103
10
Agsmswem H SOLUTmNS
restart;
endloop 2: 1000:m == 0:
for m from 1 to 10000 do
N == m : ctr == 0 :
for i from 1 to endlaop do:
N
imeod2=0thenN== elseN=r 3'N+ 1 :end if:
2
ctr == ctr + l :
ifN= 1 then 1' == endloop; end if;
end do:
C[m] == ct
Math 026L.04 Spring 2002
Test #1 Solutions
1.
(a)
3
3
(b)
2
1
(c)
1 + x2
2.
Let = tan1 x. Then tan = x. Dierentiating both sides with respect to x gives
d
tan = dx x, or
1 d
= 1.
cos2 dx
Hence,
2
1
d
1
2
2
1
= cos = cos (tan x) =
=
2
dx
1 + x2
1+x
d
dx
Math 026L.04 Spring 2002
Test #4 Solutions
1.
(a) The possible values for X are: 0, 1, or 2.
(b) With probability 2/6, the player rolls 1 or 6. If that happens then with probability 1/4,
the player gets 0 heads (TT), with probability 1/4 the player gets 2
Math 026L.04 Spring 2002
Test #2 Solutions
1.
(a) y(x) = ln(2 + x) ln 2
(b) y(x) = tan(tan x)
2.
1
(a) S(t) = 150 e 50 t so that S(20) = 100.55 kg.
(b) After a very long time the concentration is 0 kg/L. This is not a surprise because we would
expect the