HW 3 SOLUTION
1.
Qreforming
H1
Reformer
CH4+2H2O(L)
300K
H2
CO,CO2,H2,H2O,CH4
T=1100K
Using Equil one can calculate the mole fractions of the final stage and enthalpies of
the initial and final stages
3.15 Electrical, Optical, and Magnetic Materials and Devices
Caroline A. Ross
Fall Term, 2005
Final Exam (6 pages)
Closed book exam. Formulae and data are on the last 4 pages of the exam.
This takes 1
MASSACHESUTS ISNTITUTE OF TECHNOLOGY
FUNDAMNETALS OF ADVANCED ENEFRGY CONVERSION
SPRING 04
HOMEWORK III
DUE DATE, March 1, 2004
Most fuel cells run on pure hydrogen, or a mixture of inert gases and hy
MASSACHESUTS ISNTITUTE OF TECHNOLOGY
FUNDAMNETALS OF ADVANCED ENEFRGY CONVERSION
SPRING 04
HOMEWORK II
DUE DATE, FEBRARY 23, 2004
The rising atmospheric concentration of carbon dioxide, a product of h
1. (20 ) For the telescope conguration shown below, where lenses L1 and L2 have
focal lengths f1 , f2 , respectively, the object plane and two stops S1 and S2 of
halfsizes a1 , a2 , respectively, are
Sample Final - Solutions
Problem 1
a.
Material is multidomain.
Domains in Co line up with c-axis. Hoop shape will depend on angle between
co-axis and eld.
b.
Add a linear term mu0 H.
c.
Assume thermal
2.710 Optics
Final Exam Solutions
Spring 09
1. Consider the following system.
(a) If we position an on-axis point source at the center of the object plane (front
focal plane of L1), a collimated ray b
3.032ProblemSet3Solutions
Fall2007
Due: Startof Lecture, 10.01.07
1.
Here, we will analyze the stress states of a solid block of aluminum under various
loading conditions using the Mohrs Circle constr
Homework II Solution
(1) The efficiency in the ideal case (Carnot cycle) is:
ideal =1-(300K)/(273K+1300K)=0.81.
Then, the second law efficiency becomes
0.5
II =
= 0.62
0.81
LHV of C6H6=40141kJ/kg=31