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EEL 3123  UCF Study Resources

Microelectronics 4th Neaman Chpt4
School: UCF
Course: Electronics
Microelectronics: Circuit Analysis and Design, 4th edition Chapter 4 By D. A. Neamen Problem Solutions _ Chapter 4 4.1 (a) (i) g m = 2 kn W I DQ 2 L 0.1 W W 0.5 = 2 (0.5) = 2.5 2 L L k W (ii) I DQ = n (VGSQ VTN )2 2 L 0.1 2 0. 5 = (2.5)(VG

Lecture 13_F2012
School: UCF
Course: Electrical Networks
FourierSeries(continued) Fourier Series (continued) Dr.ShadyElashhab Fall2012 Fall 2012 Application of Fourier Series: RC Circuit. Find the steady state response of the network? Solution strategy: Represent the input voltage as a sum of sinusoids using

Ch01_17
School: UCF
Course: Electrical Networks
Irwin, Basic Engineering Circuit Analysis, 10/E 1 SOLUTION: Chapter 1: Basic Concepts Problem 1.17 2 Problem 1.17 Irwin, Basic Engineering Circuit Analysis, 10/E Chapter 1: Basic concepts

Ch02_7
School: UCF
Course: Electrical Networks
Irwin, Basic Engineering Circuit Analysis, 10/E 1 SOLUTION: Chapter 2: Resistive circuits Problem 2.7

Ch02_8
School: UCF
Course: Electrical Networks
Irwin, Basic Engineering Circuit Analysis, 10/E 1 SOLUTION: Chapter 2: Resistive circuits Problem 2.8

Ch02_9
School: UCF
Course: Electrical Networks
Irwin, Basic Engineering Circuit Analysis, 10/E 1 SOLUTION: Chapter 2: Resistive circuits Problem 2.9

Ch02_44
School: UCF
Course: Electrical Networks
Irwin, Basic Engineering Circuit Analysis, 10/E 1 SOLUTION: Chapter 2: Resistive circuits Problem 2.44

Ch02_58
School: UCF
Course: Electrical Networks
Irwin, Basic Engineering Circuit Analysis, 10/E 1 SOLUTION: Chapter 2: Resistive circuits Problem 2.58

Ch02_60
School: UCF
Course: Electrical Networks
Irwin, Basic Engineering Circuit Analysis, 10/E 1 SOLUTION: Chapter 2: Resistive circuits Problem 2.60

Ch02_57
School: UCF
Course: Electrical Networks
Irwin, Basic Engineering Circuit Analysis, 10/E 1 SOLUTION: Chapter 2: Resistive circuits Problem 2.57

Ch02_71
School: UCF
Course: Electrical Networks
Irwin, Basic Engineering Circuit Analysis, 10/E 1 SOLUTION: Chapter 2: Resistive circuits Problem 2.71

Ch02_88
School: UCF
Course: Electrical Networks
Irwin, Basic Engineering Circuit Analysis, 10/E 1 SOLUTION: Chapter 2: Resistive circuits Problem 2.88 2 Problem 2.88 Irwin, Basic Engineering Circuit Analysis, 10/E Chapter 2: Resistive circuits

IRWIN 10e 4_9
School: UCF
Course: Electrical Networks
Irwin, Basic Engineering Circuit Analysis, 10/E 1 SOLUTION: Chapter 4: Operational Amplifiers Problem 4.9

Ch01_3
School: UCF
Course: Electrical Networks
Irwin, Basic Engineering Circuit Analysis, 10/E 1 SOLUTION: Chapter 1: Basic Concepts Problem 1.3

2Inverse Laplace Transform
School: UCF
Course: Electrical Networks
Given the initial condition, analysis to be , . Hence, can be determined using transient . Both and can also be determined using Laplace transform. Using KVL, we can write 1 Taking the Laplace transform yields Taking the inverse Laplace transform yields S

