' Opposite
' deocer
hwo-ren use
W - measurement of triangles
based 0?? ocm-e LS @
Trigonometric Ratio a ratio of the lengths of two sides of a triangle.
Sine (sin), Cosine (cos) and Tangent (tan) are the g basic ratios
53 c5 T3
, opposite adj
1 __WHQMW._H#WW
E3. Solve the triangle (SSA - One Triangle) " The ambiguous Case
E4. Solve the triangle (SSA - No Triangle) - The ambiguous case
N
-.
E5. Solve the triangle (SSA Two Triangles) The ambiguous case The l w -' ~ ' . . . . . . _
a f mum
Theorem 11.9 Area of a(n) CWU "
4
. E1.
X
25% .rr: m1
A c E C :9; ofa circle is the tag can bounded by 41.10 rimlg; of the circle and their
\\A\+v>lC§'P!-Ti§l! >4
méb 2 . .
Theorem 11.10Area of a(n) Q g cw. r Theorem: A = 3 0 717" , .where r IS radl
Geometm Notes 11.1 Exgloring Area and Perimeter
- ' eter is a
The mtgmqw ofa polygon is the sum of the length5 Of Its Pf? miles
4.0M mom u: g: ,m g r because the units are centimeters, meterS, IHChES, ee , r
P -
etc. Perimeters are mice: measured in
T
Geometr Notes 6.4 PrOVin uadrilaterals are Parallelo rams
Ways to prove are
Theorem 6.7: If both pairs of opposite sides of a quadrilateral are congruentr the the
quadrilateral is a parallelogram.
Theorem 6.8: If both pairs of opposite angles of
t.)
A A
(mCD+ MAB) A
1
2
I
2
\ 50 mn (MEE+ MAD)
(L: \qu 3
Theorem 10 15 If a tangent and a secant, two tangents, or two secants intersect 1n the exterror of a
Circle, then the measure of the angle formed IS half the difference of the measures of the mt