Name: _
Chemistry C3443
Fall 2013
Midterm #2
75 minutes
October 21, 2013
page 1
Instructions: (1) For some questions, you have a choice of which problem(s) to answer. For
these, cross out (X) answers you do not want counted. (2) Notice that for each quest
Teaching the Kepler laws for freshmen.
Maris van Haandel
RSG Pantarijn, Wageningen, the Netherlands
Gert Heckman
IMAPP, Radboud University, Nijmegen, the Netherlands
(Dated: November 12, 2007)
We present a natural proof of Keplers law of ellipses in terms
Keplers Laws and Gravity
Ian Morison
Observations of a supernova.
Tycho made detailed observations
of the supernova of 1572 now
called Tychos supernova.
It was initially brighter than Venus
and was visible for 18 months
before fading from view.
Tycho s
Keplers Laws
The equation of motion
We consider the motion of a point mass under the influence of a gravitational field
created by point mass that is fixed at the origin.
F IGU RE
Newtons laws give the basic equation of motion for such a system. We denote
A1 Dynamical Astronomy
Proof of Keplers first law from Newtonian dynamics
A planet orbits the Sun in an ellipse, with the Sun at one focus of the ellipse.
It would be a pity to have a course on dynamical as- as r P is the component of v perpendicular to r
Problem Set #11 Answer Key
Book Problems:
9-80: Discussed in lecture Nov 24.
Ex1.
Another way of describing square planar compounds is through consideration of only the
2
bond pairs, which renders the hybridization
Problem Set #9 Answer Key
Book Problems:
6-2: a) Xe; c) Kr; d) Ne; e Kr
6-52: 8.35 aJ
PTW Problems:
1.
Electron Affinities (EA's) for the groups 13-18 elements are below (KJ/mol; consider these as H
for X + e -
1
Chemistry 2070
Problem Set, assigned Tuesday, December 1, 2015, Answer Key
Skim Chap 26; Read 26-11 through 26-13
Problems: 23-30
23.
a.
d
10
b.
d
6
c.
d
6
d.
d
7
24.
a.
d
4
b.
d
0
c.
d
4
d.
d
0
25.
a.
Co(III), Rh(III), Ir(III)
b.
Fe(IV), Ru(IV), Os(IV)
Chemistry 2070 - Fall 2015
Problem Set #10
Read Chapter 7, 8
Chap 7 problems: 4, 8, 24, draw 3D Lewis structures for the answers to questions 27, 28 (ignore XeF6),
29, 30, 47
Chap 8 problems: draw 3D Lewis structures for the answers to 18, 23-26 (predict
Chemistry 2070 - Fall 2015
Problem Set #2
Assigned problems are found at the end of each chapter in McQuarrie. Solutions
are available for even numbered problems in the Solution Manual. You will be
quizzed on this material the week of Sept 14th. Answers w
Chemistry 2070 - Fall 2015
Problem Set #4
Assigned problems are found at the end of each chapter in McQuarrie. Solutions
are available for even numbered problems in the Solution Manual. You will be
quizzed on this material the week of Sept 28th. Answers w
Chemistry 2070 - Fall 2015
Problem Set #5
Assigned problems are found at the end of each chapter in McQuarrie. Solutions
are available for even numbered problems in the Solution Manual. You will be
quizzed on this material the week of Oct 5th. Answers wil
Chemistry 2070 - Fall 2015
Problem Set #0
Assigned problems are found at the end of each chapter in McQuarrie. Solutions
are available for even numbered problems in the Solution Manual. Normally,
Quiz questions will be derived from the quiz problems below
Chemistry 2070 - Fall 2015
Problem Set #11
Because of Thanksgiving break, the quiz on this material will be during the last week of class, 11/30-12/4.
Read Chap 9
Chap 9 Problems: 5, 9, 12, 14, 23, 28-32, 39,40, 44, 49, 75 (just do hybridization), 78, 80
Problem Set #0 Answer Key
Practice Problems
2-2
(a) Sn (b) Au (c) Zr (d) Bi (e) Cu (f) Rb (g) Br (h) Ne (i) Sb (j) As
2-4
(a) Platinum (b) Tellurium (c) Lead (d) Tantalum (e) Barium (f) Titanium
(g) Rhe
Problem Set #8 Answer Key
Book Problems:
As described in class, the atomic orbitals are actually derived from linear
combinations of the allowed ml quantum numbers except for ml = 0. Therefore, you
can not clearly assign an atomic orbital to ml
Chemistry 2070 - Fall 2015
Problem Set #6
Assigned problems are found at the end of each chapter in McQuarrie. Solutions
are available for even numbered problems in the Solution Manual. You will be
quizzed on this material the week of Oct 19th. Answers wi
Chemistry 2070 - Fall 2015
Problem Set #9
Read Chapter 6
Chap 6 problems: 2, 25, 29, 30, 32, 33, 39, 40, 48, 51, 52, 69
1.
Electron Affinities (EA's) for the groups 13-18 elements are below (KJ/mol; consider these as H
for X + e -> X , where H < 0 is favo
1
Note: Lone pairs of electrons are only shown on central atomsnot terminal atoms (unless needed for clarity).
For example, in 7-4 there are 3 lone pairs on each Br in PBr3. Also, equivalent resonance structures are not
shown. Alternate representations
Chemistry 2070 - Fall 2015
Problem Set #3
Assigned problems are found at the end of each chapter in McQuarrie. Solutions
are available for even numbered problems in the Solution Manual. You will be
quizzed on this material the week of Sept 21st. Answers w
Chemistry 2070 - Fall 2015
Problem Set #8
You will be quizzed on this material the week of Nov 2nd. Answers will be posted on the blackboard
site on Friday Oct. 30th
Read Chapter 5
Chap 5 problems: 7 (there is something wrong with one of the orbitals acco
S
O
O
O
2+
O
S
O
O
O
note that a lone pair can
be "turned into" an A=O;
the stereochemical
influence is similar
Cl
O
3+
O
O
O
Cl
O
2+
O
O
O
Cl
O
1)
2)
O
O
Lone pairs exert greater stereochemical influence than bond pairs
(i.e., they act like they are "big
Mixtures of Substances
Homogeneous - uniform in composition
- uniform in properties
- separation of components is not simple
Heterogeneous - not uniform in composition
- not uniform in properties
- separation can be simple
Physical Property - measurement
3.1
reactants products. This is a chemical reaction
3.2
The individual atoms of various types are neither created nor destroyed in a chemical
reaction.
aNa+bH2OcNaOH
a=c ; 2b=c+2d
3.3
alkali metals (alkaline): form corrosive aqueous solutions that feel sl
10.1
Combination reaction: reactants combine to form a single product could be between 2
elements, 2 compounds, 1 element and 1 compound
Aluminum is resistant to extensive air oxidation, produces aluminum oxide, a layer that is
impervious to oxygen
Iron i
Chem 3890 Assignment 1
1. Ordinary derivatives
In[1]:=
X[x_] := B * Sin[n * Pi * x / l]
(a) Take the difference
In[2]:=
Out[2]=
deltaX = X[x2] - X[x1]
- B Sin
n x1
l
+ B Sin
n x2
l
(b) Use the derivative
In[3]:=
dX = (D[X[x], x] /. x x1) * (x2 - x1)
B n
Chem 3890 Assignment 5
1. Numerical solution of the SE for the HO at and near the ground-state energy.
(i) Schrdinger equation for HO with dimensionless coordinate at the ground state energy. Here is
related to x in Eq. 2.71 of Griffiths, and the Schrding