Physics 1214, Homework #9: solutions
Answers to multiple choice questions: M1: B; M2: C.
P1: y = R
= 10d
d
R
= 0.25 mm
10
d=
d
= 4.4
There are 2 4 + 1 = 9 maxima (m = 0, 1, 2, 3, 4).
P2: d sin = m
m<
P3:
0.049
= 1.210
(700/300)2
nred = 1.201 +
b
red
= arc
Physics 1214, Homework #4: solutions
Answers to multiple choice questions: M1: C; M2: B; M3: B.
P1: (a) The particles velocity component along the x axis is v| = v cos , so the time
x
x
taken by the particle to reach the point x = 0.5 cm is t =
=
. The pa
Physics 1214, Homework #1: solutions
Answers to multiple choice questions: M1: (1) E, (2) 0; M2: E.
P1: F = 810 N
P2: For each charge,
q1 q2
q1 q3
q1 q2
q1 q3
+ k 2 cos 60 = k 2 + k 2 (1/2)
2
r
r
r
r
q1 q3
q1 q3
Fy = k 2 sin 60 = k 2 ( 3/2)
r
r
k
2
2
F =
Physics 1214, Homework #6: solutions
Answers to multiple choice questions: M1: B; M2: A.
B
=A
t
t
emf prodiced by inner and outer loops are E1 = (0.1 m)2 (0.1 T/s) = 3.14 mV and
E2 = (0.2 m)2 (0.1 T/s) = 12.57 mV, respectively. In case (a) I = (E2 E1 )/R
Physics 1214, Homework #7: solutions
Answers to multiple choice questions: M1: D; M2: D.
P1: I = 0
E
A
t
E=
V
d
C = 0
Combining, we get I = C
P2: U = P t = 100 J
A
d
V
0
= 3 109 A and B =
I = 6 1015 T
t
2r
Erms =
P
= 6.9 109 V/m
Ac0
Physics 1214, Midterm I: solutions
Answers to multiple choice questions: 1:A, 2:D, 3:B, 4:A.
E2
q
= 9 105 V/m
u = 0
= 3.58 J/m3
r2
2
q
q1
P2 Ex = k 2 k 2 cos 45 = 0
q = q1 2 2 = 2.83 C
a
( 2a)
P1 E = k
V2
P3 P = rms
R
P4 Va = k
R=
q1
q2
+k
a
2a
2
Vrms
=
Physics 1214, Homework #8: solutions
Answers to multiple choice questions: M1: B; M2: B; M3: B; M4: A,D.
P1: sin a = n sin 30 = 0.84
a = arcsin(0.84) = 57.1
sin a
= 0.5, b = 30
n
h
d = s sin(a b )
s=
cos b
= 2a = 114.2
P2: sin b =
P3: m =
P4:
s
s
1
1
1
Physics 1214, Final: answers
P1 0.545 A
P2 0.0135 A
P3 442.5 pF
P4 F1 = F3 = 2.2 104 N, F2 = 0
P5 1 107 N
P6 0.5 A
P7 7.5 cm
P8 7.5 cm
P9 11 cm
P10 1.7 V