Lecture9_A_F2012 [Compatibility Mode]
School: UCF
Course: Electrical Networks
Lecture 9A Operational Amplifiers (Op Amps) Dr. Shady Elashhab Fall 2012 V < v0 < +V+ Operational Amplifiers (Op Amps) Ideal Op Amp Inverting Amplifier Noninverting Amplifier UnityGain Buffer Differential Amplifier CurrenttoVoltage Converter i1 = i2

Lecture 14__F12.ppt
School: UCF
Course: Electrical Networks
Fourier Transform Dr. Shady Elashhab Fall 2012 Fourier transform Fourier series representation of periodic signals enables the description of periodic functions in terms of their frequency domain attributes (amplitude and phase spectra) Fourier transfor

Lecture 12_F2012
School: UCF
Course: Electrical Networks
Fourier Series Fall 2012 Dr. Shady Elashhab Motivation for Fourier series. How does a sinusoidal voltage go through an electric network (LTI system)? Using Eulers formula Now, the question becomes But, # of harmonics is 5, 9, 25, and 100 1.2 1.2 1 1 0.8 0

Lecture 4_F2012 [Compatibility Mode]
School: UCF
Course: Electrical Networks
Lecture #4 Circuit A l i U i L l Ci it Analysis Using Laplace Transform Dr. Shady Elashhab Circuit Elements in S Domain + V R I V(s) =L [s I (s) i (0)]= s L I (s) L I0 + v V(s) R V(s)=R I(s) L V(s) I0 I(s)= + sL s i I + sL I di vL dt V + V sL + LI0 I0 s

Lecture 3_F2012 [Compatibility Mode]
School: UCF
Course: Electrical Networks
EEL 3123 Networks and Systems Lecture # 3: Inverse Laplace Transform Dr. Shady Elashhab Fall 2012 Inverse Laplace Transform Complex integrals! We are going to avoid applying the definition of Inverse Laplace Transform in this class. Example 1 Example 2 Ex

Lecture 6_F2012 [Compatibility Mode]
School: UCF
Course: Electrical Networks
STEADYSTATE SINUSOIDAL RESPONSE AND IMPUSE RESPONSE IN s DOMAINE Dr. Shady Elashhab. EXAMPLE Find the transfer function V0/Vg and determine the poles and zeros of H(s). V0 Vg V0 sV0 + 6 =0 1000 250 + 0.05s 10 1000( s + 5000) V0 = 2 V 6 g s + 6000 s + 25

Lecture 7A_F2012 [Compatibility Mode]
School: UCF
Course: Electrical Networks
More examples on circuit analysis including dependent sources and Initial Conditions Example 1: Using Laplace transform methods, find v(t) assuming v(0)= 2 V Solution V0 1 V ( s) = I ( s) + s sC Initial voltage Applying KCL at the node (1) The curre

Lecture 7B_F2012 [Compatibility Mode]
School: UCF
Course: Electrical Networks
Introduction to Frequency Selective Circuits (Filters) Dr. Shady Elashhab Chapter 14: Introduction to Frequency Selective Circuits In this chapter, we analyze the effect of varying source frequency on circuit voltages and currents. In particular, the ci

Lecture 8_F2012 [Compatibility Mode]
School: UCF
Course: Electrical Networks
Lecture 8 Introduction to Frequency Selective Circuits (Filters) Dr. Shady Elashhab Fall 2012 From our previous lecture, Two lowpass filters, the series RL and the series RC, From our previous lecture, Two highpass filters, the series RL and the series

3Circuit Analysis Using Laplace Transform (1)
School: UCF
Course: Electrical Networks
Resistor in the Frequency Domain In the time domain, Ohms Law specifies that . Taking the Laplace Transform of both sides yields The quantity unit ohms . is the impedance in the frequency domain, , with the 1 Inductor in the Frequency Domain In the time d

