SOLUTIONS HWSeI. BCZOO/
[ .2. i (a) Using the same coordinate system assumed in Eq. 422, we solve for y = h:
h=y0 +Vo sinot 22
which yields h = 51.8 m foryo = 0, v0 = 42.0 m/s, 60 = 60.0 and 2 = 5.50 s.
(b) The horizontal motion is steady, so vx = v0x
Exam 1, 29 Oct 2015 Initials; .
Problem 1: [10 pts]
You kick a small rock lying on the ground and it takes off on a projectile path, just
clearing a fence that is 15.0 m high, and lands on the ground on the other side. The
flight time to the fence is 0.65
WWWWMWWAWW WWM WWWWWW W WW, 1
, This is a completely inelastic collision, followed by projectile motion. In the
collision, we use momentum conservation.
slioes : logether :> (3'2 kg) (30 III/S) = (52 kg)?
Therefore, \7 = 1.8 m/ 5 toward the right as the
HW Set 3 (due 10-04-12)
BC 2001 Mechanics
1. (Do in class) The figure shows 2 horizontal forces on a block that is on a frictionless floor. 3 N 5 N
Assume that a third horizontal force F3 also acts on the block. What are the magnitude and
direction of F3
LEARN For a general upward acceleration a, the net work done is
would be v
Fd Fg d
m( g a)d mgd
mv 2 / 2 by the work-kinetic energy theorem, the speed of the astronaut
2ad , which is independent of the mass o
Exp: Free Fall Acceleration
February 16, 2016
To calculate the measured value for g, the acceleration due to gravity.
Learn how to use a ticker timer.
The equipment and materials that are used.
Exp: Introduction to Measurements:
Mass Density of CD
PHY 2001 ETRA 
February 4, 2016
Learn the definition of mass density and its formula = V
(m stands for mass
while V stands for the volume of the object)