8.4
14. Solve by the Substitution Method
xy=4;
x 2+ y 2 =8
4
xy=4 x= y
4
y
Insert
for x and solve for y:
x 2+ y 2 =8
42 2
16
+ y =8 2 + y2 =8
y
y
Multiply all sides with
4
16+ y =8 y
y2 :
2
Re-write as quadratic equation, subtract
4
8y
2
2
y 8 y +16=0
Fa
Exercise 8.2
8:
The system of equations:
x y 3z 8
3 x y 2 z 2
2x 4 y z 0
The equations in matrix form
1 1 3 x 8
3 1 2 y 2
2 4 1 z 0
The augmented matrix
1 1 3 8
3 1 2 2
2 4 1 0
Convert to row-echelon form
Add
3
times the first row to the sec
Task 1
17
1 lightyear is the equivalent of about 9.5* 10 cm
1light year
17
9.510 cm
The equation is
=
( 2100 )( 1 light year
)
1012 = 1.3 trillion
17
9.510 cm = 1.3*
lightyears
Task 2
Verhulst
Task 3
f t
c
1 ae bt
In order to find
f 0
, we have to replac
Logistic Functions Set
Module 6
Hollie Kepic
12/20/2015
Math 140
Task 1
17
1 lightyear is the equivalent of about 9.5* 10 cm
1light year
17
9.510 cm
The equation is
=
( 2100 )( 1 light year
)
1012 = 1.3 trillion
17
9.510 cm = 1.3*
lightyears
Task 2
Verhul
EXERCISE SETS
Hollie Kepic
MATH 140
12/10/2015
Exercise Set 3.4 page 387
Problem 9
f ( x )=x 3 + x 24 x 4
a. List all rational zeros
1, -1, 2, -2, 4, -4
b. Use synthetic division to test possible rational zeros and find the actual zero
1
1
2
3
1
-4
6
2
-4
Carl Friedrich Gauss
Hollie Kepic
Math 140
15 January 2016
Carl Friedrich Gauss was a prodigious man who, by the age of ten, had far surpassed
those around him. When he was 14 years old, he met with one of the first of many significant
people in his life,
Gaussian Elimination
Exercise-Module 8
Math 140
1/13/2016
2016
*Please note: I downloaded a trial for mathtype 6.0 to see if I liked it any better than the normal
equation editor. That is why my equations and the like look different than other times. Spoi