4Transfer Function, Convolution And SteadyState Response (1)
School: UCF
Course: Electrical Networks
Transfer Function Using voltage divider law, we can write 1 = = 1 1 + + = = where is the transfer function of the circuit, defined as the ratio of the output to the input. 1 We can have other quantities as either the input or output. For example

1Properties And Concepts Of Laplace Transform
School: UCF
Course: Electrical Networks
The Laplace Transform The Laplace transform can be used to solve a system of differential equations. It converts integral and differential equations into algebraic equations, and hence, simplifies the solution for an unknown quantity to the manipulation o

IRWIN 10e 4_11
School: UCF
Course: Electrical Networks
Irwin, Basic Engineering Circuit Analysis, 10/E 1 SOLUTION: Chapter 4: Operational Amplifiers Problem 4.11

IRWIN 10e 4_8
School: UCF
Course: Electrical Networks
Irwin, Basic Engineering Circuit Analysis, 10/E 1 SOLUTION: Chapter 4: Operational Amplifiers Problem 4.8

Ch02_65
School: UCF
Course: Electrical Networks
Irwin, Basic Engineering Circuit Analysis, 10/E 1 SOLUTION: Chapter 2: Resistive circuits Problem 2.65 2 Problem 2.65 Irwin, Basic Engineering Circuit Analysis, 10/E Chapter 2: Resistive circuits Irwin, Basic Engineering Circuit Analysis, 10/E Chapter 2:

IRWIN 10e 3_4
School: UCF
Course: Electrical Networks
Irwin, Basic Engineering Circuit Analysis, 10/E 1 SOLUTION: Chapter 3: Nodal and Loop Analysis Techniques Problem 3.4

IRWIN 10e 3_14
School: UCF
Course: Electrical Networks
Irwin, Basic Engineering Circuit Analysis, 10/E 1 SOLUTION: Chapter 3: Nodal and Loop Analysis Techniques Problem 3.14

IRWIN 10e 3_6
School: UCF
Course: Electrical Networks
Irwin, Basic Engineering Circuit Analysis, 10/E 1 SOLUTION: Chapter 3: Nodal and Loop Analysis Techniques Problem 3.6 2 Problem 3.6 Irwin, Basic Engineering Circuit Analysis, 10/E Chapter 3: Nodal and Loop Analysis Techniques

IRWIN 10e 3_11
School: UCF
Course: Electrical Networks
Irwin, Basic Engineering Circuit Analysis, 10/E 1 SOLUTION: Chapter 3: Nodal and Loop Analysis Techniques Problem 3.11 2 Problem 3.11 Irwin, Basic Engineering Circuit Analysis, 10/E Chapter 3: Nodal and Loop Analysis Techniques

Ch02_110
School: UCF
Course: Electrical Networks
Irwin, Basic Engineering Circuit Analysis, 10/E 1 SOLUTION: Chapter 2: Resistive circuits Problem 2.110 2 Problem 2.110 Irwin, Basic Engineering Circuit Analysis, 10/E Chapter 2: Resistive circuits Irwin, Basic Engineering Circuit Analysis, 10/E Chapter 2

IRWIN 10e 3_79
School: UCF
Course: Electrical Networks
Irwin, Basic Engineering Circuit Analysis, 10/E 1 SOLUTION: Chapter 3: Nodal and Loop Analysis Techniques Problem 3.79

IRWIN 10e 3_55
School: UCF
Course: Electrical Networks
Irwin, Basic Engineering Circuit Analysis, 10/E 1 SOLUTION: Chapter 3: Nodal and Loop Analysis Techniques Problem 3.55

IRWIN 10e 3_71
School: UCF
Course: Electrical Networks
Irwin, Basic Engineering Circuit Analysis, 10/E 1 SOLUTION: Chapter 3: Nodal and Loop Analysis Techniques Problem 3.71 2 Problem 3.71 Irwin, Basic Engineering Circuit Analysis, 10/E Chapter 3: Nodal and Loop Analysis Techniques

