Solution to Problem 39
Congratulations to this week's winners
Ray Kremer and Paul Leisher
Correct solutions were also received from Nathan Pauli, Bradley alumnus Kevin Bourrillion, Ben (no last name given), Ronan Cummins, Jan Siwanowicz, Philippe Fondanai
Solution to Problem36
Congratulations to this week's winner
Mike Fitzpatrick
Correct solutions were also received from Ray Kremer, William Webb, Greg Falcon, and Jeff Dowin. Two partial and one incorrect solution were also received. Greg Falcon and Willia
Solution to Problem 35
Congratulations to this week's winner
Mike Fitzpatrick and Ray Kremer
Correct solutions were also received from Jeffrey Downin, Jan Siwanowicz and William V. Webb. The number of integers satifying the conditions is 2 d - 1 . One met
Solution to Problem 34
Congratulations to this week's winner
Mike Fitzpatrick and Ray Kremer
Correct solutions were also received from Jan Siwanowicz and Thomas Teo. Two solutions were received which distributed the information correctly, but required mor
Solution to Problem 33
Congratulations to this week's winners
Mike Fitzpatrick
Correct solutions were also received from Jan Siwanowicz and from George Kirkup. Two incorrect solutions were submitted. As two solvers pointed out, the condition on the non-co
Solution to Problem 32
Congratulations to this week's winners
Mike Fitzpatrick, Ryan Vaughan, and Tim Parks
Correct solutions were also received from Abhi Dattasharma, Andreas Low, Yang Lu, Murat Ozkan, Bill Rosenberg, BHActuary, and Sid. All solutions bu
Solution to Problem 31
Congratulations to this week's winner
Mike Fitzpatrick
Correct solutions were also received from Bradley student Ray Kremer, as well as Wayne Bosma (Bradley Chemisty Professor), Kyle McCormick, Jeremy Rostand, Brent Young, Chris Gre
Solution to Problem 30
Congratulations to this week's winner
Ray Kremer
A correct solution was also submitted by Mike Fitzpatrick The following is Ray's solution. Note that he did not assume that the King's and Queen's Roads (labeled KR and QR in the diag
Solution to Problem 29
Congratulations to this week's winners
Karrie Mazurkiewicz, Ray Kremer, and Mike Fitzpatrick
One incomplete answer was received. Four incorrect submissions were received. [IMAGE] This problem can be solved as a minimization problem
Solution to Problem 28
There were no correct solutions received this week. The problem will remain open until the end of the semester. [IMAGE] Perhaps this picture, courtesy of Ray Kremer, will be useful. As the closet door swings open and shut, it traces
Solution to Problem 27
Congratulations to this week's winners
Karrie Mazurkiewicz, Kerrie Kerr, Ray Kremer, Steve Noto
Correct solutions were also received from Philip Tucker, Jon Stuff, Jrmy Rostand, Kevin Bourrillion (alumnus), and Erik Lamb (Maroa-Fors
Solution to Problem 26
Congratulations to this week's winner
Mike Fitzpatrick
Correct solutions were also received from Jim Otermat, Karrie Mazurkiewicz, Kerrie Kerr, Ray Kremer, Yan Fridman, and Erik Lamb (of Maroa-Forsyth High School). Three incorrect o
Solution to Problem 25
Congratulations to this week's winner
Ray Kremer
A correct solution was also received from Kevin Bourrillion. One incorrect submission was received. Let 2n + 1 = z 2 . Note that z must be odd. Simple algebra gives z 2 /2 + 1/2 = n +
Solution to Problem 23
Congratulations to this week's winner
Kevin Bourrillion
A correct solution was also received from Yan Fridman. One can solve the problem as a straightforward minimization problem in differential calculus. But Kevin Bourrillion's spa
Solution to Problem 22
Congratulations to this week's winners
Ray Kremer and Mike Fitzpatrick
A correct solution was also received from Yan Fridman, a partial solution was received from Kim Koin. The area of the rectangle as a function of a is [IMAGE] Cle
Solution to Problem 21
Congratulations to this week's winner
Steven Noto
Correct solutions were also received from Ray Kremer, Mike Fitzpatrick, and Yan Fridman. LABELED TRIANGLE Steven's solution was by far the most simple and elegant, using nothing but
Solution to Problem 20
Congratulations to this week's winners
Ray Kremer and Mike Fitzpatrick
The set of possible solutions make up an interval [IMAGE]
Solution to Problem 18
No correct solutions were received to this week's problem. The correct answer is that approximately 51.2% of the drawings will contain an adjacent pair of numbers. Details are available via electronic mail.
Solution to Problem 17
Congratulations to this week's winners
Ray Kremer and Mike Fitzpatrick
Correct solutions were also received from the "outside world". (They can play but they cannot win!) There is only one solution. Using X as the symbol for the num
Solution to Problem 16
Congratulations to this week's winners
Ray Kremer and Mike Fitzpatrick
A correct solution was also received from Dr. David Quigg. No correct solutions were received for the general problem. It will remain open until the end of the s
Solution to Problem 15
Congratulations to this week's winner
Ray Kremer
A correct solution was also received from Mike Fitzpatrick. There is a unique smallest solution up to permutations of the cube. See the figure below. The vertex number, V, is 21 and t
Solution to Problem 14
Congratulations to this week's winners
Mike Fitzpatrick, Ray Kremer
who will share this week's prize. Correct solutions were also received from Jim Otermat and Eric Grennan. Many incorrect submissions were received. Yes, the ant doe
Solution to Problem 13
Congratulations to this weeks winners: Joy Blue, Mike Fitzpatrick, Eric Grennan, Richard Heller, Cheng-Che Huang, Kim Koin, Scott O'Haver, Eric Schlange, Adam Rich. All of you can pick up your prize (25 cents - which is a quarter mo
Solution to Problem 11
Congratulations to this week's winner
Daniel Reeves
There were three other solutions submitted. Correct solutions were also received from Kevin Bourrillion and Jeff Decker. Answer: 1/3, 1/5, 1 a) There are two events: The selection
Solution to Problem 10
Congratulations to this week's winner
Daniel Reeves
There were two other correct solutions received, from Mike Fitzpatrick and from a Bradley mathematics professor and runner extraordinaire. You are trying to find a number N for whi