PHY-2053CA001, College Physics-I, Summer 2017
Instructor: Dr. Bhattacharya
Quiz #7
v I . '
NAME: K Ef [ e g 't' Ftafwa A PID:
Useful informations 2
Momentum P = mv Impulse J = FAt Kinetic energy = mvz 2 gm
1. What is the magnitude of the total impul
PHY-2053C-A001, College Physics-I, Summer 2017
Instructor: Dr. Bhattacharya
Quiz #5
NAME: K EY Ecfw_ Fomm A PID:
Useful informations
Newtons 2nd law: F 2 ma Acceleration due to gravity 9 = G 7%; weight W = mg
Gravitational force F : Gmrmf G = 6.674 X
PHY-2053C-A001, College Physics-I, Summer 2017
Instructor: Dr. Bhattacharya
Quiz #6
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/
Useful informations
Newtons 2nd law: F = ma Acceleration due to gravity 9 = 0%; weight W = mg
Gravitational force F = G W? 1) = 7M T = 3M r
PHY-2053C-A001, College Physics-I, Summer 2017
Instructor: Dr. Bhattacharya
Quiz #2 KEY Test Form A
NAME:
Useful informations: v = v0 + at
PID:
x = x0 + v0 t + 12 at2
v 2 = v02 + 2a(x x0 )
1. Three runners start at the same place. Shaun runs 4.0 km due ea
GENERAL PHYSICS I
Exam 1
1. (25 pts) A soccer ball is kicked with initial speed v0 and initial angle 0 relative to
the horizontal ground. Prove that the trajectory that the ball will follow is a concave
parabola.
known
unknown
v 0 , 0
trajectory = concave
16 A O. 300-kg puck,1mtlally at. reSt on Sa honzontal frichonless Surface, is struck by a 0. 200- -kg
S'puCkSS moving 1mt1ally along the x axis with a speed of 2 00 m/s After the collision, the 0. 200-S ' '
5. 1 kg puck has a speed Of 1 00 m/S at an angl
PHY 2048: useful equations
Instructor: Dr. Saiful I. Khondaker
x = x f xi average speed: distance/time
x x f xi
Average velocity and acceleration: vaverage = t = t
Displacement:
vx = lim
Instantaneous velocity and acceleration:
Kinematic equations:
t 0
ax
Rigid Objects in Equilibrium
Rigid Objects in Equilibrium
If a rigid body is in equilibrium, neither its linear motion nor its
rotational motion changes.
Reasoning Strategy
1. Select the object to which the equations for equilibrium are to be applied.
ax
1. A puck on a frictionless air hockey table has a mass of 5.0 kg and is
attached to a cord passing through a hole in the surface as in the
figure. The puck is revolving at a distance 2.0 m from the hole with an
angular velocity of 3.0 rad/s. The angular
The angular coordinate
s = r
=
s
r
is in radian
2 rad = 3600
= f i
Ch 10: End of chapter
review and problems
=
=
f i
f i
lim
t 0
a= a
+a
( in rad/s )
arad
d
=
t
dt
t
d
=
t
dt
I = m i ri
i
v2
= = 2r
r
v f = vi + at
1
2
x f = xi + vi t +
f = i + i t
5/16/2017
Problem:chapter1
15. The corners of a square lie on a circle of diameter D =
0.35 m. Each side of the square has a length L. Find L.
Problem:chapter1
15. The corners of a square lie on a circle of diameter D =
0.35 m. Each side of the square has
ILD 5
Name: _
Tutorial section _
Circular motion: Checking for coherence & reconciling
I. Discontinued circular motion: Reconciling
Dr. _ will roll a ball along a curved track, as pictured here. The dotted line
represents the balls path of motion while it
quiz
b)
t = 3.00 s = 5.00 + 30.0 + 18.0 = 53.0 rad
d
=
=
10.0 + 4.00t
=t 3.00
=
s
t 3.00 s
dt t = 3.00 s
t = 3.00 s
=
INERTIA IS IN UNITS kgm2
Angular displacement
=t-i
axis of rotation
=f - i=(2/3)rad
arclength
Sp= x rp
Sp= x rp
=s/r
Angular Speed
=
t
A 200-g block is pressed against a spring of force
constant 1.40 kN/m until the block compresses the
spring 10.0 cm. The spring rests at the bottom of a
ramp inclined at 60.0 to the horizontal. Using energy
considerations, determine how far up the incline
EXAM #3: SPRING SEMESTER 2015 PHY2049
21 April 2016 Instructor: Enrique del Barco
NAME
Read carefully the next notes:
a. For problems: Include the workout of the problem in the space below the Question. A correct
answer without the development of the solu
Question 6 2 pts
The sphere will pass the friction pad for n times before it stops on the pad when crossing it for the n + 1 time. Given that
m : 2.31:9,9 9.8,: 0.3, 91 50, 92 _ 30, I; 0.5m, lg : 2.5m, d : 0.2m,nd n, the numberoftimes the sphere complet
A small mass In is tied to a string of length I. The mass and the string were released from static at an angle .9
and allowed to swing freely. Ignoring air resistance, what is the velocity of the mass as it passes through the
lowest point? (Le. when the s
Question 4 2 pts
The purpose of this problem is to nd the minimum height required for the roller coaster car to pass the
highest point on the circular loop without falling off. Assuming the track is frictionless and that the car's wheels
do not grab o
At any point between the initial push and the system reaching equilibrium, when the spring is being extended
by a distance AI: what is the velocity of the block 1;, in terms of m: 1'0: k. and m ?
O k
v v3 5A1?
O k
v = .-'_\:I'2
m
0 1
v = 133+ k._\.r2
The same mass was released with an initial velocity 11 from and initial angle 6'1. What is the maximum angle 32 that it is able to reach on the othef side of
the swing?
O
62 = arccos (cos [6])
O
O I got a different answer
vi
I
92 = arccos ([1 COS (91)
2
Question 5 3 pts
Find the minimum launch height h that wilt allow the car to pass the top of the circular track without falling
down.
Oh=4R
O h=2.5R
Oh=3R
Qh=3.5R
O h=4.5R
O h=2R