1. The first Bohrs radius (for electron in hydrogen atom in
s
the ground state):
the
a0 =
2
mke
2
0.0529nm
2. The ground energy level in hydrogen atom:
2.
E0 =
mk 2e 4
2 2
1 ke 2
=
13.6eV
2 a0
3. The energy levels, orbit radius, kinetic energy, linear,
PHY 3101
Exam #1
Name_ID_
1. A heavy version of the electron, called the muon, differs from the
electron only in that its mass is m 207me. (a) What is the radius of the
muonic hydrogen atom in its ground state? (b) Calculate the
wavelength of radiation em
Review Exam #2
1. A monochromatic beam of light is absorbed by a collection of groundstate hydrogen atoms in such a way that six different wavelengths are
observed when the hydrogen relaxes back to the ground state.
(a) What is the wavelength of the incid
PHY 3101
Practice Exam #1
Name_ID_
#1 _
#2 _
#3 _
#4 _
Total: _
1. Suzanne observes two light pulses to be emitted from the same location,
but separated in time by 3.00 s. Mark sees the emission of the same two
pulses separated in time by 9.00 s. (a) How
Single electron atom - Total angular momentum
Today
Orbital plus Spin part
Importance classically
Ch. 8 Atomic Physics
J L S
Time derivative of J equals torque
Coupling of angular momenta
Hydrogen atom - fine structure
Effect of external magnetic fi
Thermodynamics: Concepts
Ch. 9 Statistical Physics
Thermodynamics is the study of thermal processes in
macroscopic systems.
It is usually assumed that a classical thermodynamic system is
a continuum, with properties that vary smoothly from point to
poin
Heisenberg Uncertainty Principle
Any wave:
A narrow wave packet in space must
contain a large range of wavenumbers
A wave packet localized in time must
contain a large range of frequencies
Review for Exam 2
Ch 5 Wave Properties of Matter and QM I
Ch 6 Q
Solids
Today
Solids consist of many atoms bonded together
Many possible ways to combine atomic
wavefunctions to get charge density with correct
symmetry.
All these quantum states have slightly different
energies.
Solid is similar to atom or molecule,
Schrdinger equation for Hydrogen atom and solution
Today
Ch. 7 Hydrogen Atom
is reduced mass
Magnetic effects on atomic spectra (Zeeman)
e
e-
+
V(r )
use spherical coordinates r, ,
Stern - Gerlach experiment
e2
4o r
1 2 2
1 2
2 1
E
V ( r )
Schrdinger equation for Hydrogen atom and solution
Today
Ch. 7
The Hydrogen Atom
2 d2
d2
d2
e2
2 2 2 ( r )
( r ) E ( r )
dx
2
dy
dz
4o r
use spherical coordinates r, ,
2
m
1 d
f
sin 1 2 f 0
sin d
sin
Energy levels and electron probabiliti
Finite Square Well: The particle penetrates the walls !
Today
Ch. 6
The penetration depth is the distance outside
the potential well where the probability
significantly decreases. It is given by
Quantum Mechanics II
(The Schrdinger Equation)
x
Simple Har
Tunneling wave function
Today
Ch. 6
Quantum Mechanics II
Alpha Decay
2m(V0 E )
Isotope effect
3-D Infinite Potential Well
Ch. 7
The Hydrogen Atom
This violation of classical physics is allowed by the uncertainty
principle. The particle can violate class
Wave Motion
Today
Ch. 5
Frequency and Wavelength
Frequency f, wavelength ,
and speed of propagation c
of any wave are related
Quantum Mechanics I
cf
Wave properties of matter
Uncertainty principle
Wavefunction and probability
Particle in a box
spatial va
Franck-Hertz Experiment
Today
Ch. 4
Bohr Atom
Franck-Hertz Experiment
Ch. 5
Wave Properties of Matter and QM 1
X-Ray Scattering
Shows the excitation of atoms to discrete energy levels and is
consistent with the results suggested by line spectra
Mercur
Today
Exam 1
Wednesday, Sep 24, 12:00pm, ENG2 102
Ch. 4
covers Chpts. 1 - 4.5
Bohr model - reduced mass approximation
The Structure of the Atom
Review for Exam 1
Closed book and closed notes
Provided: formula sheet
Allowed calculator (not internet enable
The Schrdinger Wave Equation
The Schrdinger wave equation in its time-dependent form
for a particle of energy E moving in a potential V in one
dimension is:
Today
Ch. 6
Quantum Mechanics II
(The Schrdinger Equation)
i
Infinite Square-Well
Operators and Ex
PHY 3101
Q1
Total
Old Final Exam
Time: 120 minutes
Q2
Q3
Q4
Name: _
P1
P2
Student ID:_ _
P3
P4
P5
P6
This is a closed book - closed notes exam. A formula sheet is provided. There are 4 questions worth 10
points each and 6 problems worth 150 points.
Clearl
Quantum Mechanics - The Copenhagen Interpretation
Today
1. A system is completely described by a wave function , which
Quantum mechanics - Copenhagen interpretation
Superposition of quantum states
represents an observer's knowledge of the system. (Heisenb
Superconducting transition temperature over the years
Today
Ch. 10, 11 Solid State Physics
Superconductors
Flux quantization
Semiconductors and devices
L26_1
afs 01fa14 L26
L26_2
afs 01fa14 L26
Critical magnetic field - phase diagram
Ideal Diamagnet:
PHY 3101 Exam 1 Spring 2015
Q1 Total 7: Time: 70 minutes
Q2
P1
P2 Name:
P3
P4 . Student ID:
(442/
This is a closed book - closed notes exam. A formula sheet is provided.
Clearly show everything that you do with the help of figures, graphs, equations, etc.