Steve Becker
X
February 8, 2015
P(X)
1
2
3
4
EG381 Module 2 Exercise
0.22
0.16
0.21
0.16
All probabilities are between 0 and 1. The Sum = 0.75 So yes this is a not probability distribution
because the sum of the probabilities is 0.75 Mean 0.1875 Standard
Steve Becker
X
July 5, 2015
P(X)
1
2
3
4
EG381 Module 2 Exercise
0.22
0.16
0.21
0.16
The probabilities are not between 0 and 1. The Sum = 0.75 So this is not a probability
distribution because the sum of the probabilities is 0.75 Mean 0.1875 Standard devi
Steve Becker
EG381: Week 3 exercise 3.1
4/10/2013
1.) The team numbers are random and dont mean anything unless the team gives them a name to
the jersey. To count them would not be wise.
2.) Mean:
714+751+664 +789+818+779+698+ 836+753+834+ 693+802 =9131/1
Steve Becker
X
July 5, 2015
P(X)
1
2
3
4
EG381 Module 2 Exercise
0.22
0.16
0.21
0.16
All probabilities are between 0 and 1. The Sum = 0.75 So yes this is a not probability distribution
because the sum of the probabilities is 0.75 Mean 0.1875 Standard devi
Steve Becker
EG381 week1 assignment
March 24, 2013
1. The average (mean) atomic weight of all elements in the periodic table is
134.355 unified atomic mass units.
Refer to the above data and determine whether the given value is a statistic or a
parameter.
For what needs to be protected in company servers which is most of anything that touches the internet
and or if a persons has access to those servers information. My companys firewall has some security
issues with it failing which is in the process of bei
Quiz Questions
Which of the following conditions legally allow workplace video surveillance monitoring?
A: Employees are given notice
Which of the following amendments reads as no soldier shallin time be quarterd in any house
without consent
A: Third amen