ECE264A CMOS Analog Integrated Circuit and Systems I
March 3, 2009
March 6, 2007
Ian Galton
EBU1 5606
Homework Assignment 6
Due: End of of class, Tuesday, March 10, 2009
Due beginningclass, Tuesday, March 13, 2007
Problems:
1. Consider the feedback ampli
ECE 264A: Analog Integrated Circuits and Systems I
February 12, 2009
Ian Galton
EBU1 5606
Homework Assignment 4
Due: Beginning of Class, Thursday, February 19, 2009
1. Download and solve the ECE264A Midterm Exam 1.
2. Although most people got the correct
Introduction
Midterm on Tuesday
Bring your OWN one page cheat sheet
1
c Gudem & Larson
Maximum Bilateral Power Gain
The maximum overall gain would be obtained when input and output are matched
simultaneously (also referred to as simultaneous conjugate m
RF Circuits Research Group
1
c Gudem & Larson
RF Circuits Research Group
Transition Frequency: Ft
A good measure of AC performance of the BJT can be captured through fT:
fT is defined as the frequency at which current gain of the transistor goes to 1.
B
1) What is the output noise expression of the following circuit? (assume matching)
VBP
VDD
MP
RF
RS
MN
VIN
2) What is the output noise expression of the following circuit? What is the requirement for
cancelling the thermal noise of the Common Gate stage?
Announcements
Schedule
Midterm 2 3/11
Final homework due Monday.
Final Project 3/18
Today: Mixer Noise and Linearity Analysis
Techniques
Final Lecture 3/13
N-path Filtering and Harmonic RejecHon Mixing for
So
Announcements
Midterm?
Schedule
Midterm 1 2/11, Midterm 2 3/11
Class cancelled on 2/27
Homework 3 assigned shortly
Final project assigned next week (form
groups)
EE265B: Communica0on Circuits II
Device Modeli
Announcements
Schedule
Class cancelled on 2/27
Midterm 2 3/11
Final project assigned.
Modied Deriva=ve Superposi=on
Require dierent
reactances at source.
Secondary (WI)
transistor is more
strongly degenerated.
ECE264A Winter Solutions to Homework Assignment 6
ECE264A Winter 2009: 2007 Problem Set 6 Solutions
Colin Weltin-Wu
Problem 1
To nd the value of C that makes the amplier ring, we can do a sweep over C values and pick
the value which causes maximal ringing
ECE264A Winter 2009: Solutions to Homework Assignment 1
ECE264A Winter 2007 Problem Set 1 Solutions
Colin Weltin-Wu
Problem 1
The circuit for the problem is as follows, where we assume VB is connected to a zero impedance
source:
Vdd
VB
RB
vout
RS
vin
Outp
ECE264A Winter 2009: Solutions to Homework Assignment 4
4. This is not a computationally intensive problem because we have no resistance at the
gate. Without gate resistance, there is no Miller eect. We have four capacitors, Cgs ,
Cgd , Csb and Cdb . Thes
ECE264A Winter Solutions to Homework Solutions
ECE264A Winter 2009:2007 Problem Set 3 Assignment 3
Colin Weltin-Wu
Problem 1
The assumption of dominant poles means we can use the zero value time constant theorem to
give us a bandwidth approximation. We ne
Introduction
RF Circuits Research Group
Loose ends. Who didnt sign the NDA?
Xie
Jin
No guest lecture next week.
Midterm in 2 weeks (from today)
1
c Gudem & Larson
RF Circuits Research Group
Homework?
2
c Gudem & Larson
RF Circuits Research Group
Home
RF Circuits Research Group
Homework?
1
c Gudem & Larson
RF Circuits Research Group
EE265B: Communication Circuits II
Review of Smith Charts (2 lecture)
Device Modeling (2 lectures)
BJT (RF Device Model, RF Noise Model)
MOS (RF D i M d l RF N i M d l)
De
Introduction
RF Circuits Research Group
Loose ends. Who didnt sign the NDA?
Bilgehan
Mohammad
Xie
Jin
Ting
Homework Assigned!
g
1
c Gudem & Larson
Last time.
RF Circuits Research Group
A final word on device modeling.
See the Enz paper (TSSC 00)
2
c G
Issues
EVM Do for extra credit Requires Envelope
EVM Doforextracredit.RequiresEnvelope
followinganalysis.SeepostedSpectre RF
tutorial.
tutorial
HW?
Singlevs DoubleSidedNoise
Single vs Double Sided Noise
N o 4kTR one sided noise
one-sided
N t 2kTR two-si
ReciprocalMixing
Reciprocal Mixing
BlockerLevels
Blocker Levels
Example
Example
SimplePhaseNoiseModel
Simple Phase Noise Model
Consider an oscillator with some noise
Consideranoscillatorwithsomenoise
Vlo t 1 A t cos lo t t
Whenthatnoiseissmall,
Vlo t
MethodsforLinearityImprovement
Methods for Linearity Improvement
AnalogLinearization
Linearizationthroughpowerconsumption
Optimumdevicebiasing
Linearizationthroughfeedback(degeneration)
Li
i ti th
h f db k (d
ti )
Long/shortchanneldevices
BJT
Lowfrequen
No OH today
Still owe you an EVM explanation
1
c Gudem & Larson
Heterodyne Mixer Noise Analysis: Total Noise
Noise Analysis of Heterodyne Mixer (total noise):
v
2
noise MIX
I DC , mix
I DC , mix
IF 4kTRL 1 4. .
.RL 4. .
.RL
ALO
VGSQ VT 0
V
GSQ
VT 0
Last Time
Bandgap Voltage and Current Source
PTAT Voltage and Current Source
CTAT Voltage and Current Source
1
c Gudem & Larson
Other Reference Circuits
There are literally hundreds of circuits for that are used to generate bandgap currents,
bandgap vo
Midterms returned today
j
g
y
Project assigned today
1
c Gudem & Larson
Silly Question #3
Data
GMIX 5dB
I
GMIX 0dB
GIFVGA 10dB
GRFVGA 20dB
LO1
GPA 20dB
GIFVGA 40dB
D/A
ALOCos LOt
GPA 0dB
GRFVGA 40dB
200MHz
IF-VGA
RF-VGA
D
Data
ALOSinLOt
Q
D/A
2GHz
PA
RF Circuits Research Group
NDAs ?
Matt Office Hours 6-8 Tuesday
1
c Gudem & Larson
Last Time
RF Circuits Research Group
Completed discussion of BJTs
Discussed large signal and small signal
behavior of MOSFETs.
1
W
Rgeltd R *
3
L
Rgeltd
1
1
12 .
V
RF Circuits Research Group
Welcome Back
Final from ECE265A is provided
TA: Matt Deibel
Grading: Homeworks (2), Midterms (2),
Design Project
Project.
1
c Gudem & Larson
RF Circuits Research Group
Outline
Understand devices with a little more detail
Fo
ECE 264A: Analog Integrated Circuits and Systems I
January 27, 2009
Ian Galton
EBU1 5606
Homework Assignment 3
Due: Beginning of Class, Tuesday, February 3, 2009
Problems 1-4 are from a previous ECE264a midterm exam. They all relate to the following ampli
ECE264A Winter 2009:2007 Problem Set 2Assignment 2
ECE264A Winter Solutions to Homework Solutions
Colin Weltin-Wu
Problem 1
(a) The dierential mode gain can be read o the circuit without computation. Due to the
200A current source, the current through M1
1
Impedance matching
Impedance matching is a general problem of taking power from a source and delivering as much as possible to the load. The power delivered from a source depends on the input impedance of the network and the source impedance.
Pdelivered