IRWIN 10e 3_56
School: UCF
Course: Electrical Networks
Irwin, Basic Engineering Circuit Analysis, 10/E 1 SOLUTION: Chapter 3: Nodal and Loop Analysis Techniques Problem 3.56

Ch02_51
School: UCF
Course: Electrical Networks
Irwin, Basic Engineering Circuit Analysis, 10/E 1 SOLUTION: Chapter 2: Resistive circuits Problem 2.51

Ch02_47
School: UCF
Course: Electrical Networks
Irwin, Basic Engineering Circuit Analysis, 10/E 1 SOLUTION: Chapter 2: Resistive circuits Problem 2.47

IRWIN 10e 4_14
School: UCF
Course: Electrical Networks
Irwin, Basic Engineering Circuit Analysis, 10/E 1 SOLUTION: Chapter 4: Operational Amplifiers Problem 4.14 2 Problem 4.14 Irwin, Basic Engineering Circuit Analysis, 10/E Chapter 4: Operational Amplifiers

IRWIN 10e 4_17
School: UCF
Course: Electrical Networks
Irwin, Basic Engineering Circuit Analysis, 10/E 1 SOLUTION: Chapter 4: Operational Amplifiers Problem 4.17

Ch01_12
School: UCF
Course: Electrical Networks
Irwin, Basic Engineering Circuit Analysis, 10/E 1 SOLUTION: Chapter 1: Basic Concepts Problem 1.12

Ch01_9
School: UCF
Course: Electrical Networks
Irwin, Basic Engineering Circuit Analysis, 10/E 1 SOLUTION: Chapter 1: Basic Concepts Problem 1.9

Ch01_29
School: UCF
Course: Electrical Networks
Irwin, Basic Engineering Circuit Analysis, 10/E 1 < SOLUTION: Chapter 1: Basic Concepts Problem 1.29

Ch01_39
School: UCF
Course: Electrical Networks
Irwin, Basic Engineering Circuit Analysis, 10/E 1 SOLUTION: Chapter 1: Basic Concepts Problem 1.39

Ch01_19
School: UCF
Course: Electrical Networks
Irwin, Basic Engineering Circuit Analysis, 10/E 1 SOLUTION: Chapter 1: Basic Concepts Problem 1.19 2 Problem 1.19 Irwin, Basic Engineering Circuit Analysis, 10/E Chapter 1: Basic concepts Irwin, Basic Engineering Circuit Analysis, 10/E Chapter 1: Basic Co

Ch01_43
School: UCF
Course: Electrical Networks
Irwin, Basic Engineering Circuit Analysis, 10/E 1 SOLUTION: Chapter 1: Basic Concepts Problem 1.43

Ch02_10
School: UCF
Course: Electrical Networks
Irwin, Basic Engineering Circuit Analysis, 10/E 1 SOLUTION: Chapter 2: Resistive circuits Problem 2.10

Ch02_13
School: UCF
Course: Electrical Networks
Irwin, Basic Engineering Circuit Analysis, 10/E 1 SOLUTION: Chapter 2: Resistive circuits Problem 2.13

Ch02_26
School: UCF
Course: Electrical Networks
Irwin, Basic Engineering Circuit Analysis, 10/E 1 SOLUTION: Chapter 2: Resistive circuits Problem 2.26

IRWIN 10e 3_84
School: UCF
Course: Electrical Networks
Irwin, Basic Engineering Circuit Analysis, 10/E 1 SOLUTION: Chapter 3: Nodal and Loop Analysis Techniques Problem 3.84 2 Problem 3.84 Irwin, Basic Engineering Circuit Analysis, 10/E Chapter 3: Nodal and Loop Analysis Techniques

Microelectronics 4th Neaman Chpt2
School: UCF
Course: Electronics
Microelectronics: Circuit Analysis and Design, 4th edition Chapter 2 By D. A. Neamen Problem Solutions _ Chapter 2 2.1 1000 (a) For I > 0.6 V, O = ( I 0.6 ) 1020 For I < 0.6 V, O = 0 1000 (b) (ii) O = 0 = [10 sin ( t )1 0.6] 1020 0. 6 Then sin (

