MA1310
Module 6 Lab 6
1. A phone company has two different phone plans from which you can choose.
Plan A: $40 a month for unlimited calling
Plan B: $20 a month plus $0.10 a minute
Based on the information provided, solve the following problems:
a) What
MA1310
Module 5 Discussion
Jane, an expert in vectors, and Jill, a student with inaccurate knowledge of vectors,
made the following statements. Based on your understanding of vectors, identify the
statement(s) made by Jane and the statement(s) made by Jil
MA1310
Module 5 Lab
2. Let u = 8i 6j and v = 5i + 8j. Find the vector u + v.
u = 8i 6j
v = -5i + 8j
Answer: u + v = 3i + 2j
3. Find the unit vector that has the same direction as vector v = 12j.
Answer: - j
4. Let u = 4i + 2j and v = 5i 3j. Find the vecto
MA3110
Evans Aquino
Module 2 Exercise 1
1. The data in the table provided does not represent a probability distribution, because it
doesnt add up to 1
2. N= 100 P=1/5= .2
a. Mean= 100(.2)= 20
b. Standard Deviation= 20 ( 1.2 ) = 16 = 4
3. N=100 P= .24
a. M
MA3110
Evans Aquino
Module 4 Exercise 1
Task 1:
The first obvious thing is that the sample sizes are different making the result inaccurate of the
bat. Also since the student surveyed her friends it doesnt seem random enough.
All three approaches will giv
MA3110
Evans Aquino
Exercise 2.2
Task 1
Series 1
ABC
Series 1
Fox
CBS
0
1
2
3
4
5
6
7
8
9
10
Series 1
5
9
6
CBS
Fox
ABC
MA3110
Evans Aquino
To me the pie chart is the best graphical representation of data, because it gives a better
idea of how much each n
MA1310: Module 4 Applications of Trigonometry
(r,) and (-r , +180) are the same point because adding 180 takes you to the
exact opposite side of the unit circle , but the MINUS r brings you back to where
you started think of 180 as taking you halfway arou
MA1310: Module 6 Binomial Theorem, Counting Principle, Permutation, and
Combination
The binomial coefficient is the number of ways of picking unordered outcomes
from possibilities, also known as a combination or combinatorial number. The
symbols and are u
MA1310: Module 5 Vectors and Conic Sections
Directed Line Segment: A directed line segment is a portion of a line that has both
a magnitude and direction. Magnitude: A magnitude is the length of a line
segment or vector. Vector: A vector is a type of math
MA1310: Module 5 Vectors and Conic Sections
An ellipse is defined by two points, each called a focus. If you take any point on
the ellipse, the sum of the distances to the focus points is constant.
The center is (0,0) and the major axis is vertical, so st
MA1310: Module 3 Trigonometric Functions
A=1
B=1
C = /2
D=2
E = 1.57
F = i. y = -cot(x)
ii. y = tan(x)
iii. y = -tan(x)
iv. y = cot(x)
Find the exact value?
A = 60
B = 150
C = -45
D = 4.1888
E = .28 or 7/25
To two decimal places?
28.03 degrees
Find the an
MA1310: Module 4 Applications of Trigonometry
B = 35
b = 9.262
c = 16.03
You will get 2 triangles
sin x = (7/5)sin 70 = 1.316, which is impossible. With angle A = 70 opposite the
side of length 7, the Law of Sines gives
sin x = (5/7)sin 70, which is a lot
MA1310: Module 2 Exponential and Logarithmic Functions
Solve the following exponential equation by expressing each side as a power of
the same base and then equating exponents:
6x = 216? 6x=216x=3.2
Solve the following exponential equation:
ex = 22.8 Expr
MA1310: Module 2 Exponential and Logarithmic Functions
Answer the following questions to complete this exercise:
What is an exponential function? It is a constant raised to a power of.
What is a natural exponential function? The function A, is the number
MA1310: Module Trigonometric Functions
a. sin 60 = sqr(3)/2
b. the tan of 45 is 1
c. = cot(pi/3) = 1/tan(pi/3) = 1/(1/root(3) = root(3)
2. Quadrant 0 lies in? the 4th quadrant
3. Find exact quadrant 0 in quadrant 4? Opposite side = sqrt[5^2-4^2] = sqrt[25
MA1310: Module 1 Sequences Exercise 1.1 Sequences and Notations
Answer the following questions to complete this exercise:
Describe an arithmetic sequence in two sentences.
In an Arithmetic Sequence the difference between one term and the next is a
constan