, 38, 39, 41, 44, 48, 55, 78, 90
y
FN
x
FP
mg
12.
Consider a free-body diagram for the grocery cart being pushed up the ramp. If th
Chapter 9: Static Equilibrium; Elasticity and Fracture
Solutions to Problems: 11,12,16,19,22,24,28,30,34,36
11.
The pivot should be placed so that the net torque on the board is zero.
We calculate torques about the pivot point, with counterclockwise
torqu
Chapter 7: Linear Momentum
Solutions to Problems: 8 11, 28, 31, 35, 37, 42, 72, 81
8.
Consider the motion in one dimension, with the positive direction being the direction of motion of
the alpha particle. Let A represent the alpha particle, with a mass of
Chapter 3: Kinematics in Two Dimensions; Vectors
Solutions to Problems: 21, 23, 27, 31, 32, 58, 59, 66
21.
Choose downward to be the positive y direction. The origin is the point where the ball is thrown from the
roof of the building. In the vertical dire
Chapter 5: Circular Motion; Gravitation
Solutions to Problems:
Gravitation: 30, 35, 44
30.
For the net force to be zero means
that the gravitational force on the
spacecraft due to the Earth must be
the same as that due to the Moon.
Write the gravitational
Solutions to Physics 101 Midterm #1 10/2/08
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The average on this exam was 75 with a standard deviation of 18. The highest score was 100 and
the lowest score was 16.
1
https:/www.coursehero.
Page 1
Physics 101 Midterm II
Thursday November 12th, 2009
5:00 5:50 pm
LAST Name:
SOLUTIONS
First Name:
Signature:
sh is
ar stu
ed d
vi y re
aC s
o
ou urc
rs e
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Penn ID:
Section (circle one):
Durian-10am
Devlin-11am
This is a 50-minute
Syllabus for Physics 101-601:
Classical Physics
Fall 2014
Instructor: Prof. Peter Allen
Telephone: 215-898-5952
Lectures: MW 6 PM - 8 PM
Office: DRL 2C1
email: [email protected]
Office Hours: MW 4:45 PM - 5:45 PM
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Physics 101 Midterm II
Professor Devlin
Thursday March 21st, 2013
5:00 5:50 pm
LAST Name:
First Name:
My signature below certifies that I have complied with the University of Pennsylvania's Code of
Academic Integrity in completing this examina
Mean free path:
P
N2
A collision happens when two particles come
within a distance of d=r1+r2. If we assume r1=r2
then d is the diameter of the diffusing molecule.
d=r1+r2
As the particle moves, it will collide with any particle contained in
a cylinder of
Physics 101, May 2014
FINAL EXAM
TOTAL 100 points.
PRINT YOUR NAME _
1. A ball is thrown from the window of a building and
strikes the ground 5 seconds later. The ball is given an
initial velocity vo = 8 m/s at an angle of 30 degrees
above the horizontal.
Solutions to Physics 101 Final Examination 12/19/06
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aC s
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The average on this exam was 138 with a standard deviation of 34. The highest score was 199 and
the lowest score was 24.
#1 (25 points)
A w
Solutions to Physics 101 Midterm #1 10/5/06
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The average on this exam was 75 with a standard deviation of 18. The highest score was 100 and
the lowest score was 23.
Th
#1 (33 points) A river f
Ch 2 Answers
# 25, 29, 36, 38, 48, 49, 52, 53, 54, 82.
25.For the baseball, 0 = 0, x x0 = 3.5 m, and the final speed of the baseball (during the throwing motion) is
= 43 m/s. The acceleration is found from Eq. 211c.
2 = 02 + 2a ( x x0 ) a =
29.
2 02
2(