Chapter 16Human Ancestry
Primate Characteristics: Arboreal
Mobile limbs
Prehensile hands
Flattened face
Binocular vision
Complex brain
One birth at time
Mobile Limbs
Hands5 digits
Flat nails
Opposable thumb
Capable of grasping
Binocular Vision
Short

13-6
Using the steps outlined in the chapter:
Step 1: HO: Distribution of the number of cardiac patients per day is Poisson, with mean = 8. HA:
Distribution is not Poisson with mean = 8
Step 2: = 0.01
Step 3: After collapsing, we have 8 categories. Theref

14-2
a.
There appears to be a positive relatively strong correlation between the 2 variables.
b.
The correlation between the variables is positive 0.89.
14-10 a.
Although parts of the graph appear linear overall the graph seems to be more curvilinear.
b.

15-2
a.
b.
For every 1 unit increase in x1, y will increase by 4.14 assuming x2 is held constant.
For every one unit increase in x2, y will increase by 8.72 assuming x1 is held constant.
y=12.67 + 4.14(4) + 8.72(9)
y= 107.71
15-6
Regressio
n Analysis
Regr

14-34
a.
y = 200+150x
y=200+150(48)
y=7400
b. 7400(2.1199)(1.26)
74002.67
74002.67(0.237)
74000.633
Lower value = 7399.37, Upper value = 7400.633
c. 7400(2.1199)(1.26)
74002.74
Lower value = 7397.26, Upper value = 7402.74
d. The interval estimate for part

14-18 a.
The least squares slope coefficient is manually computed using:
The interim calculations are:
Then we substitute into the equation as follows:
= = 8.33
The intercept is computed using:
Then we get:
=
The regression equation is:
b. The sum of squa

18.1
Both Deming and Juran emphasized that quality was the key component to business
competitiveness and that the best way to improve quality came from improving the processes and
systems that produce products and deliver services. There are, however, som

12-32
a.
Source
Factor A
Factor B
AB Interaction
Error
Total
SS
162.79
84.36
262.31
789.28
1298.74
df
4
3
12
65
84
MS
40.6975
28.12
21.859
12.14
F-ratio
3.35
2.32
1.8
b.
H0: Factors A & B do not interact to affect the mean response
HA: Factors A & B do in

12-24
a. H0: : b1 = b2 = b3=b4 ; HA: at least one block mean is different
Since 23.72 > 9.27 we reject the null at conclude that at least one of the block means was
different from the others. This means that the blocking was effective.
b. H0: 1 = 2; HA: a

11.6
a.
The confidence interval estimate for the population variance, 2 is computed using Equation 11-2 shown
below:
For a 90% confidence interval we find the following values for and with n-1 = 22-1 = 21 degrees of
freedom:
= 11.5913 and = 32.6706
The co

9-26
H0: = 0.40 n = 64
= 0.01
p = 0.42
HA: 0.40
zcv = 2.5758
zstat = = = 0.327
Since 0.327 < 2.5758 do not reject the null. There is not sufficient evidence that the population
proportion is different from 0.40.
9-28
H0: 0.45 n = 30
p = 0.55
= 0.025
HA:

9-6
a.
b.
c.
d.
9-8
H0: 45
= 0.02, n = 80, = 9, x = 47.1
HA: > 45
zcv = 2.055 So if the z statistic is greater than 2.055 we reject the null hypothesis,
otherwise do not reject.
zstat = = 2.087
p 0.5 0.4815 0.0185
Since 2.087 > 2.055 and 0.0185 < 0.02 we

8.6
a. e = 2.6810 = 11.66
b. e = 2.5758 = 1.788
c. e = (2.3363)(2.356) = 5.504
8.7
n = 10; x = 3; s = 2.261
a. 3 (1.8331) = 3 1.311
1.6894.311
b. 3 2.2622 = 3 1.617
1.383 4.617
8.8
n = 20; x = 3.13; s2 = 1.45; s = 1.204
a. t = 2.8609; 3.13 2.8609 = 3.13 0