Microelectronics 4th Neaman Chpt3
School: UCF
Course: Electronics
Microelectronics: Circuit Analysis and Design, 4th edition Chapter 3 By D. A. Neamen Problem Solutions _ Chapter 3 3.1 Kn = k n W 120 10 2 = 0.75 mA/V 2L 2 0. 8 (a) (i) I D = 0 [ ] = (0.75)[2(2 0.4)(0.1) (0.1) ] = 0.2325 mA = (0.75)[2(3 0.4)(0.1) (0.1)

Microelectronics 4th Neaman Chpt6
School: UCF
Course: Electronics
Microelectronics: Circuit Analysis and Design, 4th edition Chapter 6 By D. A. Neamen Problem Solutions _ Chapter 6 6.1 I CQ (a) (i) g m = VT VT r = ro = I CQ = = 0.5 = 19.23 mA/V 0.026 (180)(0.026) = 9.36 k 0.5 V A 150 = = 300 k I CQ 0.5 2 = 76.92 mA/V

Microelectronics 4th Neaman Chpt7
School: UCF
Course: Electronics
Microelectronics: Circuit Analysis and Design, 4th edition Chapter 7 By D. A. Neamen Problem Solutions _ Chapter 7 7.1 a. T ( s) = T (s) = V0 ( s ) Vi ( s ) = 1/ ( sC1 ) 1/ ( sC1 ) + R1 1 1 + sR1C1 b. fH = 1 1 = f H = 159 Hz 3 2 R1C1 2 (10 )(106 ) c. V0

Fourier
School: UCF
Course: Networks And Systems
! " # ! ! $%& ' () , = * $ / ) () % = = % = = +% % +% < < % % ( ) ( % ) ( ) = ( ) = $ , % % +% = % ) ( ) % ( ) = ( ) % % % ( ( % % + % () () ) + + % ( ( % % ) ) ( ) ( % ) % ( % ) % % ( ) % % = < < + < < + & = = + = + % = + ) = ( + = %< < < < <

MT1Fall05
School: UCF
Course: Networks And Systems
! " #$ %& '()*+% ,  $., = $*, + = + + + + ! # "# $ $% %& % # ' $ , () . # #$ (#)% # () ! %* +" /% % 0% # + * 1 2 &

MT2Fall05
School: UCF
Course: Networks And Systems
! " # % $ &'( )(* + , ! # &+ " $ ! %& '( ) *%& '(+ , + ) $ $ ! + % . ,#) ) = + . /0%( 1&/ $%2+ 34( 1&/ $+ & / + & + & & . ) , ) )+ , ) + %. 0 0*  *

SolMT2EEL3123.01
School: UCF
Course: Networks And Systems
!" # $ &,+ &+ &.+ % & ' () * + ! ! "#$ %& '(% ) * , ( = ( ! #' +  . ' +/. ' + = + + = +( / +(/ . / ' += 0 & + + +(/ / ( / + +/ / +(/ ( + 1 + ( 2 & 3 4 , $ & 3  54 , $ 2 2 # ' 7 2 2 6 54 4 2 2 2 2 + 2 2 , , # 2" 5 = = =% = 4 = (/ = = = = (= = ( %

SolMT2EEL3123.02
School: UCF
Course: Networks And Systems
!" # $ &+* &,* &* % & '( ) * ! ! "#$ %& '(% ) * , ! #' +  . ' +/. ' + . ' += + 0 & ( + + +( ( + , $ & 3  54 , 2 $ $ 6 2 2 2 2 # , , + 2 54 2 + 1 & 3 4 $ +(/ / 2" + 4 7 2 2 2 2 22 ( = = =% = 4 = (/ = = = = (= = ( % : = = / = ( '( % : ( = ( % :( 9

