Individual project 5
1.
2. Core 2 duo 2006= 290,000,000 Core 2 duo and quad core +GPU Core
i7= 1,140,000,000
3. The actual value for core 2 duo in 2006 is 291,000,000 and core 2 duo and quad core +
GPU core i7 in2011 is 1,160,000,000. The values that were
1. C(x)=3x+2500
2. (-0.15x^2+153x)-(3x+2500)
0.15x2+150x-2500
3. -b/(2a)=500 p(500)=-0.15(500)^2*150+500-2500 Maximum profit=35,000
-b/(2a)= -150/2(-0.15) -150/-0.30=-0.3 -b/(2a)=500 To find the value of f(-b/(2a) or to find
f(500) plug x=500.
4. 10,000=-
1. C(x)=3x+2500
2. (-0.15x^2+153x)-(3x+2500)
0.15x2+150x-2500
3. -b/(2a)=500 p(500)=-0.15(500)^2*150+500-2500 Maximum profit=35,000
-b/(2a)= -150/2(-0.15) -150/-0.30=-0.3 -b/(2a)=500 To find the value of f(-b/(2a) or to find
f(500) plug x=500.
4. 10,000=-