EE 2t3
Solohbns
Exon t
3stt
A
(o)
6cfw_tt
(d)
^(C,-r)
-t
e
cfw_ ttl
FG) = ! (t-,;t
= ,[eu(ct * rc u(c)
2e
-t
J
(4
i*?"d,"^rn ol
Th"
is
cfr6"rjf
Vo
=
lr.ro
in
atur s
uolt) =
atsune
)
=
4o
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EE213 Exam 2
April 18, 2003
Closed Book, Justify all work unless otherwise instructed.
Good Luck
NAME _____________________ __
Last four digits of SSN _______________ 1) The impulse response of a circuit is M!) = (exp(3t) - exp(2t))u(t).
If possible,
EE 213 Homework 9 Solutions
Chapter 16, Solution 24.
When the switch is position 1, v(0)=12, and iL(0) = 0. When the switch is in position 2, we have
the circuit as shown below.
s/4
+
100/s
v
1 100
=
sC
s
12 / s
48
,
I=
=2
s / 4 + 100 / s s + 400
v(t ) =
EE 213 Homework #6 Solutions
Chapter 8, Solution 58.
(a) Let i =inductor current, v = capacitor voltage i(0) =0, v(0) = 4
dv(0)
[v(0) + Ri (0)]
(4 + 0)
=
=
= 8 V/s
dt
RC
0.5
(b) For t 0 , the circuit is a source-free RLC parallel circuit.
=
1
1
=
= 1,
2 R
EE 213 Homework 5 Solutions
Chapter 15, Solution 50.
Take the Laplace transform of each term.
[s
2
V(s) s v(0) v (0)] + 2 [ s V(s) v(0)] + 10 V(s) =
3s
s +4
2
3s
s +4
3
3s
s + 7s
(s 2 + 2s + 10) V(s) = s + 2
=2
s +4 s +4
3
s + 7s
As + B
Cs + D
V(s) = 2
=2
EE 213 Homework 4 Solutions
Chapter 15, Solution 25.
5s ( s + 1)
5(1 + 1/ s )
= lim
=5
s (1 + 2 / s )(1 + 3 / s )
( s + 2)( s + 3)
5s ( s + 1)
f () = lim sF ( s ) = lim
=0
s 0
s 0 ( s + 2)( s + 3)
(a)
f (0) = lim sF ( s ) = lim
s
(b) F ( s ) =
s
5( s +
EE 213 Homework #3 Solutions
Chapter 15, Solution 10.
(a)
By taking the derivative in the time domain,
g( t ) = 8e-4t cos(2 t ) 4 e-4t sin( 2 t )
Using Table 15.2, we get,
G(s) = 8[(s+4)/(s+4)2+4)] 4[2/(s+4)2+4)]
= (8s40)/[ (s+4)2+4]
(b)
By applying the t
EE 213 Homework #2 Solutions
Chapter 10, Solution 19.
We have a supernode as shown in the circuit below.
j2
V2
V1
4
V3
+
2
Vo
-j4
0.2 Vo
Notice that
Vo = V1 .
At the supernode,
V3 V2 V2 V1 V1 V3
=
+
+
4
- j4 2
j2
0 = (2 j2) V1 + (1 + j) V2 + (-1 + j2) V
E E 2 t 3 Ex"n 2 - ' S " l . * , ; ^ s
,t - 3/s
lC
(a't
elvival2^!
S'donain
t -r?lrz
U .kl
t.
2
5
, to-4 /,
v.-(-3)
=T?T=o
T
Sp";n3o1
t4'2!o? voG)=fi.+l- - L -"/.
7 A+4
,(i-+.;*')u(rr
uo( t,
TL,;g < aa b t d .^< b J i ns?r.*;on
C u S l 1 5h ' ; c - / , o
EE213 Circuit Theory II
Midterm 1 F09
EE213: Basic Circuit Theory II
Midterm 1
There are 12 question with a total score of 75p. You may give answers in degrees or radians, as you prefer.
Problem 1
Transform the following sinusoids to phasors
1. (5p) 3 cos