SolMT1Fall05
School: UCF
Course: Networks And Systems
! = cfw_ = = = cfw_ > = + cfw_ = = = + "! ! = + + ! = + + + + + + = + = + #= +# cfw_ =# + % ( )* + + = = ! + + + $#+ "! + = # = = = + ! + = + " # +# = + + + + # +# =# = =" &' ( ) *+ * ( ,  )( ) * = = + + + + = = + + + + = . . = # . . / )  01 5 4 ( *

SolMT2Fall05
School: UCF
Course: Networks And Systems
! " # % $ &'( )(* + , ! # &+ " $ ! %& '( ) *%& '(+ , + ) $ $ ! + % . ( .(* /*(01( 2 = %& = * = = *%& = /3+1 = * * = 34 8595 .&* : , 34 )5 %6 %.7 = %0&+2 = = * = = +&/ /3+1 * &+ & 1 = = 1+/0 %0&+2 &+ & 1 + = /3+1 = %0&+2 =

Microelectronics 4th Neaman Chpt1
School: UCF
Course: Electronics
Microelectronics: Circuit Analysis and Design, 4th edition Chapter 1 By D. A. Neamen Problem Solutions _ Chapter 1 1.1 ni = BT 3 / 2 e (a) Silicon Eg / 2 kT 1.1 exp 2 ( 86 106 ) ( 250 ) 19 = 2.067 10 exp [ 25.58] ni = 1.61 108 cm 3 (i) ni = ( 5.23 101

Microelectronics 4th Neaman Chpt5
School: UCF
Course: Electronics
Microelectronics: Circuit Analysis and Design, 4th edition Chapter 5 By D. A. Neamen Problem Solutions _ Chapter 5 5.1 (a) i E = (1 + )i B 1 + = 325 = 116 = 115 2.8 115 = = 0.9914 1 + 116 iC = i E i B = 325 2.8 = 322 A = (b) 1 + = 1.80 = 90 = 89 0.020 89

Electric Networks Lab Manual
School: UCF
LABORATORY MANUAL EEL 3123 NETWORKS AND SYSTEMS DEPARTMENT OF ELECTRICAL AND COMPUTER ENGINEERING UNIVERSITY OF CENTRAL FLORIDA Prepared by Dr. PARVEEN WAHID Ms. YA SHEN FALL 2011 PREFACE This lab manual for EEL 3123  Networks and Systems is an updated v

Finalexamsample1
School: UCF
Course: Networks And Systems
EEL 3123C TEST 3  PART A  MANDATORY DURATION: 60 minutes Dec 7, 2007 1. The voltage across a 50 resistor is v (t) = 4t exp ( jtj) : What is the total energy dissipated in the resistor? What percentage of the total energy dissipated in the resistor can b

Midterm2samplequestion
School: UCF
Course: Networks And Systems
EEL 3123C TEST 3  PART A  MANDATORY DURATION: 60 minutes 1. The current through a 50 resistor is i (t) = 4t exp ( t) u (t) : What percentage of the total energy dissipated in the resistor can be associated p with the the frequency band 0 ! 3 rad/s? (50)

HW1_fall_2010
School: UCF
Course: Networks And Systems
Networks and Systems EEL 3123, Section 1 HOMEWORK 1 Assigned Aug 31, 2010, Due on Sep 7, 2010 Covers Chapter 12. If there are doubts, you are welcome to see me and discuss your problems. Your notes and the textbook should be ample material to solve these

HW2_Fall_2010
School: UCF
Course: Networks And Systems
Networks and Systems EEL 3123, Section 1 HOMEWORK 2 Assigned Sep 9, 2010 Due on Sep 16, 2010 Covers Chapter 13. Topics include circuit analysis using Laplace transform. If there are doubts, you are welcome to see me and discuss your problems. Your notes a

HW3_Fall_2010
School: UCF
Course: Networks And Systems
Networks and Systems EEL 3123, Section 1 HOMEWORK 3 Assigned Sep 23, 2010 Due on Sep 30, 2010 Covers Chapter 14. Topics include low pass, high pass, band pass and band reject filter design. If there are doubts, you are welcome to see me and discuss your p

HW4_Fall_2010
School: UCF
Course: Networks And Systems
Networks and Systems EEL 3123, Section 1 HOMEWORK 4 Assigned Oct 21, 2010 Due in class on Oct 28, 2010 Covers Chapter 16. If there are doubts, you are welcome to see me and discuss your problems. Your notes and the textbook should be ample material to sol

HW5_Fall_2010
School: UCF
Course: Networks And Systems
Networks and Systems EEL 3123, Section 1 HOMEWORK 5 Assigned November 10, 2010, Due in class on Nov 23, 2010 Covers Chapter 17 & 18. If there are doubts, you are welcome to see me and discuss your problems. Your notes and the textbook should be ample mate

AnsHW2
School: UCF
Course: Networks And Systems
+ = = + = cfw_ = + + = = + + cfw_ + + = = cfw_ + = = cfw_ + = + + cfw_+ = + + + + + + + !" $ % ! = & cfw_ ' !" ( $ % ! * = = cfw_ + !" & + = # ' + ) ' & = *& + !" + +

SolHW1
School: UCF
Course: Networks And Systems
Solutions to HW 1 1. Find the Laplace Transform of the function f (t ) = te t (t 1) cfw_ Lcfw_ f (t ) = L te t (t 1) = te t (t 1)e st dt 0 t g (t ) = te e therefore st Lcfw_ f (t ) = g (t ) (t 1)dt 0 t2 Shifting property f (t ) (t t o )dt = f (t o ), t1

Exam #1 Material Review
School: UCF
Course: Electrical Networks
Exam 1 Review Chapter 12Know how to: (1) Find a single expression for an arbitrary waveform. (2) Apply the translation in time theorem of the Laplace transform. (3) Use partial fractions and the Laplace transform tables to either find the inverse Laplace

Test #1 Solutions
School: UCF
Course: Electrical Networks
EEL 3123C: Networks and Systems, 9/19/2012 MIDTERM EXAM # 1 9:00 to 11:30 AM Student Name: . Problem 1(15 pts) 6(t 5) a) Find the Laplace transform of f (t ) = 30e u (t 5) t b) Given the following differential equation: y (t ) + 2 y (t ) + y (t ) e Find Y

Homework 1 Solutions
School: UCF
Course: Electrical Networks
EEL 3123C: Networks and Systems Solution of HW # 1, Fall 2012 Solve the following problems Problem 12.2 (a) and (b) Problem 12.14 (a) and (c) Problem 12.17 (c) Problem 12.19 (a) Problem 12.20

Homework 2 Solutions
School: UCF
Course: Electrical Networks
EEL 3123C: Networks and Systems Solution of HW # 2, Fall 2012 Solve the following problems Problem 12.28 Problem 12.40 [b] Problem 12.42 [c] Problem 12.43 [c]

Homework 3 Solutions
School: UCF
Course: Electrical Networks
EEL 3123C: Networks and Systems Solution of HW # 3, Fall 2012

Homework 4 Solutions
School: UCF
Course: Electrical Networks
EEL 3123C: Networks and Systems Solution of HW # 4, Fall 2012 Problem 14.10 Problem 14.13 Problem 14.20 \ Problem 14.22 Problem 14.36

Homework 6 Solutions
School: UCF
Course: Electrical Networks
EEL 3123C: Networks and Systems Solution of HW # 6, Fall 2012 Problem 16.1 Problem 16.3(Figure b) Problem 16.28 Problem 16.29 Problem 16.30 (a) Problem 16.37

Homework 5 Solutions
School: UCF
Course: Electrical Networks
EEL 3123C: Networks and Systems Solution of HW # 5, Fall 2012 Problem 15.1 Problem 15.3 Problem 15.4 Problem 15.10 Problem 15.15 Problem 15.28

Lecture 1_F2012 [Compatibility Mode]
School: UCF
Course: Electrical Networks
EEL 3123 Networks and Systems Lecture # 1 Dr. Shady Elashhab Fall 2012 Welcome to EEL 3123 Instructor: Office: Email: Office Hours: Dr. Dr Shady Elashhab PhD Elashhab, PhD. VW 11 258 shady.elashhab@ucf.edu y @ Wednesdays 12:00 p.m. to 12:55 p.m. or by ap

Lecture 2_F2012 [Compatibility Mode]
School: UCF
Course: Electrical Networks
EEL 3123 Networks and Systems Lecture # 2: Laplace Transform Dr. Shady Elashhab Fall 2012 Some useful Functions 1 A unit step function: A step function is defined as: Notice that: Shifted Step Function A step that occurs at t = a is expressed as: A step

Lecture9_B_F2012 [Compatibility Mode]
School: UCF
Course: Electrical Networks
Lecture 9B Active Filters Dr. Shady Elashhab Fall 2012 DISADVANTAGES OF PASSIVE FILTER CIRCUITS Passive filter circuits consisting of resistors, inductors, and capacitors are incapable of amplification, because the output magnitude does not exceed the in

Homework Sets
School: UCF
Course: Electrical Networks
EEL 3123 HOMEWORK1 Chapter 12: Laplace Transforms 12: Laplace Transforms 13: Applic of L.T. 13: Applic of L.T. 14: Passive Filters 15: Active Filters 14: Passive Filters Bode Diagrams Nyquist Diagrams 16: Fourier Series 16: Fourier Series 18: 2Port Netwo

Homework #9
School: UCF
Course: Electrical Networks
HW #9: THE NYQUIST DIAGRAM Draw the Nyquist diagram on scaled axes for each of the following transfer functions. Indicate their direction. Provide sample calculations for 3 frequencies. Suggestion: As shown in class, you can: (1) use MATLAB to run a frequ

Homework #8
School: UCF
Course: Electrical Networks
HW #8: STRAIGHTLINE BODE DIAGRAMS (MAGNITUDE AND PHASE) Sketch the straightline Bode diagrams of magnitude and phase for the following transfer functions below. Note: The first step is to place the transfer function in standard form. The transfer functi

SolHW2
School: UCF
Course: Networks And Systems
! + ! + = = = = # = + % + + # + = + + = $+ +$ = %+ + $+ + $+ $+ & = + $+ $+ = # " + % +' + $' + $% $ + $+ +$ + = + $ + + $ = + " + = = +$ + + = +$ = # +$ % +# = + = + + +$ + $ = = +$ + + = $+ = = + $+ + $+ # = +$ $ + # + $+ +& + $ = + $+

SolHW3
School: UCF
Course: Networks And Systems
=! ! = ! + !+ ! = ! + = += + + + ! + + ]= =[ +! cfw_ = # + + + = $% + + = + ! != + + + + + + ! + +! + = +! + + + = ] =! = ! = + + +! ! =! = +! [ = += = != + = ! ! + + ! cfw_! + ! = + ! + = = = ! + + ! + +! + !" + + + +! + =! + =! + = +! + " & ' (

SolHW4
School: UCF
Course: Networks And Systems
! "# ' $% & " $ () & ' , $ &$ $) '  ) . " / 01 ' " $* $* $* $ 20 $ & $ $+ + $ &$ $) ) 0$ 3 3 $ * () & ' $* , $ &$ $) ' $*  ) . " # 1 $ " $* / 1 / $ & $ $+ + $ &$ $) ) 0 / 4 * 5 ' 6 1 * ) 1 ) $ $ , + 4 * $ ) /1 * 8 ) .7 . 7 64 *) / = = + + =/ = = / =