PHY4604 Fall 2007
Problem Set 5 Solutions
PHY 4604 Problem Set #5 Solutions
Problem 1 (20 points): Use separation of variables in Cartesian coordinates to solve the infinite
cubical well (or particle
PHY4604 Fall 2006
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PHY 4604 Exam 1 Solutions
(Total Points = 100)
Problem 1 (20 points): Circle true or false for following (2 point each).
(a) (True or False) One of the breakthroughs that
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Free-Particle Spinors (p 0)
Free-Particle Solutions: In the Dirac-Pauli representation and p 0 the free
particle equation
rr
r
r
r
H op u ( p ) = c p + mc 2 u ( p ) = Eu ( p ) .
be
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Dirac Bracket Notation (1)
It is very convenient to make the following definitions
< 2 | 1 >
*
2
( x, t ) 1 ( x, t ) dx ,
and
< 2 | O | 1 >
Like (x,t)!
Like (x,t)!
*
2
( x, t )Oop
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Hadrons + Baryon Octet
(JP = + fermions, B = 1, Ch = 0, Bo = 0, To = 0)
Symbol
Name
+
0
p
n
0
Sigma
Mass
MeV
1189
Sigma
1193
Sigma
1189
Proton
Neutron
Cascade
938
940
1315
Cascade
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Hermitian Operators
Operators: Operators acting on a function maps it into another function.
The following are examples of operators:
Oop f ( x ) = f ( x ) + x 2
Oop f ( x ) = [ f
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Hadrons PseudoScalar Meson Nonet
(JP = 0- bosons, B = 0, Ch = 0, Bo = 0, To = 0)
Y = B + S +Ch +Bo + To
Symbol
Name
+
0
pion
Mass
MeV
140
pion
135
K+
K0
K0bar
K
pion
140
kaon
494
k
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Useful Math
Trigonometric Relations:
sin( A B ) = sin A cos B cos A sin B
cos( A B ) = cos A cos B m sin A sin B
2 cos A cos B = cos( A + B ) + cos( A B )
2 sin A sin B = cos( A +
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The Infinite Square Well (5)
Case II: Another set of solutions comes from taking A' = 0 and sin(kL/2) =
0, which implies that kL/2 = n- with n- = 1, 2, 3, . Thus,
n ( x ) = 2 B '
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The Simple Structure of our Universe
Elementary Particle: Indivisible piece of matter without internal
structure and without detectable size or shape .
.
Mass and chage located
ins
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The Harmonic Oscillator (1)
One Dimensional Simple Harmonic Oscillator: The simple harmonic
oscillator has a linear restoring force (i.e. Hookes Law spring) and
dV ( x )
Fx =
= Kx
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The Harmonic Oscillator (2)
Hamiltonian Operator: The Hamiltonian operator for the simple harmonic
oscillator is given by
1
1
2
H op =
( p x ) op + m 2 ( x 2 ) op since V ( x ) = 1
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The Harmonic Oscillator (3)
Energy Eigenvalue Equation: We are looking for solutions of the equation
Hop|En> = En|En>
where |En> are the eigenkets and En are the allowed energies (
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The Harmonic Oscillator (4)
Properties of the Ground State: We can use
hm
(a+ ) op (a ) op ) and ( x)op = h (a+ )op + (a )op )
2m
2
to calculate (x)(px) for the ground state. We se
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The Dirac Delta Function
Dirac Delta Function: The Dirac delta function is not really
a function (mathematically it is called a distribution). It
corresponds to an infinitely high,
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The Free Particle
A stationary state free particle (i.e. V(x) = 0) with energy E must satisfy
h 2 d 2 ( x )
= E ( x ) and hence ( x ) = Ae ikx
2
2m dx
where A is a constant and h 2
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Momentum-Space Wavefunctions
Change Variable: Since px = hk we can express the position-space wave
function as follows:
+
+
1
1
i ( p x x E ( p x )t ) / h
ip x / h
( x, t ) =
dp x
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Quarks & Anti-Quarks
(J = + fermions, Le = 0, L = 0, L = 0)
Generation
Mass
MeV
B
Qem
Y
I
Iz
S
Ch
5
1/3
2/3
1/3
1/2
1/2
0
0
0
0
+1/6
+1/2
10
1/3
-1/3
1/3
1/2
-1/2
0
0
0
0
+1/6
-1/2
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The Infinite Square Well (4)
One Dimensional Box
Particle in a One-Dimensional Box: Consider the
solution of
h 2 d 2 ( x )
+ V ( x ) ( x ) = E ( x ) ,
2m dx 2
where
-L/2
( x, t )
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Leptons & Anti-Leptons
(J = fermions, B = 0, Ch = 0, Bo = 0, To = 0)
Generation
Qem = Qweak + QU1
Mass
MeV
Qem
Le
L
L
QU1
Qweak
1st
~0
-1/2
~0
-1/2
+1/2
2nd
106
-1/2
-1/2
3rd
~0
-1
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Expectation Values and Differential Operators (2)
Dynamical Variables become Differential Operators:
2
2
E op = ih
( p x ) op = ih
( p x ) op = h 2 2
x
t
x
Expectation Values of Dy
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The Helicity Operator
The bonus embodied in the Dirac equation is the extra two-fold degeneracy.
For example, the two positive energy solutions
+
r
r
rr
rr
(1)
( 2)
u E > 0 ( p )
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Schrdingers Equation
The Classical Hamiltonian: Classically the energy is the sum of the kinetic
energy plus the potential energy as follows (in one dimension):
p2
E = x + V ( x) ,
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Angular Momentum and Spin
Orbital Angular Momentum: The orbital angular momentum operator is
defined as follows:
r
r
r
Lop = rop p op
It is easy to show that the orbital angular mo
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Probability Flux
Probability Flux: Look at the time dependence of the
probability that the particle lies in the region x1 x x2
j(x1,t)
j(x2,t)
P(x1,x2,t)
x2
P ( x1 , x 2 , t ) = *
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Total Angular Momentum J
We see that
r
r
rr
rr
[ H op , Lop ] = ihc ( p op ) and [ H op , S op ] = + ihc ( p op )
r
L or the spin angular
and hence neither the orbital angular mome
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Classical Mechanics vs Quantum Mechanics
Classical Mechanics: The goal of classical mechanics is to determine the
position of a particle at any given time, x(t). Once we know x(t)
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Relativistic Energy and Momentum (Summary)
Relativistic Energy:
The total relativistic energy is the sum of the kinetic energy (energy of
motion) plus the rest mass energy (RME = m