PRACTICE PROBLEMS:
STRENGTH OF MATERIAL
CONCEPTUAL QUESTIONS
QUESTION I:
Compare the mechanical properties of a steel cable, made by twisting many thin wires together, with those
of a solid steel rod of the same diameter. What advantages does each have?
Q
DDB
Practice problems : Fluid Mechanics
PRACTICE PROBLEMS
FLUID MECHANICS
CONCEPTUAL QUESTIONS
QUESTION I (I took this question out)
QUESTION II
The gauge pressure at the bottom of a cylinder of liquid is 0.4atm . The liquid is poured into another
cylinde
DDB
A.
Practice problems : Rotation
PRACTICE PROBLEMS
MECHANICS
ROTATION
CONCEPTUAL QUESTIONS
QUESTION I
To maximize the moment of inertia of a flywheel while minimizing its weight, what shape and distribution of mass
should it have? Explain.
QUESTION II
DDB
Practice problems : Structures
PRACTICE PROBLEMS: STRUCTURES
D. STRUCTURES
CONCEPTUAL QUESTIONS
QUESTION I
What are the zero force members?
Structure
Structure
F2
PROBLEMS
QUESTION D1
The structures below are called trusses and have a pin support an
DDB
Practice problems : Equilibrium
PRACTICE PROBLEMS: EQUILIBRIUM
B. EQUILIBRIUM
CONCEPTUAL QUESTIONS
QUESTION I
Torque on the right leg: We want to find the magnitude and tension in the
hip abductor muscle T shown in the figure. The direction is given.
SOLUTIONS PROBLEM SET 5
NEWTONS LAWS WITH CIRCULAR MOTION; TORQUE
#1
the radius of rotation is
cos =
R = 1.252 12 = 0.75m
1
0.75
= 0.8 and sin =
= 0.6
1.25
1.25
y
T1
x
T1
y
T1sinq
T1cosq
x
R
T2
mg
Here cos =
q T2cosq
T2
T2sinq
mg
1.00
= 0.8
1.25
a) total
NYA PROBLEM SET # 5
Newtons Laws with Circular Motion; Torque
1.
A 4 kg block is attached to a vertical
rod by means of two strings of length
1.25 m each. When the system rotates
about the axis of the rod, the strings are
extended as in the diagram.
1.25m
NYA PROBLEM SET # 4
Newtons Laws; Friction
1.
A rifle bullet with mass 2 grams, traveling with a speed of 3,600 cm/s, strikes a
block of soft wood and penetrates to a depth of 10 cm before coming to rest.
a)
How long does it take the bullet to stop?
b)
Wh
SOLUTIONS PROBLEM SET 3
NON-UNIFORM CIRCULAR MOTION
#1
v. = 90kml h = 901000m = 25.0ml s
3600s
vI = 50kml h = 13.9ml s
I
a = ~ v = 13.9 - 25.0 = -0.7 4m I S2
t
~t
15
the magnitude of the centripetal (radial) acceleration when v = Vf = 50kmlh is
the tangen
1
2
10
A car is moving along an oval track that is
tilted or banked. The angle of the incline is 10.
Here is a close up for the car
at a single instant in time.
The car moves in a horizontal circle, denoted by the dashed red
line, meaning it stays a
Conclusion
In this experiment the objective was to have a very small percent error between the total initial
momentum and the total final momentum, because theoretically the momentum should be
conserved in a frictionless collision. However, our results we
Introduction
The purpose of this lab was to replicate the human arm through the use of levers, weights and
strings. Our goal was to determine whether the human arm was designed for speed or for
strength. This was accomplished by comparing the linear veloc
Analysis
In the first part of this lab, the acceleration vectors were obtained by subtracting
displacement vectors (x) and dividing by (t)2.
From the 5th spark to the 15th spark, the acceleration was 73.45 cm/s2 and from the 10th to
the 20th spark the acc
Abstract
Newtons second law was verified experimentally by using a glider on a frictionless air track, which was
pulled by hanging masses. The acceleration was caused by these masses pulling on the glider and was
calculated using a computer program. When
Abstract
The purpose of this experiment was to verify Newtons second law; F=ma. This law can be applied to
uniform circular motion. The centripetal force is
By plotting the centripetal force vs. the centripetal acceleration, the slope should equal the mas
Lab #2
Velocity and position using slopes and areas
By: Scott Harvey & Hudson Danielis-Garzon
Physics NYA; George Ostojic
Date experiment performed: August 27, 2010
Date Submitted: September 3, 2010
Discussion
After plotting the data from table 1, the pos
Discussion
Based on our graph, it is clear that the range of the ball increases as the height of launch
increases, due to the acceleration of gravity. We originally thought there would be a direct
linear relation between R and h. It turned out to be simil
Abstract
Newtons second law is Fnet=Mtotal a.
Therefore a= Fnet /Mtotal
For the atwood machine, Fnet is also equal to the difference in weights : (M)g
Mtotal is also equal to 2M + M
Therefore
This experiment examined the relationship between acceleration
Abstract
The objective of this lab was to experimentally determine the resultant of several vector
forces. This was obtained by finding the balancing force (equilibrant) of the weights and
changing its direction by 180 degrees, since the equilibrant is op
Charles Vlasic
0965261
203-DDC-05 ASTROPHYSICS, sec. 02
George Ostojic
22:21:25
Abstract
Introduction
Saturn is the second largest planet in the solar system, right behind Jupiter, and
ranked sixth in the distance to the sun. Saturns largest moon